carbocations and rearrangements

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  • เผยแพร่เมื่อ 19 ธ.ค. 2024

ความคิดเห็น • 41

  • @BallyBoy95
    @BallyBoy95 12 ปีที่แล้ว +12

    Thank you sooooooooooo much!
    You saved me getting £25 for Chem Tuition just for this one topic lol. ;D
    Really helpful, great vid.

  • @johnmandrake8829
    @johnmandrake8829 8 ปีที่แล้ว +19

    Mann..bless you for creating these vids and helping us all

  • @6x886
    @6x886 4 ปีที่แล้ว +3

    These people are real heroes. For making education free for all.

  • @crystalshanshuo
    @crystalshanshuo 12 ปีที่แล้ว +8

    This is super helpful!!! Thank you for making it so clear! :D

  • @shaaa..n4263
    @shaaa..n4263 3 ปีที่แล้ว +2

    This helps me understand JEE BASICS . THANKS a lot 😍 Khan's acedemy

    • @ayushpandey8963
      @ayushpandey8963 ปีที่แล้ว

      bhaha right , after completing the syllabus i just wanted to revisit everything in depth and this is the right content!

  • @onlyvoocals
    @onlyvoocals 3 หลายเดือนก่อน +1

    What about reactivity of Carbocation?

  • @ermiasbelachew9921
    @ermiasbelachew9921 3 ปีที่แล้ว +1

    thank you very much because I understood how rearrangement occurs and why

  • @ForgottenBathory7
    @ForgottenBathory7 8 ปีที่แล้ว +4

    How do I choose between shifting the CH3 or the H in a particular molecule?Can I shift any of them all the time?

    • @jahanzebbutt8472
      @jahanzebbutt8472 8 ปีที่แล้ว +2

      notice how in the example for the methyl shift he had a quaternary carbon which donated a methyl group to the Carbo cation but in the hydride shift he had a tertiary carbon which donated a hydride. just remember that a quaternary carbon has four CARBONS attached to it and a tertiary carbon has 3 CARBONS attached to it. so if we have a tertiary carbon then it will be bonded to 3 carbons and a hydrogen. if we have a quaternary carbon then there will be no hydride shift because there will be no hydrogens on the carbon due to the carbon already being bonded to 4 carbons. hope this helps

    • @poorasslawstudent
      @poorasslawstudent 7 ปีที่แล้ว +3

      After an entire paragraph you never answered her question so I will: A tertiary carbon will donate its lone proton (H) before it donates one of its Me groups. That's all you had to say. I used to be against so many prereqs but it's like science majors don't know how to read & write.

    • @glom9995
      @glom9995 7 ปีที่แล้ว +1

      R Foutz brutal

    • @PandaBearBeast
      @PandaBearBeast 7 ปีที่แล้ว +4

      Honestly, when I was first learning this stuff I would have preferred their answer over yours because it's more detailed and helps you to visualize it. I'm assuming that you're a science major as well and that's great that you know how to read and write, but you don't have to act like an arrogant jerk and be rude to someone that was just trying to help.

    • @kevorkdanayan4791
      @kevorkdanayan4791 4 ปีที่แล้ว

      @@PandaBearBeast @r John 's answer is more to the point. that person called @Jahanzeb Butt didn't answer the question. He just explained the difference between a quaternary and a tertiary carbon. But the questions is whether a hydride or alkyl shift happens from a tertiary carbon to a carbon bearing the the formal charge.

  • @prameshwarlalsaini5872
    @prameshwarlalsaini5872 6 ปีที่แล้ว

    sir I need so more examples stability of carbonation,carboantion
    and free redical.so,where I get this.
    tell me some kind of website and any book

  • @Liquoricilicious
    @Liquoricilicious 9 ปีที่แล้ว +1

    So will this always happen if it CAN happen in a mechanism?

    • @ManuAnand97
      @ManuAnand97 9 ปีที่แล้ว +5

      Yes. Always. Various questions are formed on this concept where the student fails to identify the hydride & methyl shifts and form a wrong product.

  • @thenomadicprofessor6696
    @thenomadicprofessor6696 7 ปีที่แล้ว +1

    Do the shifts require energy?

    • @pawanprakash4131
      @pawanprakash4131 7 ปีที่แล้ว

      yes, it requires Energy

    • @stargazer4023
      @stargazer4023 7 ปีที่แล้ว

      Very little - the rearrangements are usually very rapid even when the reaction mixture is cooled below room temperature.

  • @poojapancholi5337
    @poojapancholi5337 8 ปีที่แล้ว +1

    so helpful thank u so much

  • @d3niseS
    @d3niseS 12 ปีที่แล้ว +1

    so helpful! Thank you!

  • @muhammadzubair7396
    @muhammadzubair7396 2 ปีที่แล้ว

    Thanks a bunch 🤩

  • @Shenaz6
    @Shenaz6 10 ปีที่แล้ว

    Very helpful, thank you.

  • @liang2201
    @liang2201 10 ปีที่แล้ว

    good video. helpful. Thank you so much.

  • @omageprosper9673
    @omageprosper9673 3 ปีที่แล้ว

    Pls how do we know when to do a methyl shift and when to do a hydride shift

  • @EXOL_1485
    @EXOL_1485 2 ปีที่แล้ว

    Thank you for this

  • @Toronto2245
    @Toronto2245 10 ปีที่แล้ว +1

    Bravo!

  • @TheElise1203
    @TheElise1203 12 ปีที่แล้ว +3

    Great video! Was completely lost as to how to determine the rearrangement! Thanks!

  • @kavyagujjari9119
    @kavyagujjari9119 2 ปีที่แล้ว

    thank you so much!!

  • @guneetkaur__
    @guneetkaur__ 4 ปีที่แล้ว

    Thnx

  • @tatianaalanana5537
    @tatianaalanana5537 8 ปีที่แล้ว

    thanks 😍😍😍😘😘😘😘😂😂

  • @parthjariwala6569
    @parthjariwala6569 4 ปีที่แล้ว

    so clutch

  • @adithyapatil4346
    @adithyapatil4346 4 ปีที่แล้ว

    ❤️❤️

  • @khaledragheb6503
    @khaledragheb6503 6 ปีที่แล้ว

    Thanks but the shifts arent for as so im out betchessss.

  • @p4blo90
    @p4blo90 8 ปีที่แล้ว

    👏👍

  • @tteedghihh
    @tteedghihh 10 ปีที่แล้ว +2

    I'm smarter than all of you. Just sayin.