From the TISE in 3d to spherical harmonics

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  • เผยแพร่เมื่อ 27 ม.ค. 2025

ความคิดเห็น • 67

  • @DodoEmperor
    @DodoEmperor 7 ปีที่แล้ว +22

    I started today with a quantum intro course starting here. I got freaked out by this griffiths chapter. Some friend of mine recommended this to me but you solved essentially most questions that I had and in hindsight you made me understand previous parts better.
    Thanks man, it's very clear. Even clearer than griffiths himself and he is very clear

  • @MiguelGarcia-zx1qj
    @MiguelGarcia-zx1qj 3 ปีที่แล้ว +5

    38:25 an easier to read depiction of spherical harmonics can be obtained by using saturation instead of value of light for the magnitude of the functions. So, the highest magnitudes would be represented as fully saturated colours, and low magnitudes would appear as mostly white (instead of black). I devised such a scheme, around 23 years ago, in order to represent said harmonics upon a sphere.

  • @PankajBhambhani64
    @PankajBhambhani64 4 ปีที่แล้ว +11

    These videos are really Legendre-ary! Thank you for sharing these videos.

    • @dbf72829
      @dbf72829 2 ปีที่แล้ว +1

      😭🤣

  • @Gamma_Digamma
    @Gamma_Digamma 4 ปีที่แล้ว +4

    m and l are actually the quantum numbers where m is the magnetic quantum number giving the number of degenerate orbitals and l is the azimuthal quantum number giving which subshell were talking about (s, p, d or f)

  • @MarioRiveraS96
    @MarioRiveraS96 8 ปีที่แล้ว +7

    Thanks! You might have just saved my quantum mechanics course with this video!

  • @santosfuentes1519
    @santosfuentes1519 10 ปีที่แล้ว +29

    question: at 15:03 after you have divided out (- hbar squared RY over 2 m r squared) shouldn't r squared be canceled out? should you not have (1/R)dr(r^2dR) ? thanks!

    • @navneetmishra3208
      @navneetmishra3208 3 ปีที่แล้ว +3

      Yup

    • @kgfcccvvhbbbc7565
      @kgfcccvvhbbbc7565 3 ปีที่แล้ว +1

      @@navneetmishra3208 yes. No r squared. Teacher forget r squared. I forgive you.

  • @cosmicnomad8575
    @cosmicnomad8575 2 ปีที่แล้ว +2

    That was excellent! Well done! Such a beautiful concept in my opinion!

  • @KingCrocoduck
    @KingCrocoduck 10 ปีที่แล้ว +15

    Mistake at 14:17
    the r^2 term should have cancelled out

    • @KingCrocoduck
      @KingCrocoduck 10 ปีที่แล้ว +12

      nevertheless this video kicked ass

    • @MisterTutor2010
      @MisterTutor2010 10 ปีที่แล้ว +5

      King Crocoduck perhaps you can do a video giving a foul mouth explanation of the rigid rotator as you did with the harmonic oscillator :)

    • @matthewlemke5310
      @matthewlemke5310 5 ปีที่แล้ว +2

      @@MisterTutor2010 4 years ago you were triggered.

    • @MisterTutor2010
      @MisterTutor2010 5 ปีที่แล้ว +3

      @@matthewlemke5310 What are you talking about? That video was hilarious.

    • @ifrazali3052
      @ifrazali3052 6 หลายเดือนก่อน

      ​@@matthewlemke53109 years ago lol
      How are you guys holding up?

  • @SlySkills
    @SlySkills 6 ปีที่แล้ว +3

    Answers to your questions either in your video description or as a comment is the only thing these videos are missing to really check our understanding.
    Thank you so much for everything though. You've done more than enough and it's greatly appreciated.

    • @SlySkills
      @SlySkills 6 ปีที่แล้ว +2

      Attempted Answers:
      Find P(1,1) (cos(theta)) = sin(theta)
      P(7) = 0 at 7 different points
      P(4,7) = 0 at 3 different points - This one is pretty much a guess, not sure how to compute.
      m = -3 then l = 3, only allowed value

    • @BPHSadayappanAlagappan
      @BPHSadayappanAlagappan 3 ปีที่แล้ว

      Awesome 😎

    • @BPHSadayappanAlagappan
      @BPHSadayappanAlagappan 3 ปีที่แล้ว +1

      I think if M=-3, L can be greater than 3.

  • @clopensets6104
    @clopensets6104 4 ปีที่แล้ว

    I have been having trouble grasping the concept of spherical harmonics for days!!! My textbook didn't help in clarifying the mathematical details, as it mainly focused on the physical and experimental implications of mathematically predicted 'orbital configurations' (which were derived via spherical harmonics). This video helped clarify a lot of the mathematical components, which I was too lazy to research myself. THANKYOU FOR YOUR INSIGHTS!!

  • @fornasm
    @fornasm 2 หลายเดือนก่อน

    it might be worth to remind that: The problem with spherical co-ordinates (or any system of non-Cartesian co-ordinates) is that the direction from a point P
    along which one co-ordinate changes and the other two remain constant depends on the location of P
    . In Cartesian co-ordinates the directions and lengths of the basis vectors are independent of location. But if you are try to generalize this property of Cartesian co-ordinates to other co-ordinate systems it just does not hold.

  • @briannagopaul3493
    @briannagopaul3493 9 หลายเดือนก่อน

    Thank you for these lectures, these make so much more sense!!

  • @erikstephens6370
    @erikstephens6370 2 ปีที่แล้ว +1

    14:17 that term should be 1/R, not 1/Rr^2. The r's from the Y/r^2 and -h^2/2mr^2 cancel each other. Still, a great video.

  • @iqranasir9224
    @iqranasir9224 2 ปีที่แล้ว +2

    thank you for saving my semister 😍

  • @BLVGamingY
    @BLVGamingY 11 หลายเดือนก่อน

    why isn't at 22:30 the phi function an arbitrary sum of opposite exponentials as opposed to just one exponential
    nonetheless m ends up a whole number

  • @scitwi9164
    @scitwi9164 7 ปีที่แล้ว +2

    09:00 Are you sure about that? If the X part is a constant, then they Y+Z part is equal to the same constant with a negative sign. But X and Y can still change in various ways, just independent of x, right?

    • @clopensets6104
      @clopensets6104 4 ปีที่แล้ว

      What do you mean? The 2nd derivative of X multiplied by the inverse of X, is only equal to the negative of the sum of the 2nd derivatives of Y and Z respectively, each multiplied by their respective inverses, when the potential energy equals the energy eigenvalue.

  • @bakirev
    @bakirev 5 ปีที่แล้ว +1

    I didn't quite get the reasoning of spherical coordinates not being independent of each other which causes the laplacian to be complicated. It was that vector r changes if you change phi for example. But r is just the distance right not the vector?

  • @mojamamaduda
    @mojamamaduda 8 ปีที่แล้ว +5

    thanks for this video,you are a legend

  • @dm3248
    @dm3248 4 ปีที่แล้ว +1

    Thanks for such an amazing lecture..!!

  • @paladin1147
    @paladin1147 9 หลายเดือนก่อน

    Amazing, just check the comments for certain errors or keep the Griffiths book next to you to verify. Thank you for the video

  • @ameerbux78666
    @ameerbux78666 4 ปีที่แล้ว

    wow, only thing sad here is that ive only dicoverered this channel now. thanks for the vid, you explain great

  • @clopensets6104
    @clopensets6104 4 ปีที่แล้ว

    In 36:10 . Just out of curiosity, how do you get the normalisation factor from evaluating the double-integral underneath???

    • @movintarget300
      @movintarget300 4 ปีที่แล้ว

      It's the same as the normalisation integral for more familiar Cartesian coordinates, except we are now in spherical polar coordinates, so dxdydz -> r^2sin(theta)d(theta)d(phi)d(r). I think you can just grind through this by plugging in (Y*Y) . This may be done in more detail in Griffiths Intro or try googling Jain QM pdf and it's done in there.

  • @fornasm
    @fornasm 2 หลายเดือนก่อน

    unfortunately, this lecture does not even seem a lecture on physics ... I hope it comes in next lectures

  • @alexkumarsingh2805
    @alexkumarsingh2805 4 ปีที่แล้ว

    29:11
    0

  • @inperatieloos
    @inperatieloos 9 ปีที่แล้ว

    37:58 isn't it r^2*dr*sin([T])d[T]*d[F]?

    • @rap8209
      @rap8209 8 ปีที่แล้ว

      +inperatieloos I think d(Omega)=Sin(T)d(T)d(Phi) so here he integrated over omega, not considering radial part

  • @rajupdl6
    @rajupdl6 4 ปีที่แล้ว

    Awesome lecture 👍

  • @seacaptain72
    @seacaptain72 6 ปีที่แล้ว +2

    Is there somewhere I can find the solutions to the check your understanding questions at the end? I've done these on all the vids but haven't been able to check them

  • @takinyele
    @takinyele 9 ปีที่แล้ว +3

    Oh my god I love you so much

  • @إحساسفيزيائية
    @إحساسفيزيائية 4 ปีที่แล้ว +1

    Thanks 💜

  • @knowledgebankforfpscppscnt5486
    @knowledgebankforfpscppscnt5486 5 ปีที่แล้ว

    22:18 how

  • @hasnatahmad6164
    @hasnatahmad6164 4 ปีที่แล้ว

    one thing I didn't understand
    what are "pheeta" and "phi" here

    • @movintarget300
      @movintarget300 4 ปีที่แล้ว +2

      Solutions of the wavefunction in spherical polar coordinates split into the dependence on pheeeta and phii.
      Edit: you can also solve for the r dependence but is less important in angular momentum which is... well, angular.

  • @Salmanul_
    @Salmanul_ 4 ปีที่แล้ว

    Why spherical coordinates?

    • @HankGussman
      @HankGussman 4 ปีที่แล้ว

      Orbitals can be described in terms of spherical coordinates.

    • @jacobvandijk6525
      @jacobvandijk6525 ปีที่แล้ว

      Why do you describe your room with Cartesian coordinates? Because it is rectangular.
      Why do we describe the "room" of an electron with spherical coordinate? Because it is spherical (most of the time), they think.

  • @wonka5004
    @wonka5004 8 ปีที่แล้ว

    Great explanation 10/10

  • @Salmanul_
    @Salmanul_ 4 ปีที่แล้ว

    28:31, fractional derivatives exist so idk about that.

    • @shayanmoosavi9139
      @shayanmoosavi9139 3 ปีที่แล้ว +2

      If m is not an integer the phi dependence of the wave function won't be single valued and our boundary condition which is Φ(0)=Φ(2π) won't be satisfied.
      Also fractional derivatives are extremely advanced stuff. This is an *introduction* to quantum mechanics which is for undergraduates.
      I've found this article, I hope it answers your question :
      en.m.wikipedia.org/wiki/Fractional_Schr%C3%B6dinger_equation
      Although I haven't understood a single word😂😂

  • @rebekahshtayfman1967
    @rebekahshtayfman1967 7 ปีที่แล้ว +3

    I think you meant r^2*sin(theta)*dr*d(theta)*d(phi)
    at the 38 minute mark (approximately)
    By the way, thank you for the amazing videos. You're great!

  • @أزهارالحوامدة
    @أزهارالحوامدة 9 ปีที่แล้ว +1

    thank you

  • @fcmilsweeper9
    @fcmilsweeper9 9 ปีที่แล้ว

    Wait why do they have to be constant?

    • @Prometheus4096
      @Prometheus4096 9 ปีที่แล้ว

      +fcmilsweeper9
      Without context, I think in the case you think about both describe the energy of the same system.

  • @learningwithsaba6131
    @learningwithsaba6131 5 ปีที่แล้ว

    superb

  • @navneetmishra3208
    @navneetmishra3208 3 ปีที่แล้ว

    THANK YOU SO SO MUCH

  • @ZeroXAlAttas
    @ZeroXAlAttas 9 ปีที่แล้ว

    Wow, this really helps~~ thanks!! :))

  • @herman9737
    @herman9737 4 ปีที่แล้ว

    why cant weee just stick to cartesian.... jk spherical reveals nice intrinsic proterties of QM

  • @craigfowler7098
    @craigfowler7098 5 ปีที่แล้ว

    My brain hurts

  • @fornasm
    @fornasm 2 หลายเดือนก่อน

    I am sorry Prof. Carlson, I have appreciated your lectures so far because their math's treatment is clear and easy to follow. But now they are starting to luck with the important connection of math's to physics. After all this is a physics course, isn't it?! So why would one suddenly introduce spherical coordinates? At least it should have mentioned that major topic of original quantum mechanics was atomic physics and in atomics physics the "force" is central and 1/2 etc ... this is why it may be useful to introduce spherical harmonics: because the future "problems" you are going to treat are "atomic physics", correct?! Atomics physics has the peculiarity of introducing "symmetry" in the problems and this a rather important general problem in "physics" ... This is at least my opinion. If your share such opinion, don't you think it have been educative to remind that?! Otherwise, this course seems now turn into a math's course of solving partial derivative equations ... Many thanks

  • @MinuteMayne
    @MinuteMayne 6 ปีที่แล้ว +5

    Bruh the way you write partials is wildly distracting.

  • @Al-Qaisi_Iraqi
    @Al-Qaisi_Iraqi 6 หลายเดือนก่อน

    Thank you