It’s sad how an 11 minute video on 2x speed has made me understand this entire lesson whereas my teacher’s almost two weeks of ‘teaching’ this only confused me. Thank you so much 😭
I'm going to need to write you a "Thank You" letter when I graduate. You're the sole reason I am making through my math courses. Thank you very very much.
I know this video was posted a long time ago but since this is a big platform and many could be getting the wrong information I was to say I believe you grpahed this wrong @BrianMcLogan this function should start at (pi/2, 0) because sine starts at the sinusoidal axis which is y = 0 for this function. The points should be (/pi/2, -2) (pi/2, 0) (3pi/2 , 2) (5pi/2 , 0) (7pi/2 , -2) to graph this.
Professor do you have a video that explains the adding and the subtracting of the Pi fractions ? Because thats what’s confusing me through the whole video.
Great video. Your instruction is very clear. I especially appreciate that you validated Ng Chin Eon's observation. The presentation did not clearly lay out which way to shift. My guess is that you got distracted by the visitor and skipped over the direction. Thanks for clarifying.
Shouldn't the parent function only have 1 as its amplitude since the 2 amp should be the stretch only for this one right because its 2sin and not just sin? Love your videos. They are a very good review for me. Thank you.
Brian McLogan Oh yeah I see, cool. I actually had my trig graph/equation test today. The only question i got wrong was what are the asymptotes of y=csc3x. such a dumb mistake lol cause that question is really straightforward, i just was going too fast. Most likely gonna get 47/48 on the test. Right now im getting 97% in the class. Do you think that test mark will improve it? I'm really aiming to get 98% or 99% in the class, we got 3 tests + the exam to go...
Good class teacher and Thank you!!!! But Whole ok But the final grafic seems to me Wrong. Supouse to star Sin grafic in (0, Pi/2) By the grafic you are assuming ×=Pi/2 them Y=2 ( Wrong) If: x=Pi/2 Y= 0 ( Correct )
the teacher forgot to calculate the end of the period, (which is the period shifted by pi/2) which is 4pi + pi/2 = 9pi/2. So that the period goes from pi/2 to 9pi/2.
good job explaining effect of 'b' on 'c' but then the screw up of x shift direction pointed by several. also poor contrast of ink on white board and untidy writing. the first point made a lot of amends for the rest, so thank you.
It’s sad how an 11 minute video on 2x speed has made me understand this entire lesson whereas my teacher’s almost two weeks of ‘teaching’ this only confused me. Thank you so much 😭
@Ellis Royce You’re right. I don’t care
I'm going to need to write you a "Thank You" letter when I graduate. You're the sole reason I am making through my math courses.
Thank you very very much.
Here on Brian's videos because some teachers are absolutely incompetent. Thank God for this man!
These math videos are awesome because they always fill in the important blanks that my professor never manages to mention.
Shouldn't this phase shift have been in the other direction? When I plug in the pi/2 and 3*(Pi/2) for x I get 0 and 2 respectively.
That's what I thought too. The phase shift is positive so the zero should be at pi/2
Thank you for illustrating the influence a period change has on the c. It is an issue I've had multiple times.
the graph's initial period should start at π/2 right? Even in desmos it starts at π/2?
yes the initial period starts at pi/2
Ok thanks!
I am truly appreciate you and your teaching method. Your videos are awesome and very easy to understand. Thank you so so so much.
I know this video was posted a long time ago but since this is a big platform and many could be getting the wrong information I was to say I believe you grpahed this wrong @BrianMcLogan this function should start at (pi/2, 0) because sine starts at the sinusoidal axis which is y = 0 for this function. The points should be (/pi/2, -2) (pi/2, 0) (3pi/2 , 2) (5pi/2 , 0) (7pi/2 , -2) to graph this.
Can you timestamp what point I made the mistake so I can review and correct?
@@brianmclogan Yes ofcource, I believe it was 10:25 where you did it.
"actually you know what you're in luck" ... I love how he makes you feel as if you've won something ;p
This is such a great teacher.
Very helpful video but please check the last step in drawing the graph. You should have put zero on the pi/2
you explained really well but the graph should start from the origin at pi/2.
The final graph should start from pi/2 going up, I think the phone distract u,
To find the phase shift couldn’t you also multiply pi/4 by 2 because that’s how much period increased by and if you simplify that you still get pi/2
I got anxiety when he told one of the students to put their phone down and I haven't been in high school in 6 years lol
3:15 LOL
Uh oh a test.
Professor do you have a video that explains the adding and the subtracting of the Pi fractions ? Because thats what’s confusing me through the whole video.
Why did you divide by 4 to get the x-scale?
I appreciate it. You're doing good work.
10:54 i think the graph should start from pi/2. Because i get 0 when i sub pi/2 into the sin equation
that is correct! thank you for noticing and posting
Great video. Your instruction is very clear. I especially appreciate that you validated Ng Chin Eon's observation. The presentation did not clearly lay out which way to shift. My guess is that you got distracted by the visitor and skipped over the direction. Thanks for clarifying.
You are welcome! Happy to help you out.
Shouldn't the parent function only have 1 as its amplitude since the 2 amp should be the stretch only for this one right because its 2sin and not just sin? Love your videos. They are a very good review for me. Thank you.
Thankyou!!!❤
why is the intercept at π/2 instead of π/4? I'm confused because inside the parenthesis it's (x/2-π/4)
i love this man
Isn't c the phase shift??
Someone got caught vaping in the bathroom at 3:02
shouldnt the sine graph start from the midline instead of starting from 2
Graph is starting at pi/2 and that’s the zero x intercept but I don’t know why Professor made it maximum point? 😟
thanks helped a lot
The GOAT💪🐐
great teacher helped me heeps
Shouldn't the red graph be shifted pi/2 to the right? because it was -pi/2 in the function?
no the x/2 changes that shift
try it on desmos
Brian McLogan but if you have (x-pi/2) in the argument of sine/cos, you would translate pi/2 units to the right, right?
if it is (x-pi/2 then yes that is correct, if it is ((x/2)-pi/2) then it is pi to the right. Basically set the argument equal to zero and solve
Brian McLogan Oh yeah I see, cool. I actually had my trig graph/equation test today. The only question i got wrong was what are the asymptotes of y=csc3x. such a dumb mistake lol cause that question is really straightforward, i just was going too fast. Most likely gonna get 47/48 on the test. Right now im getting 97% in the class. Do you think that test mark will improve it? I'm really aiming to get 98% or 99% in the class, we got 3 tests + the exam to go...
Looks like you shifted it left instead of right
Thank you sir,👍
how do we know that theres no shifting?
there is a shift, pi/2 to the right
Thank you so much
you are very welcome!
Good class teacher and Thank you!!!! But Whole ok
But the final grafic seems to me Wrong. Supouse to star Sin grafic in (0, Pi/2)
By the grafic you are assuming ×=Pi/2 them Y=2 ( Wrong)
If: x=Pi/2 Y= 0 ( Correct )
That green pen is very light, difficult to read close up numbers and symbols.
The graph is shifted pi/2 to the right
you explained it very well. thanks this video saved me!
you are very welcome Tina.
the teacher forgot to calculate the end of the period, (which is the period shifted by pi/2) which is 4pi + pi/2 = 9pi/2. So that the period goes from pi/2 to 9pi/2.
for x=pi/2 y=0 we plot points and dont need to shift the graph
okay
good job explaining effect of 'b' on 'c' but then the screw up of x shift direction pointed by several.
also poor contrast of ink on white board and untidy writing.
the first point made a lot of amends for the rest, so thank you.
yea could have made the video better but glad you extracted some value
Brian mate it’s a great video and helped me a lot cheers ❤️
goat
you sketched the graph wrong. it starts at pi/2 where its value is 0 (not 1) and goes on until 9pi/2 where its value is again 0 not 1.
yeah I got confused until I realized the graph was wrong
Yes, you are correct, I also found the same problem.
it is incorrect, you have a max at 3pi/2.
the parent graph not correct
Sorry sir i was wrong.
no worries
Carol cheated?
Your parent function is wrong. The max point should be at 1.
wrong graph. should shift to the right, not left!!!