I've seen similar - lower amp draw with load. The resistor, in my experience, plays a key factor. The transistor's oscillation at the right voltage is agitating the electrostatic environment, and the load places greater stress on the resistor to behave as an entry point for ambient charge. It's very counter-intuitive, because in a sense, the resistor behaves more like a diode with respect to (bringing in charge from) the electrostatic environment. Thanks for sharing this.
That is a new way of explaining this lower amp draw . Lowering the resistance increased the difference in amp draw . Thank You , i like input i can think about .
@@hydniq3327 Glad to be part of this important conversation. As I said, it's counter-intuitive, but once you grasp what's going on, it opens up one's understanding of what constitutes an "open system." Our electrical/electronic world view, so-to-speak, is built on closed system electrodynamics. Classical closed system thinking would suggest the 5W resistor is excessively high for this setup (- a line of thinking valid perhaps, within its own paradigm). However, I prefer to think of it (the resistor) as a mediator thru which the dielectric or electrostatic medium is stressed, and in a moment of temporary imbalance, pushes charge back into the circuit via the resistor's interaction between circuit and ambient charge. Bearden, Stiffler, Don Smith and others all seem to refer to this dynamic in their own words and/or demonstrations.
@@BobSmith-vq3uo Your always welcome to share your views on this subject . I have been thinking of the "open system." To do with the dielectric stress i think that might be happening in the coils where the inductance and capacitance is . Thank you for your input .
I've seen similar - lower amp draw with load. The resistor, in my experience, plays a key factor. The transistor's oscillation at the right voltage is agitating the electrostatic environment, and the load places greater stress on the resistor to behave as an entry point for ambient charge. It's very counter-intuitive, because in a sense, the resistor behaves more like a diode with respect to (bringing in charge from) the electrostatic environment. Thanks for sharing this.
That is a new way of explaining this lower amp draw . Lowering the resistance increased the difference in amp draw . Thank You , i like input i can think about .
@@hydniq3327 Glad to be part of this important conversation. As I said, it's counter-intuitive, but once you grasp what's going on, it opens up one's understanding of what constitutes an "open system." Our electrical/electronic world view, so-to-speak, is built on closed system electrodynamics. Classical closed system thinking would suggest the 5W resistor is excessively high for this setup (- a line of thinking valid perhaps, within its own paradigm). However, I prefer to think of it (the resistor) as a mediator thru which the dielectric or electrostatic medium is stressed, and in a moment of temporary imbalance, pushes charge back into the circuit via the resistor's interaction between circuit and ambient charge.
Bearden, Stiffler, Don Smith and others all seem to refer to this dynamic in their own words and/or demonstrations.
@@BobSmith-vq3uo Your always welcome to share your views on this subject . I have been thinking of the "open system." To do with the dielectric stress i think that might be happening in the coils where the inductance and capacitance is . Thank you for your input .
All I can see is junk, and your explanation is not describing the circuit.
So comment would be speculative at best...