This type of question is solved through logically drawing out the graph of g(x). I have covered this type of question in my continuity and differentiability playlist, Check it out!
you will easily be able to answer this question. follow these steps: 1. open the modulus sign and make more piece wise definitions of f(x). 2. Then once f(x) is perfect for differentiation then differentiate it. 3. then put x->x-1 for f(x-1) and put x->x+1 for f(x+1), then add. 4. draw graph and it will be simple to give the answer. I have covered this type of question in my playlist of continuity and differentiability, check it out!
Sir ... please explain the solution for this question:
Let f(x)=|||x|-1|-1| and g(x)-(max f(t): x
This type of question is solved through logically drawing out the graph of g(x).
I have covered this type of question in my continuity and differentiability playlist, Check it out!
Let f(x)={1−∣x∣,0,∣x∣≤1∣x∣>1 and g(x)=f(x−1)+f(x+1), then number of points where g(x) is not differentiable is
you will easily be able to answer this question.
follow these steps:
1. open the modulus sign and make more piece wise definitions of f(x).
2. Then once f(x) is perfect for differentiation then differentiate it.
3. then put x->x-1 for f(x-1) and put x->x+1 for f(x+1), then add.
4. draw graph and it will be simple to give the answer.
I have covered this type of question in my playlist of continuity and differentiability, check it out!
Sir...in step 3 ...I am confused how to draw f(1-x)+f(1+x) together