DON'T MISS 3 PRACTICE PROBLEMS AT THE END. PLEASE SHARE THIS 🙌 AND KINDLY PROMOTE THE CHANNEL. 20TH VIDEO OF RESOLVED SERIES FOCUSSES ON THE CONCEPT OF "ELECTROSTATIC SHIELDING" AND HOW TO LOGICALLY TACKLE JEE ADVANCED LEVEL QUESTIONS ON THIS CONCEPT. HERE'S THE LINK TO PROBLEM STATEMENT OF USED IN THIS VIDEO👇 drive.google.com/file/d/12JXVupK3lr7lKxwYGTGq0UQLMgFncNxB/view?usp=drivesdk
Sir I am watching this video today, but 2 weeks before in my part test, I saw the same exact PAASAGE hw ques, I was able to solve in the test... Feeling much happy :)
Thanks sir for explaining in such a nice way ...I always had doubt about this concept and used to do wrong in my tests now kudos to you I have got the concept 🤘🏼😎😃
This is a mind blowing concept sir !! Some problems related to this concept has been bugging me a long time Now I am confident to solve any problem in this concept😃
thanks a lot sir jee!!!!!!!! i had dbt in this concept before seeing your vedio i did a problem wrong in allen aits based on this concept ; now the concept is crystal clear🤩🤩🥺🥺
Answer to the problem at 17:25 Q11) B , Q12) C , Q13) B (I am not exactly sure why).. I think because as we approach near Q inside cavity, potential would go toward infinity..hence positive...but not sure why positive for other points 18:15 Q9) A , B , C 19:00 Q3) B (and it doesn't matter where the point charge at A is placed..answer will still remain the same as the whole spherical shell can be considered a cavity of radius r and so it won't contribute any potential term) Are these answers correct?
So ok, when we are near the surface of the cavity it behaves it seems like we are very close to -ve charge ..so potential could be negative...BUT BUT BUT my approach is this , we know that the potential of the conductor is zero and the electric field inside the cavity is towards the the surface originating from the +q ending on the surface , so we could say electric field lines are starting from the q and ending on surface , and we know that in the direction of electric field potential decreases....so it decreased to zero it means it was +ve before
For the distribution of charges on the outer surface of the sphere (of the video problem) - Using Method of Images for a charge in front of a conducting sphere. Q2= -(R/a) Q1 substituting a=2R we get q=-Q/2 and of course the entire charge will be distributed on the surface as E in a conductor=0 . Nice explanation sir! 👏👏
16:15 sir here, can we say that since the outside charge will not affect the potential , the Vc1 is simply the potential in case 2 that you created with only the cavity charges.
Can you post a time stamp of each question against your answer for me to easily check or navigate ? You can also check the comments I have liked for correct answers below
Thank you sir for yet another amazing concept explanation. Sir at 13:42 why we didn't consider potential due to induced charge at cavity surface and the charge at c1
Sir let's say we have a point rightside to C2 inside the cavity.. Can we find the potential there? To find the potential there, can i use the same superposition logic, that is forgetting the cavity first and finding potential due to the outside charges and then due to the cavity.. So should the answer be the same as what we got for C1 @ 15:01 ?
HELLO SIR,which are the potential candidate physics problem(situations) which can be asked in future jee exams??like the one you made a video on surface tension appeared this year
@@PHYSICSSIRJEE no sir it is solution of last three question (which you provided us for practice purpose )from my side 😊 ... btw thanks for this lecture I have too much confusion in this part
Sir just a small clarification needed from your side: In the diagram it is misleading to see that the surfaces of cavity and spherical conductor coincide ,should it not be mentioned in the ques that they are slightly apart from each other or the charges do not interact there?
Sir I got answers to practice questions please check sir Practice problem-1 11:B 12:C 13B Practice problem-2 9:ABC Practice problem-3 3:C Thanks sir for helping me to learn quantity things 🥰🥰
ans of 3rd will be 3q solve this by electrostatic shielding due to b and outer charges field inside is zero so they contribute same potential at all points inside shell so potential of the shell is same as potential due to b and outer induced charges at centre and inner charges + cabity dont contribute any field and potential outside the shell so their contribution is zero hence k2q/2r +k(q final /r)=0 hence q final=-q initally outer charge was 2q now -q so 3q charge flown
Due to inside charges there is no electric field outside the conductor. So no work done will be performed to bring unit positive charge from infinity to the shell.. so no potential will be contributed by the inner charges . But here you have mentioned them. Why it so?Plz clarify my doubts Thank you
SIR PLEASE UPLOAD A VIDEO ON CHARGE PARTICLE PRESENT INSIDE A SOLID METALLIC CONDUCTOR WITHOUT CAVITY.IN THAT CASE WHY POTENCIAL AT ALL POINT INSIDE CONDUCTOR IS NOT SAME.
Sir in the practice problem of shm build - 20 do what would be the resistive force here we have to consider as viscosity is to be neglected then what would be the resistive force ? Buoyancy? Please give an hint sir .
@@swetankpandey999 where will the buoyant force work as there is no water between walls and plate and its thin on other side , its like a submarine which when touches floor can never come up as no water beneath so no buoyant force then . But tho I have considered it before asking this question but I'm a bit confused .
@@swetankpandey999 no actually if it goes bottom there would be no water between surface of submarine and ocean floor so no buoyant force so it can't come up as it can't oppose pressure
And here also the wall and plate surface will not separate and yes there would be forward retardation tho but the thing its a thing plate so no buoyant force at front i guess.... But I have considered it x tho . that's why I am asking sir 😀
ans is B. Assume that the final charge is 2q-q’. Then potential due to this charge and B is supposed to be same. So, 2q-q’/r= 2q/2r… so q’=3q that is the migrated charge. I’m assuming youve understood how electrostatic shielding works and why charges INSIDE a cavity wont affect surface ones
@@subhashpatel5861 pot at surface is 0, and inside the cavity field lines are along the surface, that means potential must be decreasing, so Inside pot is +ve
Sir, won't we write the potential at C1 also due to the charge induced on the outside surface of cavity as it is neutral? and what would be the charge on the inner surface of the outer sphere?
@@PHYSICSSIRJEE Yes, sir I got it now, thank you. I have been thinking on this whole concept from last one hour. And sir, I asked a question yesterday about conservative field as a comment here only, but I think you deleted it for some reason...it has been bothering me for some time... can you explain why so that I am also satisfied... it's ok if you don't explain...just tell from where do I learn the concept that electric field inside a battery is non conservative or conservative and work done by it... I couldn't find any video on it too :(
@@vilakshangupta380 I don't delete any comments🙂 . At times , TH-cam algorithm holds some comments for Review .I don't know on what basis . Regarding non-conservative field inside battery , please read through this thread 👇 physics.stackexchange.com/questions/377411/why-is-the-electric-field-created-by-a-battery-non-conservative#:~:text=Because%20the%20work%20functions%20are,flowed%20against%20the%20electric%20force. You may alternatively refer to Sears Book recommended in telegram group or even I think Griffiths or Purcell discussed it.
sir manam elanti situations lo a on outer surface unnapudu ..in everys ituation cavity lenattu theekuni charge find cheyocha.. ante bayata spherni earth chesi in this kind of situations...inka cavity ni separate enduku chesam sir pls explain.. endkunate c1 is inside the cavity kada..
@@PHYSICSSIRJEE ok sir ty mee student air 222 cheppadu mee gurinchi alsonitin sir nundi chaduvuthunna .. just respond like this to me sir.. will feel more confident.. ty
sir if we wanted potential at a point outside the whole sphere will we take contributions from charges inside cavity?....becoz in this pronlem for potential inside cavity we took contributions form the charges outside the cavity too...
@@PHYSICSSIRJEE sir if the charge distribution on inner surface of cavity would be a non uniform one so then also potential due to induced + already present there would cancel ?
@@PHYSICSSIRJEE ok sir now I realised.....I SHOULD'VE MENTIONED THAT THE POSITION of charge q won't matter until they are inside the shell because when they are inside net field produced by them is....0 hence equipotential ......and hence Inside the shell the induced charge and the charge placed are non existent.....for outer world ........only the induced charge distribution on the inner side of the shell will change .....but the answer doesn't changes here I feel..... But yes we can not ignore it as it comes in the outer universe outside the shell than the answer would be affected by the location of that charge q...also
SIR ITS A HUMBLE REQUEST FROM STUDENTS SIDE PLEASE COME ON UNACADEMY PLUS OR START YOUR PERSONAL COURSE AND BLESS US WID YOUR TEACHING 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🥇🥇🥇🥇🥇🥇🥇🥇🥇🥇🥇🥇🥇 ALREADY FEELING THE REAL PHYSICS WITH NITIN SACHAN SIR
Maybe sir has his own aspirations of setting up something very big. So maybe that's why he isn't coming on plus. But as a plus member I also want sir to join unacademy.
DON'T MISS 3 PRACTICE PROBLEMS AT THE END.
PLEASE SHARE THIS 🙌 AND KINDLY PROMOTE THE CHANNEL.
20TH VIDEO OF RESOLVED SERIES FOCUSSES ON THE CONCEPT OF "ELECTROSTATIC SHIELDING" AND HOW TO LOGICALLY TACKLE JEE ADVANCED LEVEL QUESTIONS ON THIS CONCEPT.
HERE'S THE LINK TO PROBLEM STATEMENT OF USED IN THIS VIDEO👇
drive.google.com/file/d/12JXVupK3lr7lKxwYGTGq0UQLMgFncNxB/view?usp=drivesdk
Sir where can i find the answers to those practice problems ? Thanks a lot for the content
sir can you please tell the answers of the practice problems ?? didnt find them in your series..
i got B C B (11 12 13)
A C B
C
Theoretical Problems in conductor are probably the toughest in jee syllabus , Thank you for explaining so lucidly some really nice concepts
Very true 😫
Not for von neumann.
I would say, the most mind bending and counter intuitive, yet beautiful when you understand it
346 likes 0 dislikes, pure concept. LOVE YOU JANARDHAN SIR.😘😘😘
Perfect way to start a day !
Was searching for this type of questions for revision ｡◕‿◕｡
i hope we get more teachers like u who make the concepts crystal clear.
V nice video
Amazing q and concept
Amazing Video!
Sir I am watching this video today, but 2 weeks before in my part test, I saw the same exact PAASAGE hw ques, I was able to solve in the test...
Feeling much happy :)
Thanks sir for explaining in such a nice way ...I always had doubt about this concept and used to do wrong in my tests now kudos to you I have got the concept 🤘🏼😎😃
😎
Brilliant video
Helpful in revision
This is a mind blowing concept sir !!
Some problems related to this concept has been bugging me a long time
Now I am confident to solve any problem in this concept😃
thanks a lot sir jee!!!!!!!! i had dbt in this concept before seeing your vedio i did a problem wrong in allen aits based on this concept ; now the concept is crystal clear🤩🤩🥺🥺
Answer to the problem at
17:25 Q11) B , Q12) C , Q13) B (I am not exactly sure why).. I think because as we approach near Q inside cavity, potential would go toward infinity..hence positive...but not sure why positive for other points
18:15 Q9) A , B , C
19:00 Q3) B (and it doesn't matter where the point charge at A is placed..answer will still remain the same as the whole spherical shell can be considered a cavity of radius r and so it won't contribute any potential term)
Are these answers correct?
So ok, when we are near the surface of the cavity it behaves it seems like we are very close to -ve charge ..so potential could be negative...BUT BUT BUT
my approach is this , we know that the potential of the conductor is zero and the electric field inside the cavity is towards the the surface originating from the +q ending on the surface , so we could say electric field lines are starting from the q and ending on surface , and we know that in the direction of electric field potential decreases....so it decreased to zero it means it was +ve before
Thank you so much sir for providing such conceptual questions with a lucid explanation...
Definitely the most underrated channel
This is my fav topic :)
For the distribution of charges on the outer surface of the sphere (of the video problem) -
Using Method of Images for a charge in front of a conducting sphere.
Q2= -(R/a) Q1 substituting a=2R we get q=-Q/2 and of course the entire charge will be distributed on the surface as E in a conductor=0 .
Nice explanation sir! 👏👏
Finally understood this shielding concept :), thank you so much sir...
16:15 sir here, can we say that since the outside charge will not affect the potential , the Vc1 is simply the potential in case 2 that you created with only the cavity charges.
Yes u can
Thanks a ton really appreciate it one question in mcq of pathfinder had me confused but now you were there to c,ear it with an amazing explanation.
Sir I improved a lot after wathcing your content thanks a lot sir you are omega of my preparation
Wonderful Sir,all doubts have been cleared 👏
amazing ...
Thank you sir you have explained it so well that my misconception about this topics got clear.
Excellent
Lovely explanation
#jee advance 2023
Cleared my all doubts😊
janrdhan sir loved it ,sir is your health fine sir ,take care sir
Answer of hw question according to me.
11. A ( 17:26 )
12.C ( 17:26
13.C 17:26
second given problem
9. ABC 17:55
Pathfinder
3 . B 18:36
❤
Can you post a time stamp of each question against your answer for me to easily check or navigate ?
You can also check the comments I have liked for correct answers below
Added the time stamp sir, & you had not liked any answer so far,
thank you
Awesomely explained 😍
Thank you sir for yet another amazing concept explanation.
Sir at 13:42 why we didn't consider potential due to induced charge at cavity surface and the charge at c1
Thank you sirji☺❤
amazing sir jee😍
uff finally understood this..thank you soooooo much...
I am glad you did 🙂👍🏼
very helpful video sir🤩. Many misconceptions were cleared.
Got my concept cleared Sir . Thank you
Sir, please continue these series..
Thank you sir for this❤️
Amazing sir 🙂✨
Thanks sir !
Thanks ❤️
Sir it is just amazing
I think explain by Gaussian surface is much easier than potential difference inside a conductor is zero for prooving sigma inside is zero
Sir let's say we have a point rightside to C2 inside the cavity.. Can we find the potential there? To find the potential there, can i use the same superposition logic, that is forgetting the cavity first and finding potential due to the outside charges and then due to the cavity.. So should the answer be the same as what we got for C1 @ 15:01 ?
Yes, perfect 🙂👍
Thank you sir
HELLO SIR,which are the potential candidate physics problem(situations) which can be asked in future jee exams??like the one you made a video on surface tension appeared this year
1) 11- A 12-C 13-B [17:25]
2) ABC [17:59]
3) B [18:26]
Add the time stamp also on old videos, it will be easy. I will check and respond tomorrow 🙂👍🏼
@@PHYSICSSIRJEE no sir it is solution of last three question (which you provided us for practice purpose )from my side 😊 ... btw thanks for this lecture I have too much confusion in this part
@@ADITI_kri yes for that practice questions itself, just add a time stamp 🙂
PS: thank you for the appreciation 🙏
DONE SIR
Lovely explanation sir 🙂❤️🙂
sir please make a video on slinky (for Olympiad )
thankyou sir
most complex sh*t to understand. Thank you sir you made it very easy
Sir just a small clarification needed from your side: In the diagram it is misleading to see that the surfaces of cavity and spherical conductor coincide ,should it not be mentioned in the ques that they are slightly apart from each other or the charges do not interact there?
sir is the answer c only and charge on outer sphere is -q/2
Sir I got answers to practice questions please check sir
Practice problem-1
11:B
12:C
13B
Practice problem-2
9:ABC
Practice problem-3
3:C
Thanks sir for helping me to learn quantity things 🥰🥰
i think for last one D would be correct
ans of 3rd will be 3q
solve this by electrostatic shielding
due to b and outer charges field inside is zero so they contribute same potential at all points inside shell
so potential of the shell is same as potential due to b and outer induced charges at centre
and inner charges + cabity dont contribute any field and potential outside the shell so their contribution is zero
hence
k2q/2r +k(q final /r)=0
hence q final=-q
initally outer charge was 2q
now -q so 3q charge flown
Sir explain path finder properties of matter MCQ 6th question sir (equilibrium types)
Boom
practice problem
11 A
12 c
13 b
2 abc
3 b
Due to inside charges there is no electric field outside the conductor. So no work done will be performed to bring unit positive charge from infinity to the shell.. so no potential will be contributed by the inner charges . But here you have mentioned them. Why it so?Plz clarify my doubts
Thank you
SIR PLEASE UPLOAD A VIDEO ON CHARGE PARTICLE PRESENT INSIDE A SOLID METALLIC CONDUCTOR WITHOUT CAVITY.IN THAT CASE WHY POTENCIAL AT ALL POINT INSIDE CONDUCTOR IS NOT SAME.
Revised 31 jan
Baut acha padaya apne sir, tnks for this video. Sir, is the electric field at c¹ is 9kQ/R².
Are you also taking outside charges into consideration while calculating Electric field?
Sir in the practice problem of shm build - 20 do what would be the resistive force here we have to consider as viscosity is to be neglected then what would be the resistive force ? Buoyancy? Please give an hint sir .
@@swetankpandey999 where will the buoyant force work as there is no water between walls and plate and its thin on other side , its like a submarine which when touches floor can never come up as no water beneath so no buoyant force then . But tho I have considered it before asking this question but I'm a bit confused .
@@swetankpandey999 no actually if it goes bottom there would be no water between surface of submarine and ocean floor so no buoyant force so it can't come up as it can't oppose pressure
And here also the wall and plate surface will not separate and yes there would be forward retardation tho but the thing its a thing plate so no buoyant force at front i guess.... But I have considered it x tho . that's why I am asking sir 😀
@ 18:30 Sir is the solution to this problem available on your channel or youtube? I'm not able to solve it
ans is B. Assume that the final charge is 2q-q’. Then potential due to this charge and B is supposed to be same. So, 2q-q’/r= 2q/2r… so q’=3q that is the migrated charge. I’m assuming youve understood how electrostatic shielding works and why charges INSIDE a cavity wont affect surface ones
👌👍🏻
Practice problem 1
11-A,12-C,13-B
practice problem 2-ABC
practice problem 3- B
Got the same but can you pls brief q13 ? I didn't get it
@@subhashpatel5861 I did that a very long ago I don't even remember the question and see sirs further videos solution is there already on channel
@@subhashpatel5861 pot at surface is 0, and inside the cavity field lines are along the surface, that means potential must be decreasing, so Inside pot is +ve
11 should be B
🤩🙃
Writing comment hope I will get iit
Sir, won't we write the potential at C1 also due to the charge induced on the outside surface of cavity as it is neutral? and what would be the charge on the inner surface of the outer sphere?
The entire red thing is solid , it's a spherical hole in a solid red sphere. There is no outer sphere
@@PHYSICSSIRJEE Yes, sir I got it now, thank you. I have been thinking on this whole concept from last one hour. And sir, I asked a question yesterday about conservative field as a comment here only, but I think you deleted it for some reason...it has been bothering me for some time... can you explain why so that I am also satisfied... it's ok if you don't explain...just tell from where do I learn the concept that electric field inside a battery is non conservative or conservative and work done by it... I couldn't find any video on it too :(
@@vilakshangupta380 I don't delete any comments🙂 . At times , TH-cam algorithm holds some comments for Review .I don't know on what basis .
Regarding non-conservative field inside battery , please read through this thread 👇
physics.stackexchange.com/questions/377411/why-is-the-electric-field-created-by-a-battery-non-conservative#:~:text=Because%20the%20work%20functions%20are,flowed%20against%20the%20electric%20force.
You may alternatively refer to Sears Book recommended in telegram group or even I think Griffiths or Purcell discussed it.
@@PHYSICSSIRJEE Thanks a lot sir! Also check my answers to the 3 problems in the end if they are correct :)
18:39 iska c
sir manam elanti situations lo a on outer surface unnapudu ..in everys ituation cavity lenattu theekuni charge find cheyocha.. ante bayata spherni earth chesi in this kind of situations...inka cavity ni separate enduku chesam sir pls explain.. endkunate c1 is inside the cavity kada..
Yes , cheyochu 👍 🙂. That's what is explained in concept-1 at 2:00
@@PHYSICSSIRJEE ok sir ty mee student air 222 cheppadu mee gurinchi alsonitin sir nundi chaduvuthunna .. just respond like this to me sir.. will feel more confident.. ty
@@yakaiahbandari6382 will try my best whenever I am free. All the best with your preparation 👍
Superb /\
Sir are these Questions from Allen AITS?
No . Sri Chaitanya Chaina papers.
Sir can we calculate the potential at C2??
If it is possible.. please post a solution pic of that..
Infinitely large and indeterminately large as there is a charge at C2
sir if we wanted potential at a point outside the whole sphere will we take contributions from charges inside cavity?....becoz in this pronlem for potential inside cavity we took contributions form the charges outside the cavity too...
Yes , due to individual inside charges, potential exists at outside point. But due to all inside charges , potential outside comes out to be zero here
@@PHYSICSSIRJEE sir if the charge distribution on inner surface of cavity would be a non uniform one so then also potential due to induced + already present there would cancel ?
How is it possible that potential inside cavity(c2) is same as the conductor because E!=0 inside the cavity
Time stamp of your doubt please?
electric field is not zero inside the cavity except at C2.
Last pathfinder problem answer is 4q
sir please speak a little louder
Noted 👍
19:03 nothing would happen
Please try again
@@PHYSICSSIRJEE ok sir now I realised.....I SHOULD'VE MENTIONED THAT THE POSITION of charge q won't matter until they are inside the shell because when they are inside net field produced by them is....0 hence equipotential ......and hence Inside the shell the induced charge and the charge placed are non existent.....for outer world ........only the induced charge distribution on the inner side of the shell will change .....but the answer doesn't changes here I feel..... But yes we can not ignore it as it comes in the outer universe outside the shell than the answer would be affected by the location of that charge q...also
SIR ITS A HUMBLE REQUEST FROM STUDENTS SIDE PLEASE COME ON UNACADEMY PLUS OR START YOUR PERSONAL COURSE AND BLESS US WID YOUR TEACHING 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🥇🥇🥇🥇🥇🥇🥇🥇🥇🥇🥇🥇🥇
ALREADY FEELING THE REAL PHYSICS WITH NITIN SACHAN SIR
Maybe sir has his own aspirations of setting up something very big. So maybe that's why he isn't coming on plus. But as a plus member I also want sir to join unacademy.