At 9:15, for the two carbons that are methyl groups off of that middle carbon, would their oxidation numbers be -3 each since they "win" against the hydrogens?
Ah yes you’re correct. It is + 10 like you’re saying not -10... I really hope from the viewers perspective that was obvious it’s hard for me to gauge that from the creators perspective...
can we study mechanism of organic reaction using the oxidation number instead of formal charge? i know it can be useless but it would be cool to have to different point of view in describing the same thing
so in summary: FORMAL CHARGE FC = #Ve in periodic table - #Ve it has in compound (include bonds/ Ve) Oxidation # = number of tug of way it won (- for winner) (only count bonds NOT valence e) I hope I summarized it right, thank you A TON!
And i thought KhanAcademy was the easiest to learn from! Thank you for explaining everything so well! + the common misconceptions
Your videos are incredibly helpful and informative and you make this stuff so easy to understand. Thanks a million!
Just want to say I really appreciate your videos!!
This was sooo helpful! Thank you!!
At 9:15, for the two carbons that are methyl groups off of that middle carbon, would their oxidation numbers be -3 each since they "win" against the hydrogens?
At 19:58 it should be positive 10 correct? Not negative since +5 * 2 is +10 and since we need -2 & O is -14 and H is +2
Ah yes you’re correct. It is + 10 like you’re saying not -10... I really hope from the viewers perspective that was obvious it’s hard for me to gauge that from the creators perspective...
@@sciencesimplified3890 no worries! Thanks for taking your time to make the video!
@@sciencesimplified3890 If the viewer is following along, then they'll know it's +10. :) Thank you for all your hard work!
Haha thank you for that actually I really appreciate that comment
5:54 = Discussion Re Oxidation Number
Thank you for your videos! Feel like the way you break up the videos is a lot more digestible and less daunting than some 3 hour long videos
can we study mechanism of organic reaction using the oxidation number instead of formal charge? i know it can be useless but it would be cool to have to different point of view in describing the same thing
so in summary:
FORMAL CHARGE FC = #Ve in periodic table - #Ve it has in compound (include bonds/ Ve)
Oxidation # = number of tug of way it won (- for winner) (only count bonds NOT valence e)
I hope I summarized it right, thank you A TON!