Capacitor Dropper Circuit | Transformerless Power Supply
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- เผยแพร่เมื่อ 27 ธ.ค. 2020
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Capacitor Dropper Circuit | Transformerless Power Supply
In this video we will calculate required capacitor value for a transformer-less power supply. watch the video till end do you don't miss any detail.
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Amazing video! Never have I seen such an easy-to-understand lecture!! Thanks!
Great to hear!
Perfectly described, no one shows like you. Always keep doing great.
Thanks
Simple calculations explained nicely. Thanks
I loved it. I never knew how to calculate values . Thanks to u
I like the way you present your videos it's clear and precise,I have trouble with math formulas you make it easier to grasp it better. Thank you.
It was great idea to check the voltages across diffrent sections .That gave a clear picture. Thanks .Stay 🙌
Thanks
Thanks for the video, Its really helpfull not just the theory but the practical testing good too.
Aap bahot badiya samjhate ho sir
Very useful description. Thank you.
Thank you for imparting this knowledge .
Very clear explanation of transformer less circuit designing video you have made. This is the one video wherein I could gather the information on taking the RMS voltage for designing the correct PS. Kudos.
Thanks 😊
I love this video and the explanation keep going . It’s very organised and clear . I am not indian and with the help of the subtitles I understood thank you for your time to add English subtitles
Thanks 😊
9
@@TEKNOISTIX Bhai can you explain with 110V AC input how thsi can be done to get 12v DC output
@@TEKNOISTIX how to contact or connect sir
Your explanation is very clear. And u born for the teaching. Good job keep it up. I am from Sri lanka
btw thanks for showing the calculations!!! helpful video!
👍🏻
Thanks for your knowledgeful video .
Thank God for closed captioning. I cant understand you but I learned ALOT! THANX!
You're welcome
Best electronics video I have come across
Thank you for the video!
your teaching method is excellent, thank you. 😀👍🌼
Thanks
Excellent presentation with proper clarifications makes a perfect project. Thank you very much.
Excellent solution, thank you best of luck.
Explained clearly, much informative
Thanks 😊
Very clear good teaching ability. Keep it up. I am from Sri lanka
Thanks for your clear explanation
Mantap thank you from indonesia
Very very good presentation good explain thanks
Sir, your way of explaining is having fully touch of an Engineer. You explain the things with theory and problem calculation and with reasoning which helps to understand the subject without any doubt. Thanks for your nice explanation.
Thank you sir for good explanation
Excellent tutorial and practical experience analise video
great video and thanks for the English subtitles
Professionally well done sir....
Thanks for your videos...
explanation and calculations are splendid. Look forward to many more simple projects.
thanking you . K. subramanya Banbalore.
Thanks
Excellent video teaching. Kudos
Very good teacher thank you.
Theroitically and practically excellent sir....
बहोत ही अच्छे से समझाया आपने ऐसे समझाने वाला वीडियो पूरे यूट्यूब में नही मिला धन्यवाद
But jandar, shandar video hai. You are most intelligent person. Thanks
Thanks
Smjhaan da treeka kya baat bhaji👍🙏
Dear Sir,
Your are the best Instructor in the world.
Great Explained, I'm new Subscriber from Today.
Thanks
U are my ideal teacher. Thanks
Thanks
i know hindi but full video understand. i like you and your video. Bangladesh
Very good teacher God bless you
Method of explanation is best. God bless you
Thanks
Very nice sir thank you so much
बहुत पसंद theory plus practical, what more does one need.Thanks.
Great video .very good information sir
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Excellent
Regards
🙏🏼
Very good, thanks
Sir, Explanation is amazing 👍
Keep it up
Very good , thanks,
Your explanation is superb. Very good vidios.
Thanks 😊
I'm impressed with this share of knowledge and specially the calculations procedures. Would it be possible how to calculate value of regulator?
Teşekkür ederiz...
thanks for the clear explanation
Wow, very descriptive and knowledgeable video
Thanks
मै २५ साल से ईलेक्ट्रॉनिक्स विषय मे काम कर रहा हु । ये मैने २००५ मे बनाया था । एल ईडी बल्बवर प्रयोग करतांना। 👍
जय महाकाल
Very very good presentation thanks
You are most welcome
Good sardar ji vadiya samjhaya
Thanks 😊
Super Explanation about the stepping down voltage, Rectifying the voltage, filters, regulating voltage and getting required output voltage.
Tnq.
Nice explanation. Keep up the good work.👍
Thanks
Super fully help FULL video 😍😍😍
Thanks
Super explained. Explained strightly no time waste. Subtitles manner is good .Some times subtitles came across(Sometimes I could not see the circuits ). Please put explaining article little bit above.
You can turn off subtitles on your phone or pc just clik the cc button below the video
I like ur method of teaching
Tha ks
Excellent presentation
Nice video and very good explain sir 👍
Thanks very much sir 😊
Bahut pasand aya sir
Great work 👍🏻👍🏻
I don't know hindi but Amazing class all doubt cleared thanks 🙏
From kerala
Very useful video thanks
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sir huge respect and love from pakistan .sir your way of teaching is very good.
Thanks.. Do share these videos and channel with your frends if you think it can help someone.
Good explanation,keep it up,make video's for variable power supply with explanation for different loads.thanks in advance.
Thanks. I will make video on variable supply soon.
Keep supporting
धन्यवाद सर वैरी नाईस।
It's Not a Good Explanation. As The 2 Bias Points ie; Cathode Points Of a Diode With Another One One The Same Line In Series. Will Not Allow Current Flow - Result. You Will Create Back EMF And At The Junction. Where Both Cathodes Meet & Are In Series - Very, Very Serious Heat Damage Will Occur! R H Fraser.
Mast video hai.
Thanks a lot.
Most welcome
Excellent.
your captions are very useful bro and easily understood.... bcoz I m not a hindi.... i m tamil.
Thanks
Bahot khoob sir
Thanks
बहुत बढीया सिखाया
Thanks
Thank You Sir
Well, the maximum input voltage of the 7805 is specified to 35 V. You operate the device across its break-though voltage, which is obviously around 46V. Only the input capacitor and the internal break through resistance of the 7805 limits the undefined current (here considerably smaller than 12 mA) across the device. I am surprized that the 7805 is still working if it's break-through voltage is exceeded. Nevertheless, this operation can harm the 7804 after a certain time and there will be no more 5V limiting behaviour after a while and the diode can be damaged too.
My suggestion is to eliminate the 7804 and to use a 5 V zener diode behind the smoothing capacitor to get always a well defined voltage across the LED and its resistor. It will also draw down the rectified voltage to well defined 5 V. So you can use a smaller electrolytic capacitor with a voltage rating of 10 V (how did you decide your voltage rating or did you use a 400 V specified device). The current across the zener diode and the LED is well defined. Even when the LED gets disconnected, the circuit will not fail.
Thanks
Zener diodes dissipate power all the time. I prefer using regular ics but the input side must be protected with higher voltage zener diode (close to 35v) . At higher voltage, zener diode's power dissipation should be lower.
@@user-vo6yr8rf4c no, the power dissipation of a Zener diode at a higher voltage is higher. In fact, at voltages higher than 8 V Zener diodes doesn't work with the Zener effect but with avalanche breakdown.
Considering the data sheet for the BZX55-series in all cases you need to set the operating current for the Zener diode to at least to 5 mA. So for 5.1 V you only dissipate 25 mW. At 30 V you dissipate 150 mW.
Furthermore you dissipate power in the linear regulator. For 12 mA and a voltage drop from 30 V to 5 V you dissipate 300 mW. So in total you dissipate 450 mW. This is much more than 25 mW.
The most important rule for a capacitor voltage supply is to develop the active power at the lowest useful voltage. Otherwise you not only increase the power dissipation but also the reactive power at voltages considerably lower than the mains voltage.
The reactive power for the zener diode regulator is 2 W. The your solution it is 40 W!
Well said
@@user-vo6yr8rf4c omg VR IC also consume power all the time
Really great explanation 👍
Thanks
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Thanks
वाहे गुरू की जय हो जय श्री गुरु गोबिंद सिंह जी की जय best बताते हैं धन्यवाद आपका दिन मंगलमय हो i like sabcrise your चैनल सर thanku welcome
Thanks 😊
NICE WORK SIR.
Paaji sabse badhiya
your videos very nice
Super nice presentation
it was really awesome Videos ......Thank you Brother you video are really helpful ...... i have learn strongly aboud transformer less output
Thanks 😊
Well done sir je, what an explaination.
Thanks and welcome
Excellent sir ji
Good bahut achha
Good job.......
Useful video
I love electronics and i am your fan
Thanks
Perfect clarification.
Thanks 😊