RC Circuits, Charging Capacitors and Equation Derivations

[@philbarclay808]

It has been some time since this has been posted, but encountering it now has proven very useful. Thank you for the detailed explanation and the method of presentation.

[@JitinPillaig3]

A fabulous lecture, in which each and every step is clearly explained.........
Extremely understandable content, short and sweet.......
And a special "Hats Off" for the awesome handwriting and graphs...

[@AKLECTURES]

Jitin Pillai Thank you for the positive feedback! :)

[@rodericksibelius8472]

Now a more advanced form is using Laplace Transforms. Awesome Teaching.

[@abady50501]

Thank you it was helpful
But at 5:29 I think it should be RC

[@AKLECTURES]

Yes, you're right. When I multiplied both sides by C, forget to stick that C in there. Thanks.

[@VireakYuth]

AK LECTURES thank u...I thought I was wrong.

[@nansisahu1568]

waooo sir... honestly you areee great ...

[@frankreiserm.s.8039]

EXACTLY HOW MANY DEGREES DO YOU HAVE?

[@zkhan2023]

Thanks sir for this derivation.

[@ibraheemnadeem9179]

AMAZING VIDEO!! Thank You soo much

[@yovkorakanov6350]

6:23 can you explain please why is -ln? not +ln

[@yovkorakanov6350]

I think is it multiplied by (-1) due to d(-Q) right?

[@MrCapetanios]

the electron motion is the opposite than the current motion we chose in the previous exercises right?

[@nirolf12]

Thank you, really useful!

[@RaydinAE11]

what about parallel RC circuits?

[@renzg6887]

Ey thank you so muchhhhh

[@Thepankaz1]

There is a mistake
VC-Q=(dQ/dt)R on upper left corner should be VC-Q=(dQ/dt)CR

[@goldfishios5318]

Pankaj kumar upper left? lol

[@zmaska]

props

[@AKLECTURES]

PRAlea PTMProducts Thanks :)