Man, you are good at this. I couldn't get over how well you can write backwards.. OR your magic trick for however you did that. Thanks for your content. Big help.
This comment is for anyone using the CSA Exam Prep app, yes indeed they app get the sizing wrong because it bases its calculation off the splitter ampacity, not the conductor supplying it.(Question ID 1510) I believe Zack's interpretation is correct.
@@ZackHartle Seems like it to me, but I'm jsut an apprentice. The app fails to use to conductor sized for the splitter and rather uses the splitter ampacity. Sorry about the ambiguity, I'll reword my comment.
Dear Zack, thank you for such a nice videos. I have a question: How an overcurrent device which is set more than an ampacity of a wire can protect the wire? Please let me know . Additionally, why didn't you use 80% equipment rated as in question doesn't mentioned it is continuous or non-continuous? Thx in advance.
It would just be the maximum size permitted by the CE code. I have a few videos on OC sizing. th-cam.com/video/Ur-7OO43WPg/w-d-xo.html th-cam.com/video/XKiS-tjeSpU/w-d-xo.html
@@ZackHartle If the breaker is only rated for 70 A, shouldn't the downstream wire meet or exceed that rating too? For example if the 60 A load was defective and drew more than expected, wouldn't the wire melt before the breaker could protect it?
@@ihategoogleplus490 It could, but the CE code does allow you in certain situations to have an overcurrent larger than the wire. I have a few conductor sizing videos that cover this a bit
@@ZackHartle Yes, sorry just saw your linked video. It points to Table 13 which says for conductor ampacity of 61-70 A, a 70 A breaker is permitted. In this case for 65 A a 70 A breaker is permitted. Sorry for the confusion!
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Man, you are good at this. I couldn't get over how well you can write backwards.. OR your magic trick for however you did that. Thanks for your content. Big help.
Thanks a bunch for simplifying this code requirement. Please do more videos, especially voltage drop based on new math in CEC2024
I felt really overwhelmed by the wording of all of this in class. I was so relieved when I found your video! Thank you!
Glad it was helpful!
Great video! Thanks for breaking this down, I’m in tradeschool and this helped me a lot in my code class.
better taught than a 4 hour "lecture"... thank you so much
Glad it was helpful!
easy to understand great explanations right on point thanks for your effort
Thanks brother, you’re the man!!👍
Exactly, that is what I need. Thank you very much!😄
You're very welcome. Thanks for watching!
This comment is for anyone using the CSA Exam Prep app, yes indeed they app get the sizing wrong because it bases its calculation off the splitter ampacity, not the conductor supplying it.(Question ID 1510)
I believe Zack's interpretation is correct.
But you're saying this video is correct?
@@ZackHartle Seems like it to me, but I'm jsut an apprentice. The app fails to use to conductor sized for the splitter and rather uses the splitter ampacity. Sorry about the ambiguity, I'll reword my comment.
The Goat
Dear Zack, thank you for such a nice videos.
I have a question:
How an overcurrent device which is set more than an ampacity of a wire can protect the wire?
Please let me know .
Additionally, why didn't you use 80% equipment rated as in question doesn't mentioned it is continuous or non-continuous?
Thx in advance.
How does this rule apply if we are feeding the splitter with parallel conductors?
How was the max 70 amp OCPD determined for the first tap example?
If you know the loads, how do you size the feeders to the splitter?
Do these calculations still hold up today?
aaaaaaaaand ... SUBSCRIBED!
Excellent! Thanks for watching!
As you said in countinious brach circuit, we need to divide load amp by 0.8 and then use table2. But you didn't in this example. Can I ask why?
I guess I am treating all these as Non-continous loads. I should have been more clear
What if your equipment was temp specified at 60/75 degrees? but still feeding a load less then 100AMP ?
thank you in advance
Then you just make sure you use the appropriate column in Table 2 or 4 when sizing your conductor.
Hi, why overcurrent is 70A? Thanks.
It would just be the maximum size permitted by the CE code. I have a few videos on OC sizing.
th-cam.com/video/Ur-7OO43WPg/w-d-xo.html
th-cam.com/video/XKiS-tjeSpU/w-d-xo.html
@@ZackHartle If the breaker is only rated for 70 A, shouldn't the downstream wire meet or exceed that rating too? For example if the 60 A load was defective and drew more than expected, wouldn't the wire melt before the breaker could protect it?
@@ihategoogleplus490 It could, but the CE code does allow you in certain situations to have an overcurrent larger than the wire.
I have a few conductor sizing videos that cover this a bit
@@ZackHartle Yes, sorry just saw your linked video. It points to Table 13 which says for conductor ampacity of 61-70 A, a 70 A breaker is permitted. In this case for 65 A a 70 A breaker is permitted. Sorry for the confusion!