Learning to Graph the Sine Function with Transformations
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- เผยแพร่เมื่อ 1 ต.ค. 2024
- 👉 Learn how to graph a sine function. To graph a sine function, we first determine the amplitude (the maximum point on the graph), the period (the distance/time for a complete oscillation), the phase shift (the horizontal shift from the parent function), the vertical shift (the vertical shift from the parent function) and the x-scale (the distance between the turns and the x-intercepts). After we have obtained these features, we plot the points on the graph and graph accordingly.
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Organized Videos:
✅ How to Graph Trigonometric Functions
• How to Graph Trigonome...
✅ How to Graph Tangent | Learn About
• How to Graph Tangent |...
✅ How to Graph Secant | Learn About
• How to Graph Secant | ...
✅ How to Graph Sine and Cosine | Learn About
• How to Graph Sine and ...
✅ How to Graph Trigonometric Functions | Learn About
• How to Graph Trigonome...
✅ How to Graph The Sine Function
• How to Graph The Sine ...
✅ How to Graph The Cosine Function
• How to Graph The Cosin...
✅ How to Graph The Tangent Function
• How to Graph The Tange...
✅ How to Graph The Cotangent Function
• How to Graph The Cotan...
✅ How to Graph Cosecant Function
• How to Graph Cosecant ...
✅ How to Graph The Secant Function
• How to Graph The Secan...
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It’s sad how an 11 minute video on 2x speed has made me understand this entire lesson whereas my teacher’s almost two weeks of ‘teaching’ this only confused me. Thank you so much 😭
@Ellis Royce You’re right. I don’t care
Shouldn't this phase shift have been in the other direction? When I plug in the pi/2 and 3*(Pi/2) for x I get 0 and 2 respectively.
That's what I thought too. The phase shift is positive so the zero should be at pi/2
I know this video was posted a long time ago but since this is a big platform and many could be getting the wrong information I was to say I believe you grpahed this wrong @BrianMcLogan this function should start at (pi/2, 0) because sine starts at the sinusoidal axis which is y = 0 for this function. The points should be (/pi/2, -2) (pi/2, 0) (3pi/2 , 2) (5pi/2 , 0) (7pi/2 , -2) to graph this.
Can you timestamp what point I made the mistake so I can review and correct?
@@brianmclogan Yes ofcource, I believe it was 10:25 where you did it.
The final graph should start from pi/2 going up, I think the phone distract u,
Here on Brian's videos because some teachers are absolutely incompetent. Thank God for this man!
These math videos are awesome because they always fill in the important blanks that my professor never manages to mention.
the graph's initial period should start at π/2 right? Even in desmos it starts at π/2?
yes the initial period starts at pi/2
Ok thanks!
"actually you know what you're in luck" ... I love how he makes you feel as if you've won something ;p
I got anxiety when he told one of the students to put their phone down and I haven't been in high school in 6 years lol
I'm going to need to write you a "Thank You" letter when I graduate. You're the sole reason I am making through my math courses.
Thank you very very much.
3:15 LOL
Uh oh a test.
Someone got caught vaping in the bathroom at 3:02
you explained really well but the graph should start from the origin at pi/2.
Very helpful video but please check the last step in drawing the graph. You should have put zero on the pi/2
Thank you for illustrating the influence a period change has on the c. It is an issue I've had multiple times.
To find the phase shift couldn’t you also multiply pi/4 by 2 because that’s how much period increased by and if you simplify that you still get pi/2
Your parent function is wrong. The max point should be at 1.
Looks like you shifted it left instead of right
Good class teacher and Thank you!!!! But Whole ok
But the final grafic seems to me Wrong. Supouse to star Sin grafic in (0, Pi/2)
By the grafic you are assuming ×=Pi/2 them Y=2 ( Wrong)
If: x=Pi/2 Y= 0 ( Correct )
wrong graph. should shift to the right, not left!!!
Professor do you have a video that explains the adding and the subtracting of the Pi fractions ? Because thats what’s confusing me through the whole video.
The graph is shifted pi/2 to the right
I am truly appreciate you and your teaching method. Your videos are awesome and very easy to understand. Thank you so so so much.
Thankyou!!!❤
goat
10:54 i think the graph should start from pi/2. Because i get 0 when i sub pi/2 into the sin equation
that is correct! thank you for noticing and posting
Great video. Your instruction is very clear. I especially appreciate that you validated Ng Chin Eon's observation. The presentation did not clearly lay out which way to shift. My guess is that you got distracted by the visitor and skipped over the direction. Thanks for clarifying.
You are welcome! Happy to help you out.
The GOAT💪🐐
Carol cheated?
the teacher forgot to calculate the end of the period, (which is the period shifted by pi/2) which is 4pi + pi/2 = 9pi/2. So that the period goes from pi/2 to 9pi/2.
you sketched the graph wrong. it starts at pi/2 where its value is 0 (not 1) and goes on until 9pi/2 where its value is again 0 not 1.
yeah I got confused until I realized the graph was wrong
Yes, you are correct, I also found the same problem.
I appreciate it. You're doing good work.
That green pen is very light, difficult to read close up numbers and symbols.
the parent graph not correct
Shouldn't the parent function only have 1 as its amplitude since the 2 amp should be the stretch only for this one right because its 2sin and not just sin? Love your videos. They are a very good review for me. Thank you.
why is the intercept at π/2 instead of π/4? I'm confused because inside the parenthesis it's (x/2-π/4)
great teacher helped me heeps
Isn't c the phase shift??
i love this man
shouldnt the sine graph start from the midline instead of starting from 2
Graph is starting at pi/2 and that’s the zero x intercept but I don’t know why Professor made it maximum point? 😟
thanks helped a lot
Why did you divide by 4 to get the x-scale?
This is such a great teacher.
Thank you sir,👍
for x=pi/2 y=0 we plot points and dont need to shift the graph
okay
Shouldn't the red graph be shifted pi/2 to the right? because it was -pi/2 in the function?
no the x/2 changes that shift
try it on desmos
Brian McLogan but if you have (x-pi/2) in the argument of sine/cos, you would translate pi/2 units to the right, right?
if it is (x-pi/2 then yes that is correct, if it is ((x/2)-pi/2) then it is pi to the right. Basically set the argument equal to zero and solve
Brian McLogan Oh yeah I see, cool. I actually had my trig graph/equation test today. The only question i got wrong was what are the asymptotes of y=csc3x. such a dumb mistake lol cause that question is really straightforward, i just was going too fast. Most likely gonna get 47/48 on the test. Right now im getting 97% in the class. Do you think that test mark will improve it? I'm really aiming to get 98% or 99% in the class, we got 3 tests + the exam to go...
how do we know that theres no shifting?
there is a shift, pi/2 to the right
Sorry sir i was wrong.
no worries
Thank you so much
you are very welcome!
you explained it very well. thanks this video saved me!
you are very welcome Tina.
good job explaining effect of 'b' on 'c' but then the screw up of x shift direction pointed by several.
also poor contrast of ink on white board and untidy writing.
the first point made a lot of amends for the rest, so thank you.
yea could have made the video better but glad you extracted some value
Brian mate it’s a great video and helped me a lot cheers ❤️