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4^n = nn lg(4) = lg(n)2n lg(2) = lg(n)2 lg(2) = lg(n) / n
Pls sir how would I know that I have to start with logs Iln etc before I tackle as you quickly applied Iln.
4^n = n
n lg(4) = lg(n)
2n lg(2) = lg(n)
2 lg(2) = lg(n) / n
Pls sir how would I know that I have to start with logs Iln etc before I tackle as you quickly applied Iln.