Mod-05 Lec-24 Continuous Functions on a Metric Space

[@hardeepkhachar3168]

At 38:34 , shouldn't it be 0

[@kulkarnish5601]

Yes. It should be 0 < delta < min{|x|, epsilon/(3|x|)} for x not equal to 0 and 0 < delta < sqrt(epsilon) for x =0. Thanks.

[@anilraghu8687]

Uniform continuity 23:00

[@raushankumarpathak8939]

its P(f(x), f(y)) at 25:50

[@jahirul9568]

Thanks team

[@nandhini3106]

sir unmala.very nice and excellent sir

[@kanikarajain4842]

if f: X -> Y then if x is discrete metric space then every function defined on it is continous on X .....How ?????............Plz tell me Sir

[@cristianvaccarella8649]

Since you got a discrete metric on X every subset of X is open, so for every open subset G in Y, f^-1(G) is always open in X, that is the same as saying f is continous on X (see preceding lecture if this is not clear)

[@gaini24]

because every point of a discrete metric space is an isolated point.

[@jahirul9568]

Because, inverse image of every open set in Y is again a open set in X.

[@harshitpandey7890]

Thanx sir

[@nandhini3106]

sir complex continuous function na solluga sir pls

[@garimasingh9626]

Sir I want to do PhD under your teaching in maths.. what should I do? At jrf basis am I eligible?

[@samvlogs7378]

nice #mathophilic

[@nandhini3106]

sir unmala.very nice and excellent sir