You have really bad handwriting. Your '8' is indecipherable, and your rightmost character is either '!' or '1'. I'll do both problems, since I'm bored. For 3!, we have: (a² - 10)/√81 = 3! (a² - 10)/9 = 6 a² = 6*9 + 10 = 64 a = ±8 For 31, we have: (a² - 10)/√81 = 31 (a² - 10)/9 = 31 a² = 31*9 + 10 = 289 a = ±17 It's amazing that both interpretations yield integers. a = ±√(3!*√81+10) = ±8 a = ±√(31*√81+10) = ±17
I watched the video, and heard you say factorial, so the '1' is really intended to be '!'. BTW, your math isn't rigid in maintaining correct steps. You wrote: a² = 64 √a² = √64 a = ±8 The 2nd line loses the negative sign, but one magically appears in the 3rd line. You should have had written this: a² = 64 a = ±√64 a = ±8 The '√' symbol is the principal square root function, which returns nonnegative values when passed nonnegative values. The '±' symbol is prepended because the inverse of the square function yields 2 values, which can be described in terms of the principal square root and its negated value. Alternatively, you can use these steps: a² = 64 √a² = √64 |a| = 8 a = ±8
a^2-10/(81)^1/2=3!
a^2-10/9=6
a^2=9×6+10=54+10=64
a=+-8
You ❤❤❤
You have really bad handwriting. Your '8' is indecipherable, and your rightmost character is either '!' or '1'. I'll do both problems, since I'm bored.
For 3!, we have:
(a² - 10)/√81 = 3!
(a² - 10)/9 = 6
a² = 6*9 + 10 = 64
a = ±8
For 31, we have:
(a² - 10)/√81 = 31
(a² - 10)/9 = 31
a² = 31*9 + 10 = 289
a = ±17
It's amazing that both interpretations yield integers.
a = ±√(3!*√81+10) = ±8
a = ±√(31*√81+10) = ±17
I watched the video, and heard you say factorial, so the '1' is really intended to be '!'.
BTW, your math isn't rigid in maintaining correct steps. You wrote:
a² = 64
√a² = √64
a = ±8
The 2nd line loses the negative sign, but one magically appears in the 3rd line. You should have had written this:
a² = 64
a = ±√64
a = ±8
The '√' symbol is the principal square root function, which returns nonnegative values when passed nonnegative values. The '±' symbol is prepended because the inverse of the square function yields 2 values, which can be described in terms of the principal square root and its negated value.
Alternatively, you can use these steps:
a² = 64
√a² = √64
|a| = 8
a = ±8
Welcome bro