Just tried to subscribe because of this video, but it looks like there was another video where I had a similar thought 😂. Thank you for the amazing content!
It's because the Uncompetitive inhibitors will not bind unless there is an ES complex so they make the formation of that complex more favorable (which is reflected as a decrease in kM). Whereas the noncomp will bind the E or ES complex so it has no preference which it binds and doesn't need to make one form more favorable than the other.
Very nice but I want to clear my concept as Km decreases mean affinity of the S increases towards enzyme . So in both cases (un and non comp inhbi) enzyme fails to convert s into p e.g in other words km means substrate concentration as either substrate increase or not the product is not formed . It means km should not be affected but It is affected ..Sir explain it further when you get free .thanks
I don’t know why IFD doesn’t have a greater following yet. You are both great! Thank you!
Working on it!:-)
So good I've learned and forgotten this so many times because I never had a mnemonic for it. This is good!
Very timely. Very useful. I am working on this topic currently. Thanks.
Perfect timing!
Miracle, thank you!!
Missed a question on this when I took my mcat. Great video! Very succinct yet valuable
Thanks for your comment, succinct and valuable was the goal!!
brother, what a great video, you might have just earned me a few points on the MCAT. thanks!
Bless yall for this!
Just tried to subscribe because of this video, but it looks like there was another video where I had a similar thought 😂. Thank you for the amazing content!
awesome, bravo, short & sweet
INSTANTLY SUBSCRIBED THANK YOU!! 🤩
This is gold, thanks a lot
Great mnemonics!
GOLD. THX
I have a quiz tomorrow and damn this thing
Thanks mate ❤
Great.. kindly explain km decreases in uncompetitive inhibition...how if it is unaffected in noncomp......
It's because the Uncompetitive inhibitors will not bind unless there is an ES complex so they make the formation of that complex more favorable (which is reflected as a decrease in kM). Whereas the noncomp will bind the E or ES complex so it has no preference which it binds and doesn't need to make one form more favorable than the other.
Very nice but I want to clear my concept as Km decreases mean affinity of the S increases towards enzyme . So in both cases (un and non comp inhbi) enzyme fails to convert s into p e.g in other words km means substrate concentration as either substrate increase or not the product is not formed . It means km should not be affected but It is affected ..Sir explain it further when you get free .thanks
Jizakallah 🎉🎉
Super helpful!
bossman thank you
All I need is to remember the plots then I will remember km. Because x intercept is -1/km. Y intercept is 1/v max. Slope is km/vmax
These graphs are wrong.
why is this such a hard concepts for students lol