For every chapter, my teacher provides support videos to help with the topic; your videos have made numerous appearances and for this unit, your videos are our introduction. I use your videos mainly for calc. All of my calc 2 notes come from your videos. Everyone comments how amazing you are but you truly are carrying America's engineers through their general education courses. The impact you have made will be around for decades to come.
I'm in university physics for life sciences 1 and you're continuing to save my life just like you did last year to get me into university! thank you for your dedication
My Physics improved from 50% on semester test 1 to 97% on semester test 2🎉🎉 Thank you sir, I have nothing to offer. I’ll thank you properly in the future.
What a legend sia, for some reason, all i needed was to watch like the first few minutes of the video to have a greater understanding of latent heat as compared to when im in school learning this for at least 2hrs TY SO MUCH TEACH
Thank you very much!!!! Your videos are so clear and easy to understand, especially with the examples that you show. I was studying for my final physics exam and I was confused on many topics but I then started learning with your videos and ended up getting an A! Thank you, thank you, thank you! Could you do some more videos based on General Physics 2? Thank you and hope you are safe during this pandemic!
The minus sign negates what material the heat flows out of so the minus sign on the last problem should be on the left -Qm=Qh20 The heat flows out of the metal= heat is gained in the water Great video thanks!!
THANK YOU SIR FOR YOUR EFFORTS IN ASSISTING THE WORLD WITH PHYSICS I M FROM SOUTH AFRICA BY THE WAY, BUT AS I WAS DOING THE PROBLEM ON MY OWN I DISCOVERED THAT THE ANSWER IS 127.6 C . I THINK THE MISTAKE ON YOUR PART OCCURRED WHEN YOU WERE DETERMINING DELTA T , INSTEAD OF INITIAL TEMP 21 YOU HAD 20 DEGREES CELSIUS
Thank you so much for this vid. Now I undestand it well but there's a tiny mistake you made on the last problem. You wrote 27-20 instead of 27-21. Thank you soo much.
When talking about the green house effect, people count vegetation as a dark material but vegetation is sculpturallly complicated, so that some bits of leaf are in the light and many others in shade so that they are often categorised as dark and so as collectors of heat not reflectors of visible light, when all sunlight falling on the reflective top of leaves get reflected back up skywards. If you are taking a photograph of leaves, the pools of light on the lit bit of the leaf annoyingly come out as a stronger shape than the actual leaf comes out as being, the shine coming off leaves often often comes out as light, as bits of white in the photograph it comes out as white. If you take a photo of the sunny side of a tree, its colour is much lighter than the other side but even this lighter side does not relfect the shinyness of leaves because on the sunny side of a plant you see the underside and so the non sunny side of the leaves that are above the camara and as leaves are often curved you also see the sides of leaves that are dark because curved away from the sun. I think all this should be mentioned when people categorise the effect of vegetation on climate change. Another aspect of the usefulness of vegetation as a coooler of the world, without mentioning how they take carbondioxide out of the air, is how very shinny hay and straw are, so this dead vegetation would, if left on the ground, both aislate what is a pretty good material as far as storing heat is concerned, earth, i have read that earth has the same ability to store heat as brick but also, hay and straw are very reflective grasses are full of glass, silica, which should put animals off eating grass, so hay and strawlike live leaves and probably more so, also reflect sun light back towards space. Have you thought how much land world over is left fallow for a year where wheat is grown? Half as much as is used to grow wheat, though this is not an agricultural habit used in modern Norht America? Also lots of land is ploughed in spring, just before the heat of summer, in preparation for autumn planting of wheat so leaving so much earth to accumulate heat, that it is absolultely mind boogling. once it did nto matter how much of a material which was a good accumulater of heat was left bare to be heated by the sun but now things have changed and it does matter.
Thank you so much my guy,,,u helped me so much is the confusion I had on thermodynamics.... thanks thanks thanks God bless u....I took some weeks trying to understand this but u helped me in 31 minutes,,, thanks my guy
Thank you very much for this video your explanations are always the best Sir. I think you made mistake at 29:50, final temperature of the water according to the given statement is 21 degrees Celsius not 20 therefore final answer of the problem is 127.6 not 148.9
thank you so much for the explanation but there is a problem in the last question. you made a mistake somewhere at 27:02 if you check your calculations, it is heat gained by hot metal= heat gained by water but the problem is that when getting your temperature difference, you wrote (27-150) which is wrong. it is (150-27) because heat is being lost final temperature- temperature of the metal itself.
Thank you sir for all what you have shared. your content is terrific. I went to physics classes abt thermodynamics and I didnt understand sh*** but after your thorough explanation I start to discuss the core of the lesson with my teacher. again thank uu so much . Chapeau
How can the ice be a water at 0celecius? It’s wrong (10:00min) for that exercise to covert the ice to water at different temperature we have two kinds of heat which are q=ml and a=mcdt just added them
Hello, just for clarification. @6:40 example, why not include the sensible heat computation since the process required energy before melting the ice to latent heat?
Yes you are right. where he put 20, it should be 21. He's human like the rest of us. It doesn't matter how good you are or how smart, mistakes will always be inevitable which is why you can't always take his work as law. For example he seems to like working with C and L in joules, where as my textbook has them in KJ with the decimal moved to reflect it. I've been using my numbers and so my answers have been tending to be a little more accurate then his just because of the decimal placement. Sure enough when he converts back to KJ at the end, our answers are very close.
WOW you explanation is perfect but in the last problem about the metal and water , in heat of water you compensated the change in temperature 7 but it should be 6
Hi. At 6:20, how do I know the latent heat of fusion? It’s not given in the question. The same goes for the specific heat capacity of water used at 7:42.
@@Gmaing-madrataIs Arabic your native language? A lot of English jokes are very confusing to non native English speakers. For instance, you spelled college wrong. You spelled it as collage. In English a collage is a type of artwork. So I was trying to make a clever joke around it… Hope that makes sense, not trying to be rude. One love brother!
We know ice aka water is solid at 0 degrees and so on and so fourth , but how do we find that, the required temp for each state out for other substances.
I think on the final problem you distributed your negative incorrectly for waters mcat value. q1+q2=0 so q1= (-q2) the negative is distributed over M, C, and Delta T. I get a specific heat of around 127.62 J/kg*degrees C. when I plug this specific heat value into q1+q2 I get around 0 (0.06=3767.4+(-3767.34)) and the values are rounded so that makes sense. If you plug in 148.9 to the metals specific heat you get the equation 0=3767.4+(-4395.528) which cant be. If i've made a mistake my bad
In a physics class, the instructor has assigned a task to determine an experimental value for the heat of fusion of ice. The students dry and mass out 26.8-gram of ice and place it into a coffee cup with 100.0 g of water at 36.4°C. They place a lid on the coffee cup and insert a thermometer. After several minutes, the ice has completely melted and the water temperature has lowered to 18.1°C. What is their experimental value for the specific heat of fusion of ice? What is the answer?
Final Exams and Video Playlists: www.video-tutor.net/
seriously bro no intro no outro just straight to the point in the most simple wording possible
*cries* you're basically my physics teacher right now. ily.
Edit: I’ve graduated high school, you guys can do it!! I believe in youuu
then you my classmate. We're in the same boat
@@najeaandfriends6183 I wish you luck friend.
All true, y'all my classmates
Hey wanna skip class my classmatesss
Au di yes mr. Classmate lets skip today
you've covered a 3 days lecture in 3 seconds and explained it way better than my lecturer ever could, thank you.
a 30min video in 3sec?
true
@Let's Make gotta love storytime
You must have ADHD.
3 days ? I took it in 2 hours only😂
Bruh how tf did I learn more here in 20 mins than 8 hours of being taught by an actual teacher. Actual Legend man, Your my new physics teacher lol
In the final problem you made a mistake. The change in T for Q(h2o) should be 27-21 not 27-20 and the answer should be 127 J/KG*C
You deserve more likes.
Suggestion plzz
127.5 to be precise
I've tried to do this problem for more than 3 times getting that answer thinking there's something I'm not doing right
@@yashjiwani1040 more like 127.4390244
dude, I walked out of Chem II totally vibe checked, but you have somehow risen me from the dead in 31 minutes. THANK YOU!
For every chapter, my teacher provides support videos to help with the topic; your videos have made numerous appearances and for this unit, your videos are our introduction. I use your videos mainly for calc. All of my calc 2 notes come from your videos. Everyone comments how amazing you are but you truly are carrying America's engineers through their general education courses. The impact you have made will be around for decades to come.
you're literally carrying my grades in three of my subjects dude, thank you
I'm in university physics for life sciences 1 and you're continuing to save my life just like you did last year to get me into university! thank you for your dedication
My Physics improved from 50% on semester test 1 to 97% on semester test 2🎉🎉
Thank you sir, I have nothing to offer. I’ll thank you properly in the future.
in IB physics rn and this literally covers 50% of topic 3. Thank you sir
me too :D
ikr
Im currently in hl physics and i am failing pls send tips
@@rico-enI get you… currently preparing for my SL mock that’ll happen in few hours-
@@nevermind9835goodluck i just finished my final exams last week just hang in there❤
What a legend sia, for some reason, all i needed was to watch like the first few minutes of the video to have a greater understanding of latent heat as compared to when im in school learning this for at least 2hrs
TY SO MUCH TEACH
this video was so incredibly helpful, I understood everything after being lost for weeks in class. THANK U SO MUCH
Physics final tomorrow morning. Thank man!
Same
Me too.
Me three
I can't thank you enough for explaining things in such a way that my professor can't.
this made so much more sense than the book and the teacher combined. Thank you
Q=ML -use whenever u have a phase change
Q=mcAT -use whenever the temperature change
A few tiny mistakes have already been mentioned below, but the video is otherwise EXTREMELY helpful!
Thank you very much!!!! Your videos are so clear and easy to understand, especially with the examples that you show. I was studying for my final physics exam and I was confused on many topics but I then started learning with your videos and ended up getting an A! Thank you, thank you, thank you! Could you do some more videos based on General Physics 2? Thank you and hope you are safe during this pandemic!
Do u know how to do specific heat or heat of vaporization and heat of fusion I need help
@@alishaislam9275 Sorry I have seen this now
The minus sign negates what material the heat flows out of so the minus sign on the last problem should be on the left
-Qm=Qh20
The heat flows out of the metal= heat is gained in the water
Great video thanks!!
Oh! Wow! this method of explaining is so amazing and very easy to understand. Teachers should explain like you. Thank you so much. 🙏🏼🙏🏼🙏🏼🙏🏼🙏🏼
Bruh you just changed the whole day tutor into just 30min, thank you very much 👏👍👌
i have no words, keep up the good work, it would be an understatement to say that you're amazing.
30:58 the given initial temp for water is 21 degrees not 20 degrees. Thanks for the vid anyway, very helpful!
final answer is 127.62 J/kg C
Made me understand a whole section within few minutes...I appreciate your standard of explanation
Right on time! My exam is tomorrow night! Thanks
Keke Wilson ME TOO FROM FUTURE
Same lol
5y🙃🙌🏻
Your videos helped me through college and continue to help me through my career, thanks!
Well done boss, my lecturer at UEW didn't help us at all
You helped through highschool and college. I can't thank you enough. I wish you'd do more bio/med videos. I'd pay to see you explain these concepts😍🙏
You explained it better than my lecturer did thanx
29:50 isn't it supposed to be 27-21 not 27-20 since the water's initial temperature is 21 C as given in the problem?
THANK YOU SIR FOR YOUR EFFORTS IN ASSISTING THE WORLD WITH PHYSICS I M FROM SOUTH AFRICA BY THE WAY, BUT AS I WAS DOING THE PROBLEM ON MY OWN I DISCOVERED THAT THE ANSWER IS 127.6 C . I THINK THE MISTAKE ON YOUR PART OCCURRED WHEN YOU WERE DETERMINING DELTA T , INSTEAD OF INITIAL TEMP 21 YOU HAD 20 DEGREES CELSIUS
Bungane Radebe damn man why u gotta shout like that
Nigga be quiet
@@donnaa7640 damn Donna chiiiiiiill
WHY ARE YOU YELLING
Thanks a lot!!! Took Months trying to grasp all these but Got it all in 31 min.
Thank you so much for this vid. Now I undestand it well but there's a tiny mistake you made on the last problem. You wrote 27-20 instead of 27-21. Thank you soo much.
When talking about the green house effect, people count vegetation as a dark material but vegetation is sculpturallly complicated, so that some bits of leaf are in the light and many others in shade so that they are often categorised as dark and so as collectors of heat not reflectors of visible light, when all sunlight falling on the reflective top of leaves get reflected back up skywards.
If you are taking a photograph of leaves, the pools of light on the lit bit of the leaf annoyingly come out as a stronger shape than the actual leaf comes out as being, the shine coming off leaves often often comes out as light, as bits of white in the photograph it comes out as white. If you take a photo of the sunny side of a tree, its colour is much lighter than the other side but even this lighter side does not relfect the shinyness of leaves because on the sunny side of a plant you see the underside and so the non sunny side of the leaves that are above the camara and as leaves are often curved you also see the sides of leaves that are dark because curved away from the sun. I think all this should be mentioned when people categorise the effect of vegetation on climate change.
Another aspect of the usefulness of vegetation as a coooler of the world, without mentioning how they take carbondioxide out of the air, is how very shinny hay and straw are, so this dead vegetation would, if left on the ground, both aislate what is a pretty good material as far as storing heat is concerned, earth, i have read that earth has the same ability to store heat as brick but also, hay and straw are very reflective grasses are full of glass, silica, which should put animals off eating grass, so hay and strawlike live leaves and probably more so, also reflect sun light back towards space.
Have you thought how much land world over is left fallow for a year where wheat is grown? Half as much as is used to grow wheat, though this is not an agricultural habit used in modern Norht America? Also lots of land is ploughed in spring, just before the heat of summer, in preparation for autumn planting of wheat so leaving so much earth to accumulate heat, that it is absolultely mind boogling.
once it did nto matter how much of a material which was a good accumulater of heat was left bare to be heated by the sun but now things have changed and it does matter.
Thank you so much my guy,,,u helped me so much is the confusion I had on thermodynamics.... thanks thanks thanks God bless u....I took some weeks trying to understand this but u helped me in 31 minutes,,, thanks my guy
I'm writing exams tomorrow and this really helped because this is exactly what I was looking for😀☺👓👍👏👏👏👏
Thank you sm. I’m in Honors Physics and we’ve just begun a very difficult lab involving fusion. Thank you!
bruh you are the best tutor on the planet
Physics is getting real in me waoo, thanks 👍
26:48 for this question i got 24,094,500 J
how do you know to use the specific heat capacity of water or ice when dealing with something at 0 degrees?
You deserve my teachers position
I can't thank this guy enough.
imagine learning the staff within 20 minutes but our lecturer taught us the topic
for 2 weeks
I appreciate your videos in every universe.
Man your teaching is the best
You teach so well tho , keep the ball rolling
better than my lecturer
you are.......I haven't word to say about you. keep up
Even at this time the video is very important 🎉Thanks man.Your didna great job.🎉🎉
u have just increased my knowledge..... Thank you
I owe this guy my life
Thank you very much for this video your explanations are always the best Sir.
I think you made mistake at 29:50, final temperature of the water according to the given statement is 21 degrees Celsius not 20 therefore final answer of the problem is 127.6 not 148.9
i freeking love this man
the final answer for the specific heat of the metal is 127.6 J/kg*c , the mistake that you got at the end is the inital temp for H2O it is 21*c
As I noticed too
This was very helpful now ill pass my exam lol
saaaaaame lol
you have singlehandedly saved my school year lmao
well explained,indeed,with ur help i managed to answer all my tut questions
Will be taking my exam few hrs from now, thank uu!
Yeah your the reason i passed my chemistry test
Felt like the value latent heat of fusion( 3.33 x 10⁵ ) is higher, but here it is saying latent heat of vaporization( 22.6 x 10⁵ ) is higher ?
He is right
kk
this man is a legend
but why exactly are we considering Qh as a negative value at 28:00, and how did you deduce the temperature changes at 29:30
thank you so much for the explanation but there is a problem in the last question. you made a mistake somewhere at 27:02 if you check your calculations, it is heat gained by hot metal= heat gained by water
but the problem is that when getting your temperature difference, you wrote (27-150) which is wrong. it is (150-27) because heat is being lost final temperature- temperature of the metal itself.
I wished that this was recommended to me earlier before I took my trials ;-;
I love youuuuu ❤️❤️❤️ thank you , you have no I idea how much you have help me out with physics
Thank you sir for all what you have shared. your content is terrific. I went to physics classes abt thermodynamics and I didnt understand sh*** but after your thorough explanation I start to discuss the core of the lesson with my teacher. again thank uu so much . Chapeau
Holy balls
@@xpellidagoat Indeed
How can the ice be a water at 0celecius? It’s wrong (10:00min) for that exercise to covert the ice to water at different temperature we have two kinds of heat which are q=ml and a=mcdt just added them
Hello, just for clarification. @6:40 example, why not include the sensible heat computation since the process required energy before melting the ice to latent heat?
in the calorimeter question you use 27-20c for the water. should it not be 27-21c or am I missing something?
😀😀 I also thought I was the one wrong
Yes you are right. where he put 20, it should be 21. He's human like the rest of us. It doesn't matter how good you are or how smart, mistakes will always be inevitable which is why you can't always take his work as law.
For example he seems to like working with C and L in joules, where as my textbook has them in KJ with the decimal moved to reflect it. I've been using my numbers and so my answers have been tending to be a little more accurate then his just because of the decimal placement. Sure enough when he converts back to KJ at the end, our answers are very close.
WOW you explanation is perfect but in the last problem about the metal and water , in heat of water you compensated the change in temperature 7 but it should be 6
Hi. At 6:20, how do I know the latent heat of fusion? It’s not given in the question. The same goes for the specific heat capacity of water used at 7:42.
An smp table has the values
I watched you in high school, now I am in collage and watching you
So you’re majoring in art?? lol
@@derekchatcavage9180 No I'm in betrol institute
@@Gmaing-madrataIs Arabic your native language? A lot of English jokes are very confusing to non native English speakers. For instance, you spelled college wrong. You spelled it as collage. In English a collage is a type of artwork. So I was trying to make a clever joke around it…
Hope that makes sense, not trying to be rude. One love brother!
Love you man, saved me so much
Your explanation is so clear. Thanks!
Why is no activation energy evident in state changes but there is for exothermic or endothermic reactions?
Bro for real, thank you so much fmd.
You are simply the best
isn't the value for the latent heat of fusion for ice 334 j/g only? i checked in the internet I don't know where it got the 3.33 x ^5
Well Thank you your videos helped me a lot I only had hours to study due to writing multiple exams
Thank you a lot may the almighty bless you thanks a lot ...now am good 👍 at this topic forever
Bro reached me the things I have no idea but my teacher taught for 2 months
You doing great work boss.
Thanks man ❤. You are always straight to point 😊
you help me better than my teacher ever did
Explain Latent heat of fusion, évaporation. Specific heat capacity, heat capacity and their differences as far Calorimetry is concerned
Sir ...can we say latent heat helps to change the state of surface molecules of water in evaporation?
We know ice aka water is solid at 0 degrees and so on and so fourth , but how do we find that, the required temp for each state out for other substances.
I think on the final problem you distributed your negative incorrectly for waters mcat value. q1+q2=0 so q1= (-q2) the negative is distributed over M, C, and Delta T. I get a specific heat of around 127.62 J/kg*degrees C. when I plug this specific heat value into q1+q2 I get around 0 (0.06=3767.4+(-3767.34)) and the values are rounded so that makes sense. If you plug in 148.9 to the metals specific heat you get the equation 0=3767.4+(-4395.528) which cant be. If i've made a mistake my bad
In a physics class, the instructor has assigned a task to determine an experimental value for the heat of fusion of ice. The students dry and mass out 26.8-gram of ice and place it into a coffee cup with 100.0 g of water at 36.4°C. They place a lid on the coffee cup and insert a thermometer. After several minutes, the ice has completely melted and the water temperature has lowered to 18.1°C. What is their experimental value for the specific heat of fusion of ice? What is the answer?
Thank you so much! I understand this because of you!!
I hope you're my lecturer!
Awesome explanation dude
I like he says the word earth, "Earf". makes him even more badass.
Currently cramming for my year 12 Physics test🙏🏻
Thank you so much, this lecture really helped me so much😭
الله يكثر من امثالك يا غالي
Great work. Your videos have been helping me. Thanks