Electrical PE Exam - The Conjugate (S=VI*) [part 1]

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  • เผยแพร่เมื่อ 6 ก.พ. 2025
  • An in-depth analysis of the complex conjugate applied to power calculations on the PE exam.

ความคิดเห็น • 10

  • @creativesquare1110
    @creativesquare1110 6 ปีที่แล้ว +6

    cleared the concept in just 7 minutes.. hats off man

  • @tony3387
    @tony3387 3 ปีที่แล้ว

    very good explanation. helps me a lot!!

  • @ghmag82
    @ghmag82 9 ปีที่แล้ว +8

    Current lags voltage for lagging pf loads. (Rotation is ccw by standard convention.) Your headings for leading and lagging are backwards.

    • @BruceHamilton
      @BruceHamilton 7 ปีที่แล้ว +1

      The labels have since been fixed, in case anyone was going to skip the video because of this previous mistake.

  • @kamikaze_twist
    @kamikaze_twist 4 ปีที่แล้ว +2

    Man you should have been my college professor. Thanks for the amazing explanation!

  • @yuunn
    @yuunn 11 ปีที่แล้ว

    Great explanation.

  • @kanishkaravindranath9314
    @kanishkaravindranath9314 4 ปีที่แล้ว

    very good

  • @haseebzarrar
    @haseebzarrar 4 ปีที่แล้ว

    The First Eq. of Phi under LEADING graphically as drawn is PHI = Theta V - Theta I ... (did I miss something unless you mean the magnitude are same for Leading and Lagging. Please help me understand better. Thanks in advance.

    • @haseebzarrar
      @haseebzarrar 4 ปีที่แล้ว

      Disregard - I watched PART 2 !!! hahaha.

  • @bucknelljay
    @bucknelljay 13 ปีที่แล้ว

    A good intro. Hard to read the small writing toward the end in the lagging/leading example.