For a much more in-depth analysis and review of feedback in electronic circuits watch videos 149 through 161. Starting at: th-cam.com/video/T9Wbm5Tm7Pw/w-d-xo.html Also, @52:15, the output waveform is not technically correct. It should be an upside-down version of the input, with the magnitude scaled up. In other words, the mirror image of what is drawn.
Professor, is the output signal that you drew at 52:15 correct? BTW, these lectures are excellent and I am enjoying the course and taking a lot of notes. I am a retired ME.
Is that output waveform from an inverting amplifier right? It should only flip it upside down right but the picture you drew is flipped leftside right . Correct me if I am wrong.
What is the relation of delay and instability , concerning that if there is no delay, the stability is related to the gain when the minus input varies. And when there’s delay, I don’t understand how it influence the stablity
Professor, I have a doubt (around the 1 hour time). Let's think of an operational amplifier with negative terminal at ground, and the positive terminal with the resistor R2 between it and vout and R1 between it and vin. Ignoring stability, etc for a moment, it can still theoretically produce a stable output right? Vout = A(V+ - V-). If Vout is finite, we would be having V+ following V-. Think of a scenario where V+ is slightly dipping below 0 (V- is grounded). Now we can still assume as if current flows from vin to v+ then from v+ to vout right. And A*vdelta condition is also satisfied since vdelta here is -ve since the positive terminal is dipping slightly below 0. It would still behave as an inverting amplifier right, atleast in steady state theoretically?
Professor are you going to share practical courses using simulation maybe I really enjoy your courses and sure many of new electrical engineering student ❣️
at 52:45 the first configuration of op-amp you said that Vout directly affecting the V1 because R2 has no current but in second configuration R2 has current now how Vout affect the V1
Time Stamps:
0:00 = Review and Overview
2:40 = Amplifier
13:30 = Operational Amplifier
19:39 = Ideal vs Practical Op-Amp
30:51 = Feedback
37:50 = Asymptotic Equality
45:37 = Inverting Amplifier
57:44 = Non-Inverting Amplifier
1:06:10 = Funny Things with Active Circuits
Thank you for making these videos available to all! you are a great teacher!
For a much more in-depth analysis and review of feedback in electronic circuits watch videos 149 through 161. Starting at:
th-cam.com/video/T9Wbm5Tm7Pw/w-d-xo.html
Also, @52:15, the output waveform is not technically correct. It should be an upside-down version of the input, with the magnitude scaled up. In other words, the mirror image of what is drawn.
thanks for everything.
Wow, that part about instability was gold 35:50
the way he DELIVERS
LOL, yeah it was awesome.
Amazing professor! Thanks for the clarification.
Professor, is the output signal that you drew at 52:15 correct? BTW, these lectures are excellent and I am enjoying the course and taking a lot of notes. I am a retired ME.
You are right. I should be the mirror image of what I drew. Thanks for bringing this up.
Even I got the same doubt bro.Then i lost it and now corrected it but I must say cleared op amp basics in one go
You are a magician,.Proffessor 🤩
you made this so interesting sir!
Is that output waveform from an inverting amplifier right? It should only flip it upside down right but the picture you drew is flipped leftside right . Correct me if I am wrong.
What is the relation of delay and instability , concerning that if there is no delay, the stability is related to the gain when the minus input varies. And when there’s delay, I don’t understand how it influence the stablity
Professor, I have a doubt (around the 1 hour time). Let's think of an operational amplifier with negative terminal at ground, and the positive terminal with the resistor R2 between it and vout and R1 between it and vin. Ignoring stability, etc for a moment, it can still theoretically produce a stable output right? Vout = A(V+ - V-). If Vout is finite, we would be having V+ following V-. Think of a scenario where V+ is slightly dipping below 0 (V- is grounded). Now we can still assume as if current flows from vin to v+ then from v+ to vout right. And A*vdelta condition is also satisfied since vdelta here is -ve since the positive terminal is dipping slightly below 0. It would still behave as an inverting amplifier right, atleast in steady state theoretically?
Professor, do you have extensive feedback lectures? I would love to see what are your thoughts on that topic!
Yes, watch 158N all the way to 171N.
@@AliHajimiriChannel thanks professor! :)
Hi Sir, when is voltage gain important? when is current gain important? when is power gain important?
Professor are you going to share practical courses using simulation maybe I really enjoy your courses and sure many of new electrical engineering student ❣️
at 52:45 the first configuration of op-amp you said that Vout directly affecting the V1 because R2 has no current but in second configuration R2 has current now how Vout affect the V1
is their a quick trick to identify the type of feedback in a big complicated analog circuit?
Please watch videos 149 through 161 for a much more in-depth treatment. Start at:
th-cam.com/video/T9Wbm5Tm7Pw/w-d-xo.html
inverting amp's graph was a mistake? How come no one spotted it in the class
how come that guy eating bananas in the front row