Median and Quartiles from a Stem and Leaf Diagram

[@GenericUserUnknown]

Thank you for making this easy-to-follow video for all of us!

[@B.L.O.O.D.Y_H.E.L.L]

thank you.

[@louismapuranga3465]

thank u our teacher for yr tym cz u juc sacrificed yr tym for pple who do not even pay u ; anyway thank u for yr help

[@shailyy_.]

Thank you so freaking much! I always thought interquartile range in stem and leaf was the same as graphs, where Q1= (0.25)x n instead of 0.25n/4

[@pythonassignment]

5:18 ❤

[@samsonkparobor990]

Thank you

[@IanCrump-e2h]

Q2 = 0.5(n+1) will always work for the median. However, the formula, that you used for Q1 and Q3, will only work for when n is odd. It doesn't work for when n is even. For example, if n is 8, then using your method gives Q3 as the 6.75th value, which I presume you would take to be the 7th value ... whereas Q3 is in fact the value between the 6th and the 7th. For a specific example, Q3 for 1 , 3 , 5 , 5 , 6 , 7 , 10 , 10 would be 0.5(7+10) = 8.5, not 10 as your method would give.

[@funkohunteruk2847]

thanks for your help :)

[@kangietan1708]

Hi, I also use ur formula for IQR but I facing an issue here.
If I have 12 data, Q1 position is 3.25, so we take average of 3rd and 4th position. Q3 position is 9.75, we take average of 9th & 10th position
But if i have 10 data, Q1 position is 2.75, we take 3rd position and not average of 3rd & 4th. And Q3 position is 8.25 and we take 8th position and not average of 8th & 9th.
In short, I am stuck when I get .25 or .75. Can help? Thanks.

[@MrsCKirby-ho3yc]

For 12 items of data the median is average of 6 and 7. LQ is average of 3 and 4. Uq is average of 9 and 10.
For 10 items of data median is average of 5 and 6. LQ is data item 3 and UQ is data item 8.
Draw out 12 or 10 dots in a line. Mark the positions and you will be able to see this more clearly.
If you have 9 items of data the media is 5, LQ average of 2 and 3, UQ average of 7 and 8.