MAN thank you so much for this video! You've explained a concept in 7 minutes, where I couldn't seem to grasp the idea in a lecture that is over an hour! Again, thank you very much!! Subscribed for Past, current, and future content :)
Hey just wanted to say thanks a bunch for posting such amazing videos!! You are honestly the only reason I passed calculus this semester [= now i must get through calc two and physics next semester =\ stay awesome!
Thank you again so much for this video, you always seem to post videos of what I'm going to be tested on, thank you for your time!!!! Truly appreciate it.
It occurred to me at about 3:12 that both of these functions are even about the X axis, first by observation and then by subbing y and -y to check the x value. So the integral could be taken from 0 to 2 and its value doubled, which makes the maths easier... for polynomials like this, the entire expression vanishes at the lower, zero bound and you only have to sub in for the upper (and do the doubling in this case) and your answer immediately appears.
Jason Meyler You have 2y^2 on one side and 4+y^2 on the other side. 2y^2 means there is two y^2. If you were to subtract one y^2 on both sides you would have 1y^2 = 4 left. (or y^2 = 4)
I see that you combined both equations as one algebraic expression and then integrated, ive taken calculus I, so I don't know the rules for these new problem types so I trust you and thank you for such amazing teaching, do you work as a calculus teacher in a college or university?
If your curves look like they're on top of each other such that you could call one the "upper" curve and one the "lower" curve, and you can draw vertical rectangles to approximate the whole area, then you need to integrate with respect to x. If your curves look like they're next to each other such that you could call one the "right" curve and one the "left" curve, and you can draw horizontal rectangles to approximate the whole area, then you need to integrate with respect to y. :)
+John Parks Hey John, to sketch a curve that's in terms of y, you could plot individual coordinate points and then connect them. For example, plug in 0 for y, and see what x value(s) you get back, then plug in 1 for y and see what x value(s) you get back. Or you could flip the variable and sketch the curve as if it were the normal y=...x..., and then reflect that curve over the line y=x. Either method will give you the graph of the curve x=...y...
+fancy pixel That's not a stupid question. The reason is because it's a definite integral, which means there's an upper and lower limit of integration, and whenever that's the case, you don't add the +C.
i love how slowly and simply you explained that, it was incredibly helpful. thanks a bunch!
+Clayton Marquardt I always hated when we had to move too quickly through the material, so I try not to do the same.
MAN thank you so much for this video! You've explained a concept in 7 minutes, where I couldn't seem to grasp the idea in a lecture that is over an hour!
Again, thank you very much!!
Subscribed for Past, current, and future content :)
:D
Hey just wanted to say thanks a bunch for posting such amazing videos!! You are honestly the only reason I passed calculus this semester [= now i must get through calc two and physics next semester =\ stay awesome!
I love the way this girl teaches calculus.
Thank you again so much for this video, you always seem to post videos of what I'm going to be tested on, thank you for your time!!!! Truly appreciate it.
You are literally an angel...there's just no other way!
This is kind of irrelevant but I have to say that u have such a sweet voice...makes watching these videos even better
It occurred to me at about 3:12 that both of these functions are even about the X axis, first by observation and then by subbing y and -y to check the x value. So the integral could be taken from 0 to 2 and its value doubled, which makes the maths easier... for polynomials like this, the entire expression vanishes at the lower, zero bound and you only have to sub in for the upper (and do the doubling in this case) and your answer immediately appears.
Thank you. I had this exact problem in my Calc 1 class.
That's awesome!! I'm so glad they helped!! :D
Glad I could help!
I can't stop thinking about your beautiful voice!!
Jason Meyler You have 2y^2 on one side and 4+y^2 on the other side. 2y^2 means there is two y^2. If you were to subtract one y^2 on both sides you would have 1y^2 = 4 left. (or y^2 = 4)
You're going to rock calc two and physics! :)
Loving the color of the board, please keep it that way :)
You're a life saver... I am bad in expressing gratitudes.. but thanks a bunch!
+TnV You're welcome, I'm glad it helped!!
Taking Calc 2 rn your vids are 👌
You're welcome!
Glad I could help! :D
Thanks!
thank you for all your videos
I have to send my teacher to u to teach him how to teach.
Great video and thanks
I'm sorry to hear about your teacher, but I'm glad I can help! :)
I wish some of these tools were available sooner as well! :)
I see that you combined both equations as one algebraic expression and then integrated, ive taken calculus I, so I don't know the rules for these new problem types so I trust you and thank you for such amazing teaching, do you work as a calculus teacher in a college or university?
+Ryan Morris I was a tutor for a long time, and now I do this full-time! :)
In the beginning of the video @ 1:01 you subtract y from both sides and getting an answer y^2= 4. How did you get that?
+Jason Meyler 2y^2-y^2 = y^2
Possible give us lessons in the conversion of the decimal system to binary system and vice versa
I really like this topic ;D Thank you once again!
You're welcome! :D
Thank you soooo much, that was very helpful!
thank you for your videos. You are very helpful
You're welcome!
I love you .......it just very helpful during quiz ....love u soo much
do you only put the +C when you have an indefinite integral?
yep! :)
GOD BLESS YOU, LADY!
Good explanation. Which software are you using for writing?
Thanks! I use Sketchbook (by Autodesk). :)
you are awesome!!!!!
So helpful!
thank you!!! :D
I don't know if its just me but shoudnt the integrand have 4 + y^2 instead of 4 - y^2? Is it just a translation error?
Is there any playlist containing related problems to this?
The third, fourth and fifth videos in this playlist are all area between curves problems: th-cam.com/play/PLJ8OrXpbC-BMz4irMey8DcJe_iiXgA9aI.html
Hello,
What brought me here is a quick question... How do we know when to integrate with respect to DY instead of DX?
If your curves look like they're on top of each other such that you could call one the "upper" curve and one the "lower" curve, and you can draw vertical rectangles to approximate the whole area, then you need to integrate with respect to x. If your curves look like they're next to each other such that you could call one the "right" curve and one the "left" curve, and you can draw horizontal rectangles to approximate the whole area, then you need to integrate with respect to y. :)
Wow. Thank you so much! Your response was very informative and helpful.
Quick question, u integrated the first function 4-y^2 but u didn't subtract the integration of the second function 2y^2. am I missing something?
Is there a method I can use to graph these x= equations on my TI-83 calculator?
I'm having trouble drawing the graphs when the function is in terms of y. Can someone please explain the process behind that?
+John Parks Hey John, to sketch a curve that's in terms of y, you could plot individual coordinate points and then connect them. For example, plug in 0 for y, and see what x value(s) you get back, then plug in 1 for y and see what x value(s) you get back. Or you could flip the variable and sketch the curve as if it were the normal y=...x..., and then reflect that curve over the line y=x. Either method will give you the graph of the curve x=...y...
CalculusExpert.com Thank you so much, I'll give that a try!
Aww thanks! :)
Thanks a lot
Thank you So Much
Do you have heterochromia? Looks awesome.
your very helpful thanks alot
I like it better too. :)
THANK YOU THANK YOU THANK YOU
i have a stupid question but why is there is no +c in the end?
+fancy pixel That's not a stupid question. The reason is because it's a definite integral, which means there's an upper and lower limit of integration, and whenever that's the case, you don't add the +C.
thanks
What software are you using, please?
Tq very much
I love you!
I explain here :) integralcalc . com/how-I-create-my-videos/
You're amazing
I must just have that sixth sense or something. :)
Ya I don't think TH-cam always give 100% accurate view counts
Thanks but give shortcut methods.
i love u
Your view count also says 3? weird, me too...
:)
mARRY ME PLEASE!
Aww thanks! :)