A point that is slowly dawning on me -- with a concrete example in this video -- is that everything along the path of trajectory gets compressed. This is very confusing to me. From spaceship B's perspective, it is not clear why the path to Basecamp (A) is shorter than from A's perspective. From A's perspective, doesn't it seem like the ship is shortened?
So you just jump off your spaceship at the base with instantaneous deceleration from .999c? Talk about a warm welcome home with massive kinetic energy.
I think relativistic effects remain restricted to object moving at relativistic speed. Such an object can't change anything outside its boundary limits.
But you are finding the time it takes base A and origin of B to coincide on B's perspective, but then on B's perspective he is stationary and base A is moving towards it, so the distance as measured by observer at B will be greater as according to him his reference frame is stationary
Motion is supposed to be relative. So if the base sees the spaceship to be 2.11 light years away and moving towards the base, the spaceship can be assumed as stationary and the base to be in motion towards the spaceship, and hence should be 2.11 light years away! So what is the peoblem then?
i think you make a mistake. shouldn't the person on the spaceship will see the distance further than the person on earth because length is contracted. so it should be L sub a = L sub b divided by gamma. Hence, L sub b = L sub a multiplied by gamma
Yes i am also in same delima as in previous question sir has told L sub B is length seen by the man in ship and used La=Lb/gama But in this it is reversed
Sir,I am sorry if this is a dumb question,but shouldn't the length transformation equation be the reverse according to the derivation? That is, shouldn't L(sub A)=L(sub B)√1-v^2/c^2 ?? Also,if the reverse is correct,can you please explain how?
@@MichelvanBiezen Ok...so here,should we take B as stationary reference frame and A as the moving one,moving towards B,since we are required to find distance with respect to B?
Wo we cover a distance in less time then it would take light to cover that same distance, are we going faster than light? Or does that mean 34 days at our speed would equate to 2 years on base?
Ty for the reply, keep up the good work sir. I dont know if you know it but you are making a real positive impact on the lives of many students like me.
The scenario is very funny, this guy just said you will leave the evil empire in the dust, are they not gonna follow you though? Lol. Great video though.
the lorentz factor is 22.4. When you find out the value of the speed of the spacecraft using the formula, the velocity of the spacecraft comes out to be really close to the velocity of light. Thus, he took it to be c.
Excellent. Certainly gets the brain ticking!
One of d Gr8st teachers ever seen.
A point that is slowly dawning on me -- with a concrete example in this video -- is that everything along the path of trajectory gets compressed. This is very confusing to me. From spaceship B's perspective, it is not clear why the path to Basecamp (A) is shorter than from A's perspective. From A's perspective, doesn't it seem like the ship is shortened?
So you just jump off your spaceship at the base with instantaneous deceleration from .999c? Talk about a warm welcome home with massive kinetic energy.
I think relativistic effects remain restricted to object moving at relativistic speed. Such an object can't change anything outside its boundary limits.
Yes, but an observer traveling near the speed of light will see the relativistic effects from his/her observation point.
But you are finding the time it takes base A and origin of B to coincide on B's perspective, but then on B's perspective he is stationary and base A is moving towards it, so the distance as measured by observer at B will be greater as according to him his reference frame is stationary
isnt that the point?
Motion is supposed to be relative. So if the base sees the spaceship to be 2.11 light years away and moving towards the base, the spaceship can be assumed as stationary and the base to be in motion towards the spaceship, and hence should be 2.11 light years away! So what is the peoblem then?
Great explanation
Thanks
Shouldn’t you divide by v instead of c?
When gamma = 22.8, v and c are essentially the same. (noted on the white board)
i think you make a mistake. shouldn't the person on the spaceship will see the distance further than the person on earth because length is contracted.
so it should be L sub a = L sub b divided by gamma. Hence, L sub b = L sub a multiplied by gamma
Objects will appear closer for observers on a fast moving space ship.
Yes i am also in same delima as in previous question sir has told L sub B is length seen by the man in ship and used La=Lb/gama
But in this it is reversed
Sir i have a small dought that in this question you took dB=dA/gama
But in previous question you took LA=LB/gama
Why is it so?
It depends on the reference point. Who is observing and what are they looking at.
Sir,I am sorry if this is a dumb question,but shouldn't the length transformation equation be the reverse according to the derivation?
That is, shouldn't L(sub A)=L(sub B)√1-v^2/c^2 ??
Also,if the reverse is correct,can you please explain how?
It depends on the problem and the point of reference. The best way to learn this is to work through a number of examples and problems.
@@MichelvanBiezen Ok...so here,should we take B as stationary reference frame and A as the moving one,moving towards B,since we are required to find distance with respect to B?
Wo we cover a distance in less time then it would take light to cover that same distance, are we going faster than light?
Or does that mean 34 days at our speed would equate to 2 years on base?
We can never travel at or faster than the speed of light. Therefore the latter is the correct case.
Ty for the reply, keep up the good work sir. I dont know if you know it but you are making a real positive impact on the lives of many students like me.
The scenario is very funny, this guy just said you will leave the evil empire in the dust, are they not gonna follow you though? Lol. Great video though.
Great! thank you!
thank you!
thank you. i didnt understand why you divided the distance as seen by B by the speed of light. did i miss something?
the lorentz factor is 22.4. When you find out the value of the speed of the spacecraft using the formula, the velocity of the spacecraft comes out to be really close to the velocity of light. Thus, he took it to be c.