Mr lasseviren.. i really don't know how to say this to make you understand how thankful i am for your videos... but just know you are the main reason i am still a Physics student..... you restored my hope and confidence .. thanks.. hope one day i get to meet you and shake the hands of a legend
holy .. i can't believe that i can understand this fxxking eletric field. I don't know who you are and i don't know where you at, but thank you verrrrrrrrrrrrrrrrrrrrrrry much. You are my angel. I love you.
I've watched so many of your E and M type vids. I'm very thankful for them! After reading the chapter and sitting through a bad lecture they're so perfect to solidify my understanding! Keep making vids man you're great at it!
how come for the metal hollow sphere with the metal sphere with charge Q inside you said that the outter shell would have to be negative Q because of the argument that if E=0 within the metal shell the Qenc=0=Q+(-Q).. could we use the same argument in this case? that the metal shell would have to have a charge of -Q because if E=0 within a
When he is referring to the outer field of the cylinder, there cannot be any electrical field, because the outer shell is grounded, indicating no net charge, as the positive core charge negates the negative charge on the inner cylindrical shell. In part two he exactly comes to this conclusion, which also is identical to the example of the Gaussian sphere in an earlier video.
On the last problem, shouldn't the charge on the inside of the outer wall be -q, still being in elctrostatic equilibrium? In that case the outer shell should also be grounded, giving a net charge outside the cable of 0, and therefore E=0 by equivalence. But since there is an electric field outside i guess the outer shell is in fact not grounded, giving a positive charge q on the surface of the outer shell as well.
yes, I have the same question. If there is no net charge why there is electric field. In the concentric shell subject outer field was 0. I cannot understand.
@@eminemeldayilmaz9644 galiba sadece içerdeki yükü aldı içerdeki yükün E etkisi var, gerçek kablolarda da böyle galiba.dışardaki metal nötr. böyle olması gerekiyor olabilir mi ?
+Phillippe Foix Totally, but why use lambda for the cable, when we use sig. for hollow spheres/planar sheets, and rho for insulated spheres, etc. Seems counter intuitive, and I have my first exam tomorrow O_o
+Max Dornfest Use sigma for surface area, rho for volume. Since we are not concerned about either the area or the volume of the wire in this problem (i.e. we are treating it as a continuous line of charge,) use lambda.
I thought the shielding's job was to prevent the coaxial cable from leaking an electric field into the outside world. But the formula here shows that it does get out?
Yes, coaxial cables usually cause both electric fields and magnetic fields (and therefore EM waves) to cancel out when they are outside the cable. This is usually the case because the current going through the center wire is equal but opposite to the current going through the outside cylindrical wire. In the example in this video there is no current and there are only charges on the central wire. So no shielding in this case.
SIR IF THERE IS no net charge b/w 1 and 2 cylinder than that means there is some negative line charge density and the the charge for outer gaussian surfacre should be zero???
+NEERAJ SHARMA No. There's some charge on one surface and the inverse of that charge on the other. meaning that the net charge is zero because when you add the inner and outer surface charges the total is zero.
In order to have an Electric field between the cylinders one must have Potential difference (Voltage) across the cylinders. If the material of the cylinders is an insulator (non-conductive material) electrons would never travel to the surface of the cylinders creating no Electric field since there is no Potential difference there.
You are assuming the charge is positive when looking at an electric cable XD last time i checked,electrons had a negative charge,so shouldn't we take it as a negative if we follow the laws of common sense? (no offense)
Lambda can represent a negative number. Flow of charge can be positive if we take a frame of reference to be opposite the flow of electrons. You are a nob
11 Years later, and you are still helping people like me. Thank you!!
Mr lasseviren.. i really don't know how to say this to make you understand how thankful i am for your videos... but just know you are the main reason i am still a Physics student..... you restored my hope and confidence .. thanks.. hope one day i get to meet you and shake the hands of a legend
best physics teacher in youtube!
holy .. i can't believe that i can understand this fxxking eletric field. I don't know who you are and i don't know where you at, but thank you verrrrrrrrrrrrrrrrrrrrrrry much. You are my angel. I love you.
@William Han so sadly i could not correct the exam. so sad day. i tried my best but .. ㅜㅜ
@William Han ㅠㅠ 공부열심히하시고 몸조심하세여
I've watched so many of your E and M type vids. I'm very thankful for them! After reading the chapter and sitting through a bad lecture they're so perfect to solidify my understanding! Keep making vids man you're great at it!
I hope you became a teacher or some other profession. I really appreciate these videos and they help tremendously.
These Gauss's Law video's have been very helpful. Cheers!
how come for the metal hollow sphere with the metal sphere with charge Q inside you said that the outter shell would have to be negative Q because of the argument that if E=0 within the metal shell the Qenc=0=Q+(-Q).. could we use the same argument in this case? that the metal shell would have to have a charge of -Q because if E=0 within a
When he is referring to the outer field of the cylinder, there cannot be any electrical field, because the outer shell is grounded, indicating no net charge, as the positive core charge negates the negative charge on the inner cylindrical shell. In part two he exactly comes to this conclusion, which also is identical to the example of the Gaussian sphere in an earlier video.
idk how to put this in best words, but ur just amazing...
I love you. This is exactly the problem I'm working on.
@Yoshi Licks respect for replying to a 7-year-old comment. 🤝 This brings back good memories.
Finally, I can pass my emt class.
Extremely helpful....Thanks for such an explanation...
thanks for helping me ace my exam!
On the last problem, shouldn't the charge on the inside of the outer wall be -q, still being in elctrostatic equilibrium? In that case the outer shell should also be grounded, giving a net charge outside the cable of 0, and therefore E=0 by equivalence. But since there is an electric field outside i guess the outer shell is in fact not grounded, giving a positive charge q on the surface of the outer shell as well.
your videos really helps! Thanks for quality vids..
8:35 why we did not do that in previous examples ? why we didn't say E=0 ?
yes, I have the same question. If there is no net charge why there is electric field. In the concentric shell subject outer field was 0. I cannot understand.
@@eminemeldayilmaz9644 galiba sadece içerdeki yükü aldı içerdeki yükün E etkisi var, gerçek kablolarda da böyle galiba.dışardaki metal nötr. böyle olması gerekiyor olabilir mi ?
Sir what do you do when the outer cylinder has a negative charge density -Lambda
Wonderful explanation, thank you!
sir, how to know when to use limda, sigma and rho ?
Hakim Zaz For international convention lamda is for linear distribution, sigma is for area distribution and rho is for volumetric distribution
thank you very much..
+Phillippe Foix Totally, but why use lambda for the cable, when we use sig. for hollow spheres/planar sheets, and rho for insulated spheres, etc. Seems counter intuitive, and I have my first exam tomorrow O_o
+Max Dornfest Use sigma for surface area, rho for volume. Since we are not concerned about either the area or the volume of the wire in this problem (i.e. we are treating it as a continuous line of charge,) use lambda.
Then we'd be using gauss' law with the electric displacement D which looks at Polarization and electric field inside materials
this is a great video
thanks
what if instead of a line going down the axis we have a sphere
I thought the shielding's job was to prevent the coaxial cable from leaking an electric field into the outside world. But the formula here shows that it does get out?
Yes, coaxial cables usually cause both electric fields and magnetic fields (and therefore EM waves) to cancel out when they are outside the cable. This is usually the case because the current going through the center wire is equal but opposite to the current going through the outside cylindrical wire. In the example in this video there is no current and there are only charges on the central wire. So no shielding in this case.
i like u video....it very easy to understood
SIR IF THERE IS no net charge b/w 1 and 2 cylinder than that means there is some negative line charge density and the the charge for outer gaussian surfacre should be zero???
+NEERAJ SHARMA No. There's some charge on one surface and the inverse of that charge on the other. meaning that the net charge is zero because when you add the inner and outer surface charges the total is zero.
It's called the braid strand. Just a FYI
In order to have an Electric field between the cylinders one must have Potential difference (Voltage) across the cylinders. If the material of the cylinders is an insulator (non-conductive material) electrons would never travel to the surface of the cylinders creating no Electric field since there is no Potential difference there.
thanks for the video
you didn't quite explain why E =0 when in between the cylinders.
Magnetic field for coaxial cable
what if the outer layer has net charge
Elijah Hua than calculate that too
thanks!
merci
Gausss'ss law
@gerryramosftw
Was just going to ask the same thing..
why arent you my teacher?
You are assuming the charge is positive when looking at an electric cable XD last time i checked,electrons had a negative charge,so shouldn't we take it as a negative if we follow the laws of common sense? (no offense)
Lambda can represent a negative number. Flow of charge can be positive if we take a frame of reference to be opposite the flow of electrons. You are a nob
Tommyl21 Yeah i know λ can be negative,but i remember he said positive charge. Whats a nob?
I really appreciate
Thx
Good
Adamsın abi
dafuq did I just listen?
wait is this khan?
ch