In last question our approach could be:- C -(5,7,9) for that, S should be no. such that after addition it must not give carry because (S+9+1(for carry)=A) this will lead S==A. So S=2,3 but (S+9)=A, where A can't be 1 therefore. S=3, A=2, R=8 :-)
Mam, h can be 0 also... If value of y is less than 8 then if carry is added then we will get value less than 10 and there will be no carry in next term i. e h..... But video was good I learn a lot from this.. Thank you
How did you decide that "H" have a carry in "THIS" in second question. There are S could be 2 and if "I" could be 2 then how "H" got carry? explain me .I am confuse.
because H is added to some thing to get E and after that T is added to something to get and it's value be 9 so since t has a carry and H be 9 then T = 8
Thank u mam due to this vedio I'm able to do and get answers Of even CAT level problems also easier. Ur way of explaining is very nice Mam💕💕💕. Please upload more vedios of different aptitude questions Which are appeared in placements tests with their tricks.
Mam, you have told that rule2 is by adding two odd or two even numbers result an even number but if there is a carry then the result will be odd . So can you please explain clearly.
We know that u has a carry and it is assigned.to 0 and it would be same alphabet as u but when we assigned to carry as 1 and it would be different alphabet like e , so if we has a value of 1 to 8 we do not get the value of 10 suppose 1+8 =9 and 1+7 =8 we don't get carry because it is single digit and when we add 1+9 = 10 so we get 10 and this 1 is a carry and it is assigned to p alphabet and remaining value 0 is assigned to e alphabet and 9 is assigned to u alphabet I think I am assuming like this ..
no, R+A=6+4=0 with carry 1. now for S you assumed 3, so 3+3=6+1(carry)=7, so c=7. now S+9=3+9=2 with carry 1, here A is coming as 2, while previously we assumed it 4, that's contradiction, so your assumption is wrong
Q3- YOUR+YOU=HEART, thats even true in real life for you!
In last question our approach could be:- C -(5,7,9) for that, S should be no. such that after addition it must not give carry because (S+9+1(for carry)=A) this will lead S==A. So S=2,3 but (S+9)=A, where A can't be 1 therefore. S=3, A=2, R=8
:-)
Thank a lot ..I learned this just because of you
Very useful video..
Thank you mam..!!
mujhe smjh nhi aaya
Mam, h can be 0 also... If value of y is less than 8 then if carry is added then we will get value less than 10 and there will be no carry in next term i. e h..... But video was good I learn a lot from this.. Thank you
Q3 why does the line 9+4 could not have carry
THANKS MAM. AWESOME VIDEO
For last question we can also have
U-9,P-1,E-0,A-7,C-3,S-6. This is also possible
You forgot value of R
Wrong,, Because R + A (3+7)has to give 0 , but the value of 3 is already repeated though C by the values
Oh tq
as u r saying tht take 2 digit number those numbers can be anything,for suppose 33+42=75,here i am not getting 3 digit number.
this was very helpful, thank you
Fantastic ⭐
in Q2 IS+THIS= HERE
IF I=5,S=9,H=7,R=1,E=8,T=6. With the help of this, answer is 74.
IS THIS CORRECT OR NOT ???
Tnk u..mam...very helpful
How did you decide that "H" have a carry in "THIS" in second question. There are S could be 2 and if "I" could be 2 then how "H" got carry?
explain me .I am confuse.
because H is added to some thing to get E and after that T is added to something to get and it's value be 9 so
since t has a carry and H be 9 then T = 8
VIT attendence check •
Mam please tell me why h is not taken 0
Mistake in the Q3: y ka value 9 tha upar me 1 likhi :-/
1 was carry,the value of Y was 9
Thank u mam due to this vedio
I'm able to do and get answers
Of even CAT level problems also easier.
Ur way of explaining is very nice
Mam💕💕💕.
Please upload more vedios of different aptitude questions
Which are appeared in placements tests with their tricks.
Glad to hear that
mam,,I didn't understood the last problem...can u explain me again??
You can substitute any values, based on the options given u have to choose right answer
Hi mam, for 2nd problem the ans will be 72 instead of 157. Please let me know if I am wrong. Thank you.
157 is correct,apply bodmas rule
Why we taken 10
Thanks
I'm not getting anything
Mam, you have told that rule2 is by adding two odd or two even numbers result an even number but if there is a carry then the result will be odd . So can you please explain clearly.
2+2=4 also 3+3=6 both 4 and 6 are even..... but if there is a carry 1+2+2=5 and 1+3+3=7 ..5 and 7 are odd. S+S=even but S+S+1=odd.
Mam in last promblem how can one predict E to be 0 ?
We know that u has a carry and it is assigned.to 0 and it would be same alphabet as u but when we assigned to carry as 1 and it would be different alphabet like e , so if we has a value of 1 to 8 we do not get the value of 10 suppose 1+8 =9 and 1+7 =8 we don't get carry because it is single digit and when we add 1+9 = 10 so we get 10 and this 1 is a carry and it is assigned to p alphabet and remaining value 0 is assigned to e alphabet and 9 is assigned to u alphabet I think I am assuming like this ..
For last prblm when we put R - 6, A - 4 S- 3 we are getting the same answer but how???
no, R+A=6+4=0 with carry 1. now for S you assumed 3, so 3+3=6+1(carry)=7, so c=7. now S+9=3+9=2 with carry 1, here A is coming as 2, while previously we assumed it 4, that's contradiction, so your assumption is wrong
arre madam ji .. aakhri problem mei itna gabhra kyu gayi miss
Hey i couldn't understand anything 😑
She is too fast 😂
ur fault y ka value 9 tha upar me 1 likhi