Wow……took statics 40 years ago in the Fall of 1984. You make it fun to learn! All young students are blessed to have a great teacher like you! God bless you……..
I love your content. Its great for helping me get through statics with all the online courses this semester. also p1: "What's torque?" me: "Just a moment." ..... p1: "How many moments you need?" me: "Just a couple."
i guess Im asking randomly but does any of you know a method to get back into an Instagram account?? I was stupid lost the login password. I love any assistance you can give me
Jeff Hanson you seriously have made learning so much fun and I hope you understand that you have really made a difference in the lives of the people who learn from you. I appreciate your videos so much. I'm actually having fun learning statics now
hello, im on my final year mechanical engineering and i just understood the concept and how to calculate torque and moment using vectors. Thanks. Your videos are amazing !
I'm glad you are remaking this series! I am in my summer statics right now, except the hibbeler 5th edition seems to be one chapter ahead of what you are on or something because moments is chapter 3 now.
Hi the way i usually do this at work is just taking all different forces and "rotate" them until they are 90deg to the plane then do the cos of angle to determine the length. then i can do the moment equilibrium equasion. of course in extreme cases this can be quite a mess but usually its just a few forces. so i can draw a 2 d diagram, with all the forces being eather + or - the length
If you struggle with cross products there is a solver on the TI36x Pro it's under the 'vector' menu's 'math' option, it's a bit of work to enter it all in but it's a great double check.
12:04 Okay so I had to stop because I didn't understand this explanation at all. The best way I ended up finding to think about this is to just visualize a 3D plane with x, y, and z axis. If you take ANY two rays that only have x and y components and start at (0,0,0) then a ray with just z components like (0,0,1) will always form 90 degree angles with both rays. In fact the z axis itself is perpendicular to the x and y axis both.
Dr. Hanson I may see one problem. When you did r2 you said the distance is 24 on the x. If this is a right triangle shouldn't "x distance" be different then your Hypothesis??? If the same then, then we have adj=24" opp=12(5)^(1/2)" and of course hypo = 24"
can you not just do normal basic moment calculation for the last example? when do i use the 3D position vector equation and when should i use normral moment.
It's just another position vector to choose from as long as its tail starts from the point you're trying to find the moment of to anywhere on the line of action of the force. In the example, both r1 and r2's tail began from point A and they both intersected with the force's line of action which is why they both yield the same result when you take the cross product of either r1 x F or r2 x F. As long as a position vector starts from tail on point to force line of action, it can be used (they both "get to Grandma's house" in Dr. Hanson's words)
Both r1 and r2 gives you the "same" answer, because the "cross product" calculation. The r1 is the most straightforward position vector, but say on an exam that distance 24" and 30 deg is "not given" whatchagonnado? However, if you take a closer look the distance r2 is given. Bingo. Use that.. For students who are just "trying to keep their heads above water" and barely passing this course, they will not have an understanding of "line of force". Then probably fail this problem. So, you must thoroughly understand what "line of action" means so that you can easily pick your moment arm(r, position vector) coordinates. Best way to get a "solid understanding" is to solve the same problem with different r position vectors. Keep on.
![fellow fellow - พรุ่งนี้ไม่มีใครรู้ feat. INK WARUNTORN [OFFICIAL MV]](http://i.ytimg.com/vi/QP6JyjYx_W0/mqdefault.jpg)
Wow……took statics 40 years ago in the Fall of 1984. You make it fun to learn!
All young students are blessed to have a great teacher like you! God bless you……..
I love your content. Its great for helping me get through statics with all the online courses this semester. also
p1: "What's torque?"
me: "Just a moment."
.....
p1: "How many moments you need?"
me: "Just a couple."
Came here to say precisely this, you beat me to it lol
i guess Im asking randomly but does any of you know a method to get back into an Instagram account??
I was stupid lost the login password. I love any assistance you can give me
made himself laugh , classic
lol
Not all heroes wear capes. Jeff Hanson is one of them. Thank You G
jeff is my hero
Jeff Hanson you seriously have made learning so much fun and I hope you understand that you have really made a difference in the lives of the people who learn from you. I appreciate your videos so much. I'm actually having fun learning statics now
Jeff just found your series of Vids on Mech Engineering finally someone who KNOWS how to teach!,
I'm from the south, so I really appreciate your accent haha. I feel like my uncle is teaching me about statics.
what a Brillant and simple explanation thank you sir wow!!!!
hey just a moment this dude is actually making statics funny
Got my first Statics midterm today, this video helped me a lot, thanks❤
That just a moment joke cracked me u!! I am ashamed of myself 😂😂😂
8 × -7 is 56, not 42. Nice lecture, by the way. You really make everything easy to grasp.
I love you jeff but I'm not crazy right? -7*8= -56 right?? I dont see anyone saying anything in the comments so I feel a little crazy
for a second i thought was going insane🤣🤣
hello, im on my final year mechanical engineering and i just understood the concept and how to calculate torque and moment using vectors. Thanks. Your videos are amazing !
I'm glad you are remaking this series! I am in my summer statics right now, except the hibbeler 5th edition seems to be one chapter ahead of what you are on or something because moments is chapter 3 now.
I use the Global Edition and Rigid Body Equilibrium is Chapter 5. I used to be so clueless until I found this gem of a channel
Sir you are saving a lot of engineering guys out there
And gals 😉
He really meant it when he said he'd call a positional vector "How to get to Grandma's house," for the rest of his videos
Professor Hanson, thank for a classic analysis and introduction to Moments and Torque in mechanics one.
"Dont wanna get ya all worked up there" LMAOO
Great video but 7x8=56 not 42
Hi the way i usually do this at work is just taking all different forces and "rotate" them until they are 90deg to the plane then do the cos of angle to determine the length. then i can do the moment equilibrium equasion. of course in extreme cases this can be quite a mess but usually its just a few forces. so i can draw a 2 d diagram, with all the forces being eather + or - the length
Thank you for saving me from Michael Seica
OMG guys this is my first time getting TWO likes tysmm!!
If you struggle with cross products there is a solver on the TI36x Pro it's under the 'vector' menu's 'math' option, it's a bit of work to enter it all in but it's a great double check.
the super intuitive definition of position vector which makes taking moments easy.
just review what I learned before during the lockdown, really helpful, fully appreciated
awesome explanation of r vectors in your example. thx.
I hope I can run into you someday and ask for an autograph, im your fan :)
Good lesson 😌👍
From iraq ❤️🇮🇶
Keep up the great work
Thank you so much, God bless
Why do I get Dora the explorer kind of vibes so I can learn? It works, Sir you are the reason I passed. Thank you so much!!
You are the man! Thanks
damn this guy is freakin good
7 * 8 is not -42
thank you thank you thank you
Thank you! I understood the concepts.
I was worked up
12:04 Okay so I had to stop because I didn't understand this explanation at all.
The best way I ended up finding to think about this is to just visualize a 3D plane with x, y, and z axis. If you take ANY two rays that only have x and y components and start at (0,0,0) then a ray with just z components like (0,0,1) will always form 90 degree angles with both rays. In fact the z axis itself is perpendicular to the x and y axis both.
Brilliant.
Dr. Hanson I may see one problem. When you did r2 you said the distance is 24 on the x. If this is a right triangle shouldn't "x distance" be different then your Hypothesis???
If the same then, then we have adj=24" opp=12(5)^(1/2)" and of course hypo = 24"
Nice
thank youuuuu!!
I Stan for Jeff Hanson
fr
you mentioned you had another video that explains how to use ti-36 pro to solve the equations, just wondering what video that is?
7x8=56, not 42. But i'm guilty of using a calculator 8=)
Very useful video.
perfect Mr keep on doing it
Good and bad moments
can you not just do normal basic moment calculation for the last example?
when do i use the 3D position vector equation and when should i use normral moment.
the intro had me dyiing LMAOO
I appreciate your corny ass jokes they help me focus
sometimes sir give me the vibes of walter white if he does nt stop teaching.
For r x F can you use rFsin(theta) where theta is the angle between r and F?
Yeah should give the same result
How do we multiple three vectors?
Wow 🤩
Coupling effect
3:28 that was actually funny 😂😂😂😂😂😂😂😂😂😂😂
I'm having trouble understanding where the r2 comes into play.
It's just another position vector to choose from as long as its tail starts from the point you're trying to find the moment of to anywhere on the line of action of the force. In the example, both r1 and r2's tail began from point A and they both intersected with the force's line of action which is why they both yield the same result when you take the cross product of either r1 x F or r2 x F. As long as a position vector starts from tail on point to force line of action, it can be used (they both "get to Grandma's house" in Dr. Hanson's words)
Both r1 and r2 gives you the "same" answer, because the "cross product" calculation. The r1 is the most straightforward position vector, but say on an exam that distance 24" and 30 deg is "not given" whatchagonnado? However, if you take a closer look the distance r2 is given. Bingo. Use that.. For students who are just "trying to keep their heads above water" and barely passing this course, they will not have an understanding of "line of force". Then probably fail this problem. So, you must thoroughly understand what "line of action" means so that you can easily pick your moment arm(r, position vector) coordinates. Best way to get a "solid understanding" is to solve the same problem with different r position vectors. Keep on.
King
Nice joke about moment!:)
All I did is sin(60)*24*100 to get -2078