You don't need to assume that d & e are 7,5 they can only be that value as only e+1=n and if you take the other two it becomes e+1=d which is not possible. Thank you for the video. You explained it perfectly.
hi...yess you can consider that as well. There can be multiple solutions to a Crypt arithmetic problems. if you take S as 8, the other values will change accordingly.
carry will never be more than 1 ,, you can assume any no i mean two larger no like 9274+8651,, not to forget 1 no will be assigned to only one alphabet
u hv put in effort in explaining....well done.👍 u are extremely clear & loud enough...too It seems u hv uploaded just a couple of videos... if possible please..do upload many more. ur a good tutor.
Sir, it will be a big advantage to lots of people if you work and prepare tutorials on Java, C++ Programming & Operating System as it will help a millions of people to get the proper knowledge without wasting time on searching valuable tutorials on youtube. Missing your lectures:) One of the amazing lecture was on STACK & LINKED LIST(ANAND ACADEMY, THANE) God Bless..
HI can u make a video on this ones solution please? Here's a famous old math puzzle: the "college student" puzzle. A student sends home an addition problem, written out in letters: S E N D + M O R E ______________ M O N E Y Each of the 8 distinct letters in the puzzle represents a distinct digit from 0 to 9. (For example, if "M" means "5", then no other letter can mean "5".) Suppose you were to try an exhaustive search for solutions to this puzzle, trying out every possible assignment of digits for the eight letters. How many possibilities would you have
For those saying s can be 8: No, it cant be, since we already know for sure that M is 1. so if u take S=8 assuming that carry on S,1+8+1=11, would also generate a carry but in this case O would have 1 which is not possible since M is already 1 and no different digits can have same value, hence S=9.
Assalamuailkum bhaijaan, your explanation is very nice but,one thing to be noticed is that addition is always done from the units place and u started it from the highest place value.As the case is of assigning values so it may or may not can be considered as a mistake but if undertaken it would be easy to understand for us.
A - 1 J - 8 P - 7 U - 5 R - 0 N - 3 L - 6 I - 9 E - 4 Y - 2 Just by using l = i - n and e + y = l (as i - n = e + y), you can get the answer. Hope you find it helpful :P
intakhab Ali hi... we solved the two expressions in the previous steps and then got the value 8. we were not looking for combinations, we solved the expressions and answer was 8.
Hi Sir in Step 2 u kept s=9 if we use s=8 and got a carry from the e+0=n part of the problem then how can s=9 so if i get a carry from e+0=N then O can be 1 i didnt get solution for this anywhere please
@@prasanthreddy.2327 yes check, if you take S as 8, you'll take E as 9. And O is 0. Then 9+0 is 9 that's N, impossible. And if a carry over 9+0+1 again 0 which is again not possible. I hope you get that
my complete AI course www.junkminds.com/home/course/artificial-intelligence/66
First column: "Never ever forget the possibility of having a carry"
Second column: [Forgets the possibility of having a carry] ❤
You don't need to assume that d & e are 7,5 they can only be that value as only e+1=n and if you take the other two it becomes e+1=d which is not possible. Thank you for the video. You explained it perfectly.
without being on camera ....
the most simple and amazing video i found for the Crypt arithmetic problem.
ThankU
Ankit Gupta thank you
Luckily found this video. AI topics really need such explanations. Thank you!
How can you take the value of S to be 9. It can also have the value of 8 if it has a carry. 8+1+1(carry)=10
hi...yess you can consider that as well. There can be multiple solutions to a Crypt arithmetic problems. if you take S as 8, the other values will change accordingly.
carry will never be more than 1 ,, you can assume any no i mean two larger no like 9274+8651,, not to forget 1 no will be assigned to only one alphabet
1+8+1 is 10 and not 11.. so it is possible that S is equal to 8
even I also have the same doubt that s can be 8 or 9.
so Mr. junaid can you please explain what if we consider s as 8.
Mr. Junaid can you please explain by considering s as 8.
In the beginning, why have you not considered carry (+1) while adding S+M ?
because he already know the solution :'(
Wow just explored a new area of problems
Very interesting!!!!!!!!!!
Enjoy !!
the best explanation on the whole internet!
I really hope so
finally found the best explanation video, Thank you sir!!
Verrrrrrrryyyyyyyyyyy muchhhh thinkinggg required........Good explanation........thanks a lot :-)
Excellent explanation. Thank you!
u hv put in effort in explaining....well done.👍
u are extremely clear & loud enough...too
It seems u hv uploaded just a couple of videos... if possible please..do upload many more. ur a good tutor.
Crystal Henriques thank you for ur appreciation...Will surely upload more.
Thank you for your kind words, many more coming soon !!!!
Hopefully in this video there r no more trial and error method 😵😵🙏🙏🙏...tqsm sir
9:16 if dont consider carry we it has to be 9. this line is confusing. 8 also generate carry if add with any of 7 6 5 4 3 2
SIR, YOU ARE THE BEST!
Nice explanation..sir..
All the best..
Sir, it will be a big advantage to lots of people if you work and prepare tutorials on Java, C++ Programming & Operating System as it will help a millions of people to get the proper knowledge without wasting time on searching valuable tutorials on youtube.
Missing your lectures:) One of the amazing lecture was on STACK & LINKED LIST(ANAND ACADEMY, THANE)
God Bless..
thank you sir,,
please upload more problems like this 👏
Finally some logical explanation i found .
Thank you !
Hello, Can you please explain how N + R = E + 10? RHS adding 10 is not clear
Yeah felt the same, and very doubtful about the (+1) there, which brings the value to 8.
Thanks. Precise and clear.
tq sir for your clear explanation
Thanks lot for neat explanation !
Thanks. Very well explained
Mandar Dandekar : thank you
Tq for the explanation,but I have a small doubt while adding s and m why have you not considered a carry from its before I.e(E+O)
he should have considered it and then explained the elimination…refer to this video instead
th-cam.com/video/p5YjV-100Hc/w-d-xo.html
dannng , one hour before.
beautifully explained. thank you ! :))
same
HI can u make a video on this ones solution please?
Here's a famous old math puzzle: the "college student" puzzle. A student sends home an addition problem, written out in letters:
S E N D
+ M O R E
______________
M O N E Y
Each of the 8 distinct letters in the puzzle represents a distinct digit from 0 to 9. (For example, if "M" means "5", then no other letter can mean "5".)
Suppose you were to try an exhaustive search for solutions to this puzzle, trying out every possible assignment of digits for the eight letters. How many possibilities would you have
Thank you sir for helping us all😀😀👍👍
Why didn't we consider a carry in last column? In C3
Nice explanation 👍👍
S+M+1 carry can also be a condition??
thanks a lot....very informative..
thank you
Awesome explaination sir
What if the result is not have a carry?
I mean if I take two addends are 4 in size and result also 4 in size
Very good explanation
Thank you
Thank you so much sir👍🏻👍🏻
how E+10 came any one can explain?
nice video helped me a lot
For those saying s can be 8: No, it cant be, since we already know for sure that M is 1. so if u take S=8 assuming that carry on S,1+8+1=11, would also generate a carry but in this case O would have 1 which is not possible since M is already 1 and no different digits can have same value, hence S=9.
1+8+1=11 how ??? i don't get it...
@@DivyanshuSingh269 there's 1 as carry on S bro.
1+8+1=10 ?
scientist.
Assalamuailkum bhaijaan, your explanation is very nice but,one thing to be noticed is that addition is always done from the units place and u started it from the highest place value.As the case is of assigning values so it may or may not can be considered as a mistake but if undertaken it would be easy to understand for us.
why didnt you considered E+O with carry
th-cam.com/video/p5YjV-100Hc/w-d-xo.html
Give the explanation of BASE BALL GAMES...make a video
i got a different answer , but my arithmetic is correct,does it have to be the same answer?
hey..you can get different answers...its possible!!
Thank you so much 🥰
Finally got it, tqu sir🙂
Can i get programming part of this problem?
Why can't we take s=8 and put a carry 1 on the top of it
You need logic to do it
th-cam.com/video/p5YjV-100Hc/w-d-xo.html
Your voice is so good
Or bhi video send-money per h kya ye question imp h
Dedicated person! Keep up :)
Sir can you please upload the Prolog code for cryptarithmetic problem. Pleaseee
Does one question have only one solution?
No, there can be multiple solutions.
sry could not get complex method .
Please solve this cariptarithms:- June + july = april how
A - 1
J - 8
P - 7
U - 5
R - 0
N - 3
L - 6
I - 9
E - 4
Y - 2
Just by using l = i - n and e + y = l (as i - n = e + y), you can get the answer. Hope you find it helpful :P
Sir it is possible to get different answers in same cryptarithmatic questions
shivam gupta yes it is possible.
in step 5 : 6+7 = 13 is also possible why not u have taken that?
intakhab Ali
hi... we solved the two expressions in the previous steps and then got the value 8. we were not looking for combinations, we solved the expressions and answer was 8.
sry for typing mistake
i am say that value of D and E may be 6 and 7 and the sum is 13
Thanks!
Thank you so much
Appreciate !!!!!
Very helpful👌
Hi Sir
in Step 2
u kept s=9
if we use s=8 and got a carry from the e+0=n part of the problem
then how can s=9
so if i get a carry from e+0=N
then O can be 1
i didnt get solution for this anywhere
please
important here is that m=1 and there can't be 2 letters having the same value
so since we already concluded that m has to be 1, o can't be 1
I've done this whole logically
th-cam.com/video/p5YjV-100Hc/w-d-xo.html
best video
Hey man, great explanation!
nice explained
Thank u soooo much
Knowledge representation pe bna do video pkz
thank you sir
why M can't be zero
A number can never start with 0....eg- 012 acn't be a 3 digit number...
Anyone please solve india+pak=peace
yes.www.imagebanana.com/s/1911/h9GpX86Q.html
Thank you !! :))
Well, now find all the solutions of SEND + LESS = MONEY, please.
more than 80 www.imagebanana.com/s/1911/K4r3mxd4.html
base+ball=games :
7483+7455 =14938
perfect !!!
:D why I always must get this easy homeworks :D :D
super sir
Your accent is too asiatic, dude. Good problem👍🏼
Amazing
thank you
6+8=14 not 15 so E=5
its also getting carry from the previous evaluation D+E = 12 so 6+8+1 = 15
👏👏👏
I I T problem
👍
fyi this is a unique solution
:):) thanks
Why are u rushing man
Yem ardham kavatam ledhu
I know for sure that these kinds of comment are not considered but for brotherly advise please consider it and reply.
Thank you Khuda hafiz::))
You have no credibility, as you did not consider S=8 with a carry in. 1+8+1=10
You cannot take S as 8.
@@Chocopie9701 how can we know that before solving....that means we should check all the possibilities right?
@@prasanthreddy.2327 yes check, if you take S as 8, you'll take E as 9. And O is 0. Then 9+0 is 9 that's N, impossible. And if a carry over 9+0+1 again 0 which is again not possible. I hope you get that
@@Chocopie9701 yeah but this thing should have been explained in the video ig...anyways helpful video👍
Carry yyy 😂😂😂😂 lol admi
farigh
lol 69 dislikes