this vid and the one about PV diagrams and internal energy (about 4h long) summed up my entire thermodynamics in physics degree im so glad this vid exists
@@ahmadsleiman37 Probably thinking of thermochemistry. If not, chemistry and physics do tend to have many overlaps in some areas so im not too surprised.
thank you so much! with your videos I'm learning more than I have ever learned at school! i started to understand physics normally, all with the help of your explanation.
Absolute king, all your videos are so helpful! The lecture notes on thermodynamics were hard to understand but you just simplified the whole process thanks! Keep doing what you're doing
Many Thanks for your time and this helpful video. My roommates said Thermodynamics is hard. however, in 1h :18 min and 25 second. I understand the HARD THERMODYNAMICS. May my almighty God bless you and give more energy to pu on the Helpful videos like this one . Again, thank you so every much for time and Bless you hear.
I watched so many videos and looked up explanations on google to try to understand these topics but less than a couple minutes after watching your videos, everything just makes sense. You really break things down so simply. Thank you!! D:
After this course unit and the results are out I will send this video to my lecturer to see how things are supposed to be done and explained not just to brag around. Thank you Sir
First of all, WOW!! So helpful! I'm a little confused about the ideal gas problem - So in my ChemE thermo class we talk about the entropy change of an ideal gas as delta S = integral of Cp*dT/T - ln(P/P0)*R. Now this would equal zero for a reversible process, but nowhere in the problem does this say that it is reversible and the only ispentropic processes are reversible and adiabatic. I'm not sure what to think because your reasoning makes sense here but I'm sure if you have an irreversible adiabatic process there's an entropy change, as all irreversible processes have entropy changes. This is quite a thinker...
Hello... sir... Really really really.. Your videos are awesome.. I loved it, the way of your explanations.. Like a practical one.. Its amazing.. I dont want to memorize any formule after watching your videos. the thermodynamics and HMT is the most dangerous subjects in Mechanical Engineering.. But you made that things very easy for me..
How to solve this?👇 indoor heater operating on the Carnot cycle is warming the house up at a rate of 30 kJ/s to maintain the indoor temperature at 72 ºF. What is the power operating the heater if the outdoor temperature is 30 ºF?
There are different sign conventions. The heat engine sign convention assigns work as positive when the system provides the work, and heat as positive when it is added to the system.
what is meant by a jet engine cycle? Is that a measurement over time? by the same token, does a typical reciprocating or piston engine cycle refer to a single intake combustion exhaust cycle? please advise if you know
one question 1:10:00 , isn't the net change in entropy of a heat engine affected by the work done by the engine? Is there a differnce between a carnot engine and a regular heat engine?
For temperature differences and weighted averaging, you don't need to convert to Kelvin. You ultimately need Kelvin before you plug it in to the rest of the equation, but it isn't necessary to convert in advance of averaging. (T1 + T2)/2 + K will give the same outcome as: (T1 + K + T2 + K)/2 Where the two T's give temperature in Celsius, and the K is the Celsius to Kelvin conversion adder of 273.15 Kelvin.
@The Organic Chemistry Tutor Hello Sir, I am a little bit confused at 25:11 min (Carnot engine). You said heat is absorbed here and every time gas expands the engine does work hence Work is positive. But in your Internal Energy you said system does work so work is negative. and work is done on system, work is positive. I am finding these two contradicting and I am confused. This is what I think when you talking about work in the Cornot engine, Please correct me if I am correct on these two concepts. W= -PdeltaV. This formula is relative to the Work of the system not the surrounding right? In the Carnot engine, when you mentioned Work is positive when gas expands, you are talking about the work of the surrounding system not the work that the engine gains from the surrounding system right? and when the gas compress you said work is negative, you mean the work of the surrounding is negative? Please help me clarify. Thank you very much, and I am highly appreciate your time.
I think in this video he’s using W(by system)=P*dV as physicists use, and that's what you use with the graphs because you have P on y axis and V on x axis. Which would mean when gas expands, work done by the system is positive. So when he says work is positive, he means work done by the system, or as you say "work of the surrounding system" or work gained by the surrounding. If he said work is negative ("But in your Internal Energy you said system does work so work is negative. and work is done on system, work is positive"), that would mean either he meant when work is done by system (e.g expansion), work done on the system is negative. Or he was using the chemistry convention W(by system) = -P*dV. (Chemistry convention). In chemistry, it's the opposite, when gas expands, work done by system is negative. But work done on the system is positive.
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this vid and the one about PV diagrams and internal energy (about 4h long) summed up my entire thermodynamics in physics degree
im so glad this vid exists
I'm confused, I am given to study thermodynamics as in chemistry and everyone is saying its physics tf?
@@ahmadsleiman37 Probably thinking of thermochemistry. If not, chemistry and physics do tend to have many overlaps in some areas so im not too surprised.
@@ahmadsleiman37 u teach thermodynamics?
thats a very simple and light thermodynamics mod you have there then
@@ahmadsleiman37 in my classes, thermodynamics is in both subjects.
messy room is the best analogy I have heard for entropy 10/10 stars!
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thank you so much! with your videos I'm learning more than I have ever learned at school! i started to understand physics normally, all with the help of your explanation.
Absolute king, all your videos are so helpful! The lecture notes on thermodynamics were hard to understand but you just simplified the whole process thanks! Keep doing what you're doing
This topic is very hard to me.. How u can help me...thermodynamic.. Come on In my whatsapp through this number +255779563519
Many Thanks for your time and this helpful video. My roommates said Thermodynamics is hard. however, in 1h :18 min and 25 second. I understand the HARD THERMODYNAMICS. May my almighty God bless you and give more energy to pu on the Helpful videos like this one . Again, thank you so every much for time and Bless you hear.
You didn't really understand it but whatever
I watched so many videos and looked up explanations on google to try to understand these topics but less than a couple minutes after watching your videos, everything just makes sense. You really break things down so simply. Thank you!! D:
as jee aspiring student i find it quite simple solving sum before you did it is good for understanding the concept
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Entropy starts at 56:17
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After this course unit and the results are out I will send this video to my lecturer to see how things are supposed to be done and explained not just to brag around. Thank you Sir
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First of all, WOW!! So helpful! I'm a little confused about the ideal gas problem - So in my ChemE thermo class we talk about the entropy change of an ideal gas as delta S = integral of Cp*dT/T - ln(P/P0)*R. Now this would equal zero for a reversible process, but nowhere in the problem does this say that it is reversible and the only ispentropic processes are reversible and adiabatic. I'm not sure what to think because your reasoning makes sense here but I'm sure if you have an irreversible adiabatic process there's an entropy change, as all irreversible processes have entropy changes. This is quite a thinker...
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Hello... sir... Really really really.. Your videos are awesome.. I loved it, the way of your explanations.. Like a practical one.. Its amazing.. I dont want to memorize any formule after watching your videos. the thermodynamics and HMT is the most dangerous subjects in Mechanical Engineering.. But you made that things very easy for me..
true bro
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How to solve this?👇
indoor heater operating on the Carnot cycle is warming the house up at a rate of 30 kJ/s to maintain the indoor temperature at 72 ºF. What is the power operating the heater if the outdoor temperature is 30 ºF?
Really really nice vids my dude, thanks man
Thanks
Thank you very much. I got better knowledge form that video. again thank you very much
When work is done on the system, to compress the gas, the work is positive because it is added into the system.
There are different sign conventions. The heat engine sign convention assigns work as positive when the system provides the work, and heat as positive when it is added to the system.
You are a legend! Thanks man
great work
thank you so much man
This is Amazing! What’s the difference between Ql and Qc please?
Ql means heat LOST , Qc means heat from the COLD reservoir or to the COLD reservoir
Lmk if u understand
In 19:19, why the unit is J?
Thank you very much. Your video help me and save a lot of my time.
what is meant by a jet engine cycle? Is that a measurement over time? by the same token, does a typical reciprocating or piston engine cycle refer to a single intake combustion exhaust cycle? please advise if you know
Thank you a lot sir
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Great video, but I'm a bit confused at 19:14 . It's 154 kW so shouldn't the answer be 13.3 GW rather than MW?
Yeah, it should.
Yes, you are right the answer should be given in Kj's.
yup! Or 1.33*10^10 J
one question 1:10:00 , isn't the net change in entropy of a heat engine affected by the work done by the engine? Is there a differnce between a carnot engine and a regular heat engine?
Thankyou Sir!
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I recommend watching this at x1.5 speed
Very helpful!!! thanks a ton
1 ton= 1000kg.
thanks 1000kg.
@19:19, is that Joules or is it supposed to be KJ since we were dealing with KW?
Yeah I think it should be KJ
thank u so much sir, it is really helpful......
Thank you for this ❤️
1:13:06 Shouldn't you convert to Kelvin first, and then take the average? 323K vs 338K
For temperature differences and weighted averaging, you don't need to convert to Kelvin. You ultimately need Kelvin before you plug it in to the rest of the equation, but it isn't necessary to convert in advance of averaging.
(T1 + T2)/2 + K
will give the same outcome as:
(T1 + K + T2 + K)/2
Where the two T's give temperature in Celsius, and the K is the Celsius to Kelvin conversion adder of 273.15 Kelvin.
@The Organic Chemistry Tutor
Hello Sir, I am a little bit confused at 25:11 min (Carnot engine). You said heat is absorbed here and every time gas expands the engine does work hence Work is positive. But in your Internal Energy you said system does work so work is negative. and work is done on system, work is positive. I am finding these two contradicting and I am confused. This is what I think when you talking about work in the Cornot engine, Please correct me if I am correct on these two concepts.
W= -PdeltaV. This formula is relative to the Work of the system not the surrounding right?
In the Carnot engine, when you mentioned Work is positive when gas expands, you are talking about the work of the surrounding system not the work that the engine gains from the surrounding system right? and when the gas compress you said work is negative, you mean the work of the surrounding is negative?
Please help me clarify. Thank you very much, and I am highly appreciate your time.
I think in this video he’s using W(by system)=P*dV as physicists use, and that's what you use with the graphs because you have P on y axis and V on x axis. Which would mean when gas expands, work done by the system is positive. So when he says work is positive, he means work done by the system, or as you say "work of the surrounding system" or work gained by the surrounding.
If he said work is negative ("But in your Internal Energy you said system does work so work is negative. and work is done on system, work is positive"), that would mean either he meant when work is done by system (e.g expansion), work done on the system is negative. Or he was using the chemistry convention W(by system) = -P*dV. (Chemistry convention). In chemistry, it's the opposite, when gas expands, work done by system is negative. But work done on the system is positive.
at 19:20, werent we suppossed to write the answer in KJ??