while we short circuit AB terminal their is no current flowing though 8 ohm Resistors so the total short circuit current is flowing through 6 ohm Resistor.
@Amel Mennad current flowing through 6ohm resistor and no current flow through 8ohm resistor their is no short circuit across dependent source because 6ohm resistor is present here only 8 ohm is bypass due to short circuit
Here A terminal is open so no current will Flow towards A terminal But same amount of current will flow through 6 ohm and 8 ohm so that both are series
In this ckt their is only one node So we consider only v1 What you think v2 node between 8ohm and 6ohm this is not a node because 8ohm and 6ohm are in series
@@Sattiboyy when we connect 3terminal at a point is called node But in this ckt between 6ohm and 8ohm A terminal is open so that no current will flow toward the A terminal so it is not consider as a node
Why did you reverse the direction of 1.5*Ix current source. It is leaving current so by your convention it should be +ve. Please check this part sir and rest your explanation is nice and finally, Thevenin's equivalent voltage should be 2.462 V instead of 10.667V.
actually original question ix1.5 is entering to the node but i mistakenly written as leaves from node so i rectify it at 4:24 kindly consider so i take -ix1.5
actually original question ix1.5 is entering to the node but i mistakenly written as leaves from node so i rectify it at 4:24 kindly consider so i take -ix1.5
Thank you!It really help me😊
thank you so much. it really helps me for my final test :)
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You are very welcome
Tys sir... It's very useful for me
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you welcome
While calculating thevenin's resistance with 2nd method, You reversed the direction of Ix current. why?
Same query
Ix is leaving current so it would be +ve not -ve and Voc is already present how they can be in series
Here we write dependent current source value that is ix1.5 not ix
and this dependent current source entering to the node so it -ve
@@ElectricalBoostyou are wrong
Hi, I have a question if we hadn’t the 6 ohm resistor while using the sc method, how can we calculate the sc current in this case?
while we short circuit AB terminal their is no current flowing though 8 ohm Resistors
so the total short circuit current is flowing through 6 ohm Resistor.
But how if the circuit does not contain the 6 ohm resistor ? The dependent source will be short circuited ?
@Amel Mennad current flowing through 6ohm resistor and no current flow through 8ohm resistor
their is no short circuit across dependent source
because 6ohm resistor is present
here only 8 ohm is bypass due to short circuit
6ohm and 8ohm are discontinued sir?? How can it be in series??
Here A terminal is open so no current will
Flow towards A terminal
But same amount of current will flow through 6 ohm and 8 ohm so that both are series
Looks like you made and error with stating that Voc = 0 in the equation for the current thru the 6 ohm resistor
Why ur not considered other node as V2???????
Please respond to my answer
And give valuable explanation
In this ckt their is only one node
So we consider only v1
What you think v2 node between 8ohm and 6ohm this is not a node because 8ohm and 6ohm are in series
Understood or not?
@@ElectricalBoost not sir
@@ElectricalBoost so sir is there any potential drop across 6 and 8 ohm
@@Sattiboyy when we connect 3terminal at a point is called node
But in this ckt between 6ohm and 8ohm A terminal is open so that no current will flow toward the A terminal so it is not consider as a node
Why did you reverse the direction of 1.5*Ix current source. It is leaving current so by your convention it should be +ve. Please check this part sir and rest your explanation is nice and finally, Thevenin's equivalent voltage should be 2.462 V instead of 10.667V.
actually original question ix1.5 is entering to the node but i mistakenly written as leave from node
so i rectify it at 4:24 kindly consider.
5:31 I think it should be +Ix. 1.5
actually original question ix1.5 is entering to the node but i mistakenly written as leaves from node so i rectify it at 4:24 kindly consider
so i take -ix1.5
Bhai Tera LCM Galt tha
6 ku common liauhu
Ans check kara same hoga
LCM 140 aayega bhai
90 check kara
But I take 6 common so that is 30
Ache se check kara
Can't understand you at all
Bhai tune current ki direction reverse kardi, pura ques Galt Kar Diya tune!!!
actually original question ix1.5 is entering to the node but i mistakenly written as leaves from node so i rectify it at 4:24 kindly consider so i take -ix1.5
we really appreciate sir