Statics: Lesson 20 - 3 Equations and Unknowns, 3D Vectors
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I was so stressed the first 3:10 of this video. Was genuinely intrigued as to how he was going to solve this without coordinates.
Lmaooo same.. felt dumb again.
😂😂like bro jokes with literally everything
"You can do the algebra, but you can also poke yourself in the eye" haha Dr. Hanson these are amazing lectures.
Jeff Hanson, you are a consummate, artisan craftsman of mathematics with statics as your well-refined medium. I thank you.
Thank you dear for your efforts with those amazing and helpful videos in your TH-cam Chanel, go ahead and please keep doing.
enjoy the snap should have done it on the last video also
@0:58 Hi Dr.Hanson, I am a bit confused, you said that 600 N weight would be in the K hat direction, which is Z axis. But when collecting forces, you put W=600 N in the J direction. Could you please clarify this moment..????
This is a good example of using your own skills from previous lessons. He just made a mistake by saying k instead of j, but you should know its j bcs of the axis situation
Professor Hanson, thank you for another amazing lecture. Writing the correct coordinates worries me a bit.
I loved the movie magic snap!
Thank you for your time professor
For those of you with the textbook, this problem is all ass backwards because the XY&Z axis are all flipped.
Great Video!!!
I am stuck at the calculator part, how do we do it algebraically ???
Substitute until you get two equations with the same 2 unknowns, then substitute again and get the answer. Just easier and make less mistakes if you use your calculator. TI36 Pro is a cheap investment into your grades!
Hi Dr Hanson! thank you for the amazing videos! the axis system is different in book tho im looking at page 66 on your book the x axis is coming towards us, the y axis is horizontal and the z axis is vertical. I'm confused
The axis was intentionally drawn that way because there are problems in the book that are not always going to use the traditional format. Just another way to look at it.
Is that supposed to be cos45i instead of sin45i?
u are right but doesnt matter if angel is 45
the reference of the angle is the y-axis so if its with respect to the y-axis you use sin45for x component then cos45 for the y component. But if the angle is with respect to the x-asis, you use cos45 for x then sin45 for y.
how do you solve the equations with the calculator? I couldn't figure it out that part.
if you are using casio fx-991EX,
Menu/Setup/Mode
A: Equation/ Function
1.Simul Equation
Select number depending on how many unknown
then input the equation
I figured it out if you still need help
@@kurt3419 do you know how to do it with a T84 plus?
Erica Pequeno I’ll look up one looks like and let you know. I use the same calculator he does
@@EricaLuvsYella sorry I responded so late. He actually has a playlist where he goes over using the calculator. Here's the link: th-cam.com/play/PLRqDfxcafc21ZyKj0vVT9xCuv37I8Ooeg.html
Hope it helps
I believe there is an error regarding the cos 45°. It should be negative. Yeah??
nope, cos45 is positive
make sure your calculator is in degree mod, not Radian mode
How do you solve this without a calculator, specifically just the matrix part.
algebraa broo
It's just a system of linear equations problem.
Look up Gaussian elimination. That'll give you a much better tutorial than I can give with just text.
How can I use this method to solve a problem where I'm given the tension in a cable and need to find the weight of the object pulling on the cables? Thank you!
Just use the equilibrium condition in weight direction
add the tensions and equate the answer to the wight vector(W)
then get the magnitude of W and you are done, the answer is the wight (should be pointing "down" if gravity is the only force affecting the object)
Solve for the forces in the y direction, the tension between the two cables is the same. Break up the tension into the two components in order to obtain the unknown variable
I fuckin love you jeff you the fuckin man thanks for saving my Statics grade!! (and helping with calc 3 too)
please do it the exact same way, you throw us off, what are the 3 points for TDC
Sir ,with all du respect it seems there are some errors in calculating Tdb . Please double check (-3*-= 3i hat)
It's correct. It's subtracting, not multiplying. -3î - 0î = -3î.
How does B have a 0 y component?
Its on the axis
im so frustrated, you should have done TDC the normal way, i don't know how you magically used the sine and cosine
What is the normal way?
Lamba Hat for TDC
(X,y,z)
Is z = 0 ?
I dont know how to read the points on yhe graph, thats my greatest struggle
@@ikennao5299 I’m with you. I just wanted to show a different way. Yes the lambda hat method does the exact same thing. You are not alone. Many students struggle coming up with the correct coordinates of a point. Lots of practice is all I can tell you. Keep up the good work!
@@ikennao5299 Hi sir can you pls make a video on how to get the exact reading of the coordinates. I am also having issues regarding this just like some other students out there too . I will be glad if you can consider this request 🙏