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JEE Beyond Numbers
เข้าร่วมเมื่อ 30 ส.ค. 2023
"Think beyond Numbers, Solve Beyond Numbers"
This channel focuses on providing quality maths content for JEE Mains and Advanced Aspirants through solving problems and adequate theory.
This channel focuses on providing quality maths content for JEE Mains and Advanced Aspirants through solving problems and adequate theory.
Simple AOD Question
#jee #jeemains #jeeadvanced
TELEGRAM CHANNEL LINK: t.me/+Nt-f-4RkCp9iOWY9
This is a good and simple question to revise some of the concepts of Application of Derivatives chapter.
TELEGRAM CHANNEL LINK: t.me/+Nt-f-4RkCp9iOWY9
This is a good and simple question to revise some of the concepts of Application of Derivatives chapter.
มุมมอง: 32
วีดีโอ
Advanced Geometry Question
มุมมอง 7622 ชั่วโมงที่ผ่านมา
#jee #jeemains #jeeadvanced TELEGRAM CHANNEL LINK: t.me/ Nt-f-4RkCp9iOWY9 This is a very good question as this would help you gain confidence over your understanding of mathematics that even if a new type of curve comes in any question, You can apply your basic understanding and observations to solve it.
Non-Standard Ellipse (Shifted and Rotated) Problem
มุมมอง 124วันที่ผ่านมา
#jee #jeemains #jeeadvanced TELEGRAM CHANNEL LINK: t.me/ Nt-f-4RkCp9iOWY9 This is a very good question if anybody want to learn about Non-Standard Ellipse.
Binomial Coefficient Question (Advanced Level)
มุมมอง 109วันที่ผ่านมา
#jee #jeeadvanced #jee mains TELEGRAM CHANNEL LINK: t.me/ Nt-f-4RkCp9iOWY9 This is a question which involves good manipulative skills in order to solve properly.
Solution of Triangles problem (Advanced Problem)
มุมมอง 54วันที่ผ่านมา
#jee #jeemains #jeeadvanced TELEGRAM CHANNEL LINK: t.me/ Nt-f-4RkCp9iOWY9 This is a very good problem which requires precise solving in order to solve it within 2 to 3 mins.
Advanced Question (Binomial Coefficients)
มุมมอง 98วันที่ผ่านมา
#jee #jeemains #jeeadvanced TELEGRAM CHANNEL LINK: t.me/ Nt-f-4RkCp9iOWY9 This is a great question which almost replicates the Standards of a JEE Advanced Level Question.
Straight Lines Question (Doubt Question)
มุมมอง 99วันที่ผ่านมา
#jee #jeeadvanced #jeemains TELEGRAM CHANNEL LINK: t.me/ Nt-f-4RkCp9iOWY9 This was a question asked by a student in one of the previous videos. This question involves good calculation so doing calculation properly is a very important task in this question.
Good Matrix Question
มุมมอง 1152 วันที่ผ่านมา
#jee #jeemains #jeeadvanced TELEGRAM CHANNEL LINK: t.me/ Nt-f-4RkCp9iOWY9 This is a very good Question which requires the following two observations: 1. B = adj(A) 2. by multiplying with B^-1 we can modify the given condition of the question into A^2 = 2I
Straight Lines Question | Target JEE Advanced 2025
มุมมอง 9114 วันที่ผ่านมา
#jee #jeemains #jeeadvanced TELEGRAM LINK: t.me/ Nt-f-4RkCp9iOWY9 This was a good question that came in JEE Advanced 2021 Paper which requires the following theorem in order to solve it: Reflection of orthocentre about any side of triangle lies on the circumcircle.
Permutation and Combination Question | JEE Advanced 2021 PYQ
มุมมอง 5114 วันที่ผ่านมา
#jee #jeemains #jeeadvanced TELEGRAM LINK: t.me/ Nt-f-4RkCp9iOWY9 This question requires good basic understanding of Counting Techniques in order to solve properly.
Striling Number of first and second kind (P&C)
มุมมอง 9121 วันที่ผ่านมา
#jee #jeeadvanced #jeemains TELEGRAM LINK: t.me/ Nt-f-4RkCp9iOWY9 This video contains the concept of Stirling numbers of First Kind and Second Kind in Permutations and Combinations. 0:00 Stirling Number of First Kind 24:22 Stirling Number of Second Kind 44:05 Relation Between Stirling Number of First Kind and Second Kind
Hard Question of JEE Advanced 2015
มุมมอง 693หลายเดือนก่อน
#jee #jeeadvanced #jeemains Telegram Channel LINK: t.me/ Nt-f-4RkCp9iOWY9 This is a very good question of JEE Advanced 2015 paper which includes integration inequalities.
Advanced Probability Question 2
มุมมอง 348หลายเดือนก่อน
#jee #jeeadvanced #jeemains Telegram Channel LINK: t.me/ Nt-f-4RkCp9iOWY9 This is a very good question when its comes to the making the cases inorder to solve it. The question consists of a very interesting reverse situation which when tackled nicely results in a small and clean solution.
Advanced Probability Problem 1
มุมมอง 1172 หลายเดือนก่อน
#jee #jeeadvanced #jeemains I provide some extra question in my telegram channel and also you can ask me your doubts here. Telegram Channel LINK: t.me/ Nt-f-4RkCp9iOWY9 This was the pyq of probability which came in jee advanced 2018 paper. The Question is really good when it comes to its logical thinking and making cases. This video clarifies how to make cases in depth. Another video on probabi...
Advanced Integration Question
มุมมอง 7042 หลายเดือนก่อน
#jee #jeeadvanced #jeemains This question is inspired by a question of similar type that came in jee advanced 2015 paper and I hope after watching the video, you would be able to that pyq of jee advanced 2015. This question was posted way before on my telegram channel, so if you are interested in more questions like this make sure to join the telegram channel. Telegram Channel LINK: t.me/ Nt-f-...
IIT JEE 2007 Paper 1 Paragraph Type Questions
มุมมอง 873 หลายเดือนก่อน
IIT JEE 2007 Paper 1 Paragraph Type Questions
Question 1 to 9 (Single Corect MCQ Type) of IIT JEE 2007 Paper 1 Revision
มุมมอง 744 หลายเดือนก่อน
Question 1 to 9 (Single Corect MCQ Type) of IIT JEE 2007 Paper 1 Revision
JEE Advanced 2019 PYQ || Target JEE 2025
มุมมอง 1674 หลายเดือนก่อน
JEE Advanced 2019 PYQ || Target JEE 2025
Functional Equation Question 4 (JEE Advanced 2020 PYQ) (Important Method)
มุมมอง 1764 หลายเดือนก่อน
Functional Equation Question 4 (JEE Advanced 2020 PYQ) (Important Method)
Definite Integration Question 4 (Leibnitz's Rule Question)
มุมมอง 734 หลายเดือนก่อน
Definite Integration Question 4 (Leibnitz's Rule Question)
Thanks a lot Can you bring some good physical chemistry questions
Let f(x)={1−∣x∣,0,∣x∣≤1∣x∣>1 and g(x)=f(x−1)+f(x+1), then number of points where g(x) is not differentiable is
you will easily be able to answer this question. follow these steps: 1. open the modulus sign and make more piece wise definitions of f(x). 2. Then once f(x) is perfect for differentiation then differentiate it. 3. then put x->x-1 for f(x-1) and put x->x+1 for f(x+1), then add. 4. draw graph and it will be simple to give the answer. I have covered this type of question in my playlist of continuity and differentiability, check it out!
Sir...in step 3 ...I am confused how to draw f(1-x)+f(1+x) together
Sir ... please explain the solution for this question: Let f(x)=|||x|-1|-1| and g(x)-(max f(t): x <= t <= x+1, x in R} Then, 1)The graph of ` g (x)` is symmetrical about ? 2) The number of points of non differentiability of g (x) ?
This type of question is solved through logically drawing out the graph of g(x). I have covered this type of question in my continuity and differentiability playlist, Check it out!
Please add some AITS good questions..
I will try.
Really Good Question Btw love your content
Thank you for increasing frequency
This gem channel wont get any traction without a good pfp a white background with J B N would also suit
Thanks for the recommendation 😃. The Logo has been made. Hope you liked it!
Great problem
Bhai question ki frequency badha do
Sir ek question doubt tha 2023 paper 1st ka 4th question limits ka saval tha usme ye confusion hai limit does not exist answer kyu ni ho skta ek video bna kr explain kr do sir
Okay, video coming soon 😄.
Great Explanation
Sir, please teach theory also
Actually theory videos takes a lot of time if you want any specific chapters theory then I can try.
Which city do you teach
I don't teach for now. I only make these TH-cam videos to help JEE aspirants.
Sir.... please do a video on maximum and minimum of a set having 3 or 4 elements. It is very confusing concept. Please 🙏
Can you elaborate what type of question you are referring to. In fact, you can give me a question of that type and I can give it a try.
Very useful property..... and a very propable concept for exam. Thanks 🙏
If line through point P(a,2) meets the ellipse x2/9+y2/4=1 at A and D and meets the coordinate axes at B and C so that PA , PB , PC , PD are in geometric progression, then the possible values of a can be? Sir please provide a detailed solution for this question especially in regards to how the points are taken and their coordinates will be evaluated in it?
Video coming soon!
Respected Bhaiya.... Thank you so so very much. I can't thank you enough. Really appreciate your timely help. Thanks a lot. God bless you 😊🇮🇳🌹❤️🙏
Bhai plz regular 🙏 ur lectures are helpful
Sir .... please provide a detailed video on Stirling number method of first and second kind for pnc chapter. My exam is on 6 th December. Thanks and Regards 🙏🇮🇳
Uploaded! Link: th-cam.com/video/rHDjdeM2kbw/w-d-xo.htmlfeature=shared
Bhaiya ye answer galat hai Coz you forgot to use chain rule in the diff of x^1/x In reality e^π is bigger
Thanks for pointing out the error. I will reupload it soon!
Are derivatives not more effecient?
when you will take derivative and equate it to zero. then after squaring it you will reach a trigonometric equation which will take time to solve. But the solution described in video will solve the question in less time. Derivatives are not always efficient when it comes to "find the maximum or minimum value" type of questions.
Sir.... please explain the concept of Stirling number method of first and second kind in PNC. It is very urgent for my exams. Your explanation is awesome and excellent which makes it easy to understand. Please sir 🙏🇮🇳🌹❤️
I am myself stuck in my exams 😅. But I would try to help you with it as it ends. I would be free after 29 November.
Sir my exam is from 2nd December and combinatorics is on 6 th December. It would be great help if you could make a video on the requested topic before that. Thanks 🙏🇮🇳
Wow🎉
Hi ji, ye channel toh bohot aacha hai dhire dhire advanced poora ho jayega 😊. Sir aap thoda in sequence krwa skte hain I mean jaiseeweeeeeeeeee starting ke quadratic first hai toh 1 hour lecture, top 5 question maza aa jayega 🐧🌹
Bhaiya apki content mast hai qs bhi mast hai but followers kam he kyu ki apki channel todha jyada plain hai i get it you are trying to teach maths but todha thumbnails improve karlo bhot improvement aayega
PLEASE UPLOAD MORE VIDEOS
Bhaut badiyaaa ❤❤❤
Second like😅😅
We could do it by one more way , I.e , pehle hamm numerator ko o to pie ka interval Kar lete , or phir numerator Mei baki jo bachta woh pie to n pie interval rehta jo ki ek increasing interval hye or f(x) bhi positive hi hye . Toh yeh saari type (t+y)/t bann jati yahan par t and y both greater then zero.. So limit Hamari greater then 1 , a jaati.. Just 15 seconds mein ho Jaata..
Yes, You are right!. I appreciate your effort 😊.
@JEEBeyondNumbers 👍
thank you please keep uploading more helps a lot in revision :)
Sir 999 maximum value nahi h na par vo range m aayegi
999 maximum value ho bhi sakti hai and nahi bhi ho sakti hai. It all depends ki function ki actual range kya hai. Video mai jo range ki baat ho rahi hai vo bass ek subset hai actual range ka. Question kaafi kam information wala hai toh ham siraf itna bata paye hai ki 1/999 se 999 tak all values must be in the actual range but ho sakta hai it actual range 0 se 999 ho ya phir 1/999 se 1000000 ho.
@@JEEBeyondNumbers okay sir , thank you
Amazing question Nd explanations
From which book
Please reply
1000 challenging problems in mathematics for jee mains and advanced and all other competitive examinations by sameer bansal. publications: GRB
Direct derivative kar sakte hai na? Tho i have practiced this approach.. this type question is in black book .. also i have a demand.. can u make such videos on conic sections and probability plss. Like those untouched concepts which are IIT can ask next year
Actually direct derivative se jo trigonometric equation milegi usko solve karna kaafi lengthy hai. Conic Section and Probability videos coming soon.
I respect your hard work ❤❤
👏👏👏
Sir vaise maine ise click karte hi samjh gaya ki isme distance formula wala approach lena hai Maine pahle bhi aise 3 se 4 question kiye hai
Sir, I am not a JEE aspirant, but I see videos of mathematics as hobby. You have explained the concept of sandwitch theorem very well. Thanks for such informative video. But I have one query. In the second question, one observation is that for each value of n, the sum cosists of summation of 2n+1 terms. And the second observation is that as n increases, the first term of sum decreases. The second observation indicates that the series is converging but the first observation indicates that series may be diverging. Can we prove that overall the series is converging ?
Thanks for you appreciation. Here is some information about your comment: I think you are a little confused about the terminologies such as convergent or divergent. Actually the series is not a Infinite Series ( series having infinite terms). So we can't say that this is convergent or divergent. Let say if you want to consider a similar Infinite Series. Consider summation of 1/(r^2) where r goes from 1 to infinity. This series is convergent. Here you would notice that your explanation that the terms are decreasing might seem to be true. BUT it will not always be true. Consider 1/r where r goes from 1 to n. here the series is divergent . Even if you think that the terms are decreasing. Convergent and Divergent behaviours are found by using standard methods such as Integral test. The series (1/r^2) and 1/r behaviours are determined using Integral test or To be more specific P-test(special case of Integral test). I Hope it has cleared your query.
Ab ye distance wali out of the box baat exam ke bich me click kaise kregi🌬
haan thora tough toh hai. lekin it is better ki tum kuch cheeze already decide karke chalo about any type of problem. For example jo question video mai hai usmai following methods should come in mind: 1. square kholkar expansion and simplification 2. substitution karke derivatives ka concept use karna 3. distance method (discussed in video) Aise karke tumhe paper mai bhi easy rahega questions solve karna. Hope it helps.
thanks sir please contuinue this series
Glad, that you liked it!
Sir ek correction hai Apne final ans mai power hi nhi likha Great explanation btw
I have already pointed out this thing that,always do the question in advance or simply trim that part where you think about the question. And solution could be explained in less 10 minutes.
I will take care of that from next time. Thanks for your suggestion.
By the way great explanation😃
Slopes are equal... It's may easily
Done 👍🏼
Thank you 😊
Good shit bro, keep uploading 💪💪
First like ❤
Nice approach