Thank you for explaining. I guess the problem condition is "x and y are real numbers." If so, there ia another solution. It is (x, y) = ( -3^(1/4), -3^(9/4) ) . From x^8=9, we can get x = ± 3^(1/4) . [Other solutions of x are complex number. Therefore I rejected them.] As far as I checked, it was OK (if my calculation was right).
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Good solution
❤❤❤
Thank you sir for this clear explanation ❤
Great explanations man, more grace sir.
Thank you for explaining. I guess the problem condition is "x and y are real numbers."
If so, there ia another solution. It is (x, y) = ( -3^(1/4), -3^(9/4) ) .
From x^8=9, we can get x = ± 3^(1/4) . [Other solutions of x are complex number. Therefore I rejected them.]
As far as I checked, it was OK (if my calculation was right).
9^1/2 what is the result of this .. please
how can we prove that there are no more solutions?
(x)⁹ˣ = (9x)ˣ
x⁹ = 9x
x⁸ = 9
x = ∜3 => y = 9∜3