but this is clearly the wrong way to do it , it took you 5 mins to do it while KVL took me 3 very simple calculations, and we still ended up with the same result.... so what's the point of doing this ?
@@nesoacademy no you misunderstood me, i really appreciate the efforts in these videos, but if there is a simpler way what is the point of learning the hard way
I understand your point, and given the option we will surely use the method which is efficient. But as engineers we should know about the concepts, these theorems can be asked in viva, interviews, and examinations directly. And in the first chapter I have already explained to do it the way you’re suggesting.
@@mustafahajhamoud2077 Yes that's totally right what sir has explained to you and also not only for the one example , the theorem is made. Sir has just explained the way how to use that theorem, we can solve the other complex example with the help of this theorem which may cannot be solve by simply KVL.
Could you please complete analog electronics series as well
you are GOD
Thank you sir ❤️
Thanks for this video
U can also it by using KCL
thank you thank you🤎
Thank you sir
❤️ thankyou
sir plz upload graph theory lectures as well
No. I don't have time for that.
How is Current accross R2 1A?
Applie kvl
as shown in ckt diagram....current in another branch is 3A.... therefore current in R2 is 1A....which sums up as total current 4A.
How can we say that power is delivered at voltage source..(.for -ve sign)????
Watch the lecture on “Electric Power” from chapter one. Everything is explained there.
@@nesoacademy thank u sir
electric power @Neso video@13.00
yeh toh obvious baat hai... tellegen ji ne esa kya kardiya ki unke naam pe theorem ho gaya
acha
😂😂😂
#nesoacademy Please upload control system lectures your explanation is very good
When control system will come?
Correct your English.
When will control system come?Subject before main verb. Modals before subject in questions.
Can u as Android development course plz
Yes
voltage across 4a and 1 must be 3 volts , and vacross 1 is 4 v , now voltage across 4a must be 2 volta and answer be 8 watt, is it true?
Thank u sir
👏👏
but this is clearly the wrong way to do it , it took you 5 mins to do it while KVL took me 3 very simple calculations, and we still ended up with the same result.... so what's the point of doing this ?
We are learning a new theorem, and solving a problem based on the same. Simple.
@@nesoacademy no you misunderstood me, i really appreciate the efforts in these videos, but if there is a simpler way what is the point of learning the hard way
I understand your point, and given the option we will surely use the method which is efficient. But as engineers we should know about the concepts, these theorems can be asked in viva, interviews, and examinations directly. And in the first chapter I have already explained to do it the way you’re suggesting.
@@mustafahajhamoud2077 Yes that's totally right what sir has explained to you and also not only for the one example , the theorem is made. Sir has just explained the way how to use that theorem, we can solve the other complex example with the help of this theorem which may cannot be solve by simply KVL.
@@mustafahajhamoud2077 The theorem can make power related calculation in large complex networks more easier where KCL, KVL can be too hectic to apply.