Hi, math teacher here, really love how you have an x-scale. The curriculum we teach has no reference to this and my students will love it. Having a formula outright for an x-scale for them to use is awesome, thanks!
Brian you rock man, Im a 44 year-old mom of a high school senior doing credit recovery during Covid-19 at home. I have not had precal since Auburn University 1994. Thank you for running through some algebra steps, so much has changed. My son can enter the formulas into a graphing program ( desmos I think), but I pick up the formulas and rules better. I really needed to see you do the common denominators and walking through the formula. Thank you so much!!!!!!!!!!!
i know this video was 8 years ago but i do online school and the way you put it is so straightforward and easy to understand. i love how instead of including a whole ton of irrelevant information you just show us how to do the work and how to solve it. the issue i have with online school is they put a ton of information in one single paragraph and it's hard to decipher what they're trying to say. i appreciate the way you explain it and give us step by step in an easy way to follow. youve helped me a lot this year thank you a lot :-)
I just wanted to thank you for making this video because it has really helped a lot. I was so stressed for my quiz, but I remembered the way you taught how to do the phase shifts! Thank you sooo sooo much
oh so the scale is period/4 ! I thought you meant pi/4 lol. I was going crazy getting weird numbers in the calculator. Thank YOU BRIAN!!!!! I AM OFFICIALLY MCLOVINYOU!!!!
I was having hard time going through these trig function graphings, and this video helped A LOT! I wish you were my math teacher. Thanks so much for making this vidoe :))
I enjoy your style, you remind me of my high school math teacher (who I owe many apologies too). It's been 13 years since and I'm finally ready to listen, thank you for posting these videos!
Very useful. Just a little observation. I think discussion is fast and it seems there is an assumption that every viewer has mastered already which could defeat the purpose of teaching the learners.
I wonder what will happen if the C is not a whole angle (i mean like 23 degrees or like that) Can you help me with that too sir Love this video by the way ♥️
as the vertical transformation is -2 and u shift 2 units but the cosx graph is starts from 1 then, the shift should b 3 units!!as we done in log graphs pls tell
Consider we have a sinusoidal graph with a minimum point at (1,1) and a midline at (1.5,1.5) and a amplitude of [.5]. We want to find what g(x)=, and g is a trigonometric function of the form g(x)=a sin(bx+c)+d. We know the function is a result of translations and stretches applied on the basic function of sin(x). We want to transform the graph of sin(x) to our g(x) function. First we want to find the period, we know that the sin(x) period is 2pi and its amplitude is 1 unit. So g's period is equal to 4 times the horizontal (x value) so (1.5-1=.5), we take the difference of both the x values to find the distance in between those two points and then multiply by 4 to complete one cycle, or period.(( example: we start at the minimum point (1,1) from there we follow the curve up to the midline of (1.5,1.5) that's 1/4 then we go to the maximum point that's 2/4 then back down to the midline thats 3/4 then to the minimum thats 4/4=1 period, we made a total of 4 jumps(from min. to 1)mid. then to 2)max. to 3)mid. then 4)min.)so that's we we multiply by four.)) . So 4 times .5=2 units(period). In order to horizontally shrink the period of sin(x) to 2 units, we need to to multiply x by 2pi/2=pi to obtain (pi x). g's amplitude is equal to the vertical distance between the highlighted points, which is .5 units. In order to vertically shrink the amplitude of sin(pi x) to .5 units, we need to multiply it by .5 to obtain sin(pi x). Now use a translation to bring the intersection point with the midline from (0,0) to the location given by the graph, (1.5,1.5). This calls for a translation 1.5 units to the right and 1.5 units up, so .5sin(pi x) is transformed into .5sin(pi(x-1.5))+1.5=.5sin(pi x-1.5pi)+1.5. Answer) .5sin(pi x-1.5pi)+1.5.
how did you get the negative numbers? like negative 16pi/6, negative 13pi/6, and so on. because I was adding pi/2 to 2pi/3 but it only took me back to negative pi/6.
because with no transformations the minimum point of the occurs at pi, so since there is a shift left 2pi/3 your new minimum value will occur at x=pi/3
I don't know if you need the answer anymore, but basically it means that you're subtracting -2pi/3 which become adding it. So basically in that case, 2pi/3 is negative which is why there's an addition sign
Brian McLogan is my hero. Period.
No pun intended
Someone should show this to
My teachers so they know how to teach!!!!!!
disagree ! there is an easier way
exatlly
@@yulisgold7201 link?
I was sooooo confused on how the x-scale was obtained, until now. This helps soooo much.
Rosas in trouble 😂
Hi, math teacher here, really love how you have an x-scale. The curriculum we teach has no reference to this and my students will love it. Having a formula outright for an x-scale for them to use is awesome, thanks!
lets go, a teacher that admits they don't know everything. Appreciate you dude.
you are such a good teacher for watching videos like this and finding ways to improve your class.
8 minutes and this man has taught me more than my teacher has failed to teach in 2 weeks. Thank you and this man has t
Brian you rock man, Im a 44 year-old mom of a high school senior doing credit recovery during Covid-19 at home. I have not had precal since Auburn University 1994. Thank you for running through some algebra steps, so much has changed. My son can enter the formulas into a graphing program ( desmos I think), but I pick up the formulas and rules better. I really needed to see you do the common denominators and walking through the formula. Thank you so much!!!!!!!!!!!
This helped me so much for online school. Especially when catching up to things I could not get. Thank you so much.
i know this video was 8 years ago but i do online school and the way you put it is so straightforward and easy to understand. i love how instead of including a whole ton of irrelevant information you just show us how to do the work and how to solve it.
the issue i have with online school is they put a ton of information in one single paragraph and it's hard to decipher what they're trying to say. i appreciate the way you explain it and give us step by step in an easy way to follow.
youve helped me a lot this year thank you a lot :-)
I just wanted to thank you for making this video because it has really helped a lot. I was so stressed for my quiz, but I remembered the way you taught how to do the phase shifts! Thank you sooo sooo much
oh so the scale is period/4 !
I thought you meant pi/4 lol. I was going crazy getting weird numbers in the calculator.
Thank YOU BRIAN!!!!! I AM OFFICIALLY MCLOVINYOU!!!!
haha you are very welcome!
I was having hard time going through these trig function graphings, and this video helped A LOT! I wish you were my math teacher. Thanks so much for making this vidoe :))
You guys have a great teacher.
I enjoy your style, you remind me of my high school math teacher (who I owe many apologies too). It's been 13 years since and I'm finally ready to listen, thank you for posting these videos!
You are very welcome!! Happy to be there for you
This was BEYOND helpful. Thank you so much.
Brian, you knocked this out of the park.
My revision and study for my exams are much easier with your explanations. Thank you so much for dedicating time to help others, you are a hero!
That was so succinct and simple I think I like trigonometry more, now... Thanks!
Respected Sir.
Your way of teaching is very good 👍👍👍
This man has saved my math grades more times than I can count
🌠 Very Good, Brian McLogan, Keep It Up! 🌠
OMG!!! this video SAVED ME!!!! Thanks for breaking it down to layman's terms.
THank you for deciphering code
thank you so much. your videos are really helpful.
happy to be able to help
amazing job explaining. Thank you
Thank you so much!!!!! My grades in calc are surviving off of these videos alone tbh lol
Thanks
you are a god for this THANK YOU
You saved me. Thank you!
Thanks for sharing stay connneted..
I love this guy
Thank you so much !!
you are very welcome!
thank you bro
This just saved me from a mental breakdown
🙌🙌🙌
do you have to reduce them?
Thank you so much.
you are very welcome Fiona!!
113,540 people now know about Rosa getting in trouble 7 years ago
Thank you 🙏🙏🙏
i should pay my tuiton to you
Very useful. Just a little observation. I think discussion is fast and it seems there is an assumption that every viewer has mastered already which could defeat the purpose of teaching the learners.
THANK YOU
I wonder what will happen if the C is not a whole angle (i mean like 23 degrees or like that)
Can you help me with that too sir
Love this video by the way ♥️
Hi sir well, I've been wondering why we kept adding π/2
would this work if the equation of the b value was outside of the bracket e.g y=2cos0.5(x - pi/4) + 3
please help! how did you get your x scale?
ara v you get it by graphing
You need to use the unit circle
isn’t the formula supposed to be acos(b(x-c))+d? that’s what i was taught
thankas zaddty :)
very nice
thanks!
do you have videos of graph to function????
as the vertical transformation is -2 and u shift 2 units but the cosx graph is starts from 1 then, the shift should b 3 units!!as we done in log graphs
pls tell
Is the x-scale just another word for period function?
I'm from Australia so we learn a bit differently to you guys from the U.S
I Think so yeah
What if they give you the graph and ask for equation.
Consider we have a sinusoidal graph with a minimum point at (1,1) and a midline at (1.5,1.5) and a amplitude of [.5]. We want to find what g(x)=, and g is a trigonometric function of the form g(x)=a sin(bx+c)+d. We know the function is a result of translations and stretches applied on the basic function of sin(x). We want to transform the graph of sin(x) to our g(x) function. First we want to find the period, we know that the sin(x) period is 2pi and its amplitude is 1 unit. So g's period is equal to 4 times the horizontal (x value) so (1.5-1=.5), we take the difference of both the x values to find the distance in between those two points and then multiply by 4 to complete one cycle, or period.(( example: we start at the minimum point (1,1) from there we follow the curve up to the midline of (1.5,1.5) that's 1/4 then we go to the maximum point that's 2/4 then back down to the midline thats 3/4 then to the minimum thats 4/4=1 period, we made a total of 4 jumps(from min. to 1)mid. then to 2)max. to 3)mid. then 4)min.)so that's we we multiply by four.)) . So 4 times .5=2 units(period). In order to horizontally shrink the period of sin(x) to 2 units, we need to to multiply x by 2pi/2=pi to obtain (pi x). g's amplitude is equal to the vertical distance between the highlighted points, which is .5 units. In order to vertically shrink the amplitude of sin(pi x) to .5 units, we need to multiply it by .5 to obtain sin(pi x). Now use a translation to bring the intersection point with the midline from (0,0) to the location given by the graph, (1.5,1.5). This calls for a translation 1.5 units to the right and 1.5 units up, so .5sin(pi x) is transformed into .5sin(pi(x-1.5))+1.5=.5sin(pi x-1.5pi)+1.5.
Answer) .5sin(pi x-1.5pi)+1.5.
@@letspass3465 thank you
PreCalc Moment
ong
So for us to get phase shift my prof says to do c/b. Idk why since bx-c=0 is actually a little easier
5:02 why its 2pi/6. Should it be pi/3. ?
Yo, this helped a bit but you trying to do my paper?😂
is rosa on the front office yet?
Ily thanks
how did you get the negative numbers? like negative 16pi/6, negative 13pi/6, and so on. because I was adding pi/2 to 2pi/3 but it only took me back to negative pi/6.
You have to subtract because you are going on to the negative side of the number line. You subtract pi/2 when you go to the left.
How do I solve this..
y= -3[1+sin(1/2x-π/12)]
Kyle Spicer thank you I did
Why is the minimum of the point at pi/3 and not at (0,5)?
because with no transformations the minimum point of the occurs at pi, so since there is a shift left 2pi/3 your new minimum value will occur at x=pi/3
Hi even your not my prof for me you are my best prof.
gosh this makes me frustrated that you aren't my teacher... like srsly my teacher is so so sooo inadequate!!
I am somewhat confused about the Phase Shift part, why did we say (x + (2Pi/3)) when we said that (bx - c)? Wouldn't it be (x - (2Pi/3)) instead then?
I don't know if you need the answer anymore, but basically it means that you're subtracting -2pi/3 which become adding it. So basically in that case, 2pi/3 is negative which is why there's an addition sign
Thank christ
I love you
has said here that over 2 periods
6:28 I first saw it and bumm. My mind exploded. But then it's okay :V
Why am i even paying for college at this point 😭
goat!
i love u
Happy to help
what if there is no C?
Then no vertical shift
@@brianmclogan Thanks!!! I dont know what I’d do without you :’)
I don't agree with x-scale. It can be that or another. Just being consistent, any x-scale will be congruent.
🐐
it would make way more sense to students to write it as acos(b(x-c))+d.
100% agree
rosa getting expelled 1080p
👍👍👍👍👍👍👌👌👌👌👌
Hi sir well, I've been wondering why we kept adding π/2
Hi sir well, I've been wondering why we kept adding π/2
Hi sir well, I've been wondering why we kept adding π/2
Hi sir well, I've been wondering why we kept adding π/2