JEE advanced: AB=6 , BC =2 and r = 5 sqrt(2) cm then find OB where O is the centre of the circle.

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  • เผยแพร่เมื่อ 6 ม.ค. 2025

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  • @Nalogpi
    @Nalogpi 2 วันที่ผ่านมา +1

    1) Extend AB to point D on circumference. Let BD = x
    2) Extend CB to point E on circumference. Let BE = y
    6x = 2y => 3x=y
    There is another rule in which if two chords of a circle divide each other in a circle and are perpendicular to each other then
    Let a,b,c, d be divided parts of the chord then
    Radius = sqrt( a^2+b^2+c^2+d^2)/2
    Here, sqrt( x^2+y^2+36+4) /2= 5sqrt2
    10x^2 = 160
    x^2 = 16=> x=4
    y=12
    Draw perpendicular from O to point G on chord CE
    CE = 7
    GB = 7- 2 = 5
    Using the same method OG = 1
    OB = sqrt( 1+25)
    OB = sqrt(26)

  • @akshat_jpeg
    @akshat_jpeg 2 วันที่ผ่านมา +1

    Thankyouuu sirr ❤❤