Good morning sir, How can I solve this problem? Your help will be highly appreciated. Determine the efficiency and regulation of a 3-phase, 50 Hz, 150 kms long transmission line having three conductors spaced 3.5 metres delta formation when the receiving end delivers 25 MVA at 120 kV and p.f. 0.9 lagging. The resistance of the conductor is 0.25 ohm per km and the effective dia is 0.75 cm. Neglect leakance and use (i) nominal-T, and (ii) nominal-π.
There is a mistake, correct me if I am wrong. Pr= root under 3 x Ir x Vr x cos fi r But in the solution it is taken as '3' not root under root under 3 why?
Three phase power formula is 3vph Iph cos fi. As we are analysing a single phase circuit we need to use this formula for finding the receiving end power. I have not used √3 there
Really helpful video especially you're explaining according to CL Wadhwa book🙏🏻🙏🏻
Really helpful sir .. thanq so much for uploading 😃😊👌👌👌
Good explanation sir......Thanks so much
Which textbook do you use ? the name please
Power system by C. L. Wadhwa (probably)
Here we go begining 2025 stronger getting more knowledge about Electric Engineering!..
Beautiful explanation... Thank you sir
Bro, why did Vr had a 0°
Because we are assuming receiving end as reference in general
Thank you very much sir, i did hesitate to ask you directly ... I'm really thankful for your explanation.🙏
Well explanation sir.. 👏
Hello. For the value of 'A', how did you get the angle 0.0813°?
Bro same doubt bro
Well done sir.🙏
Sir, 3ph 400kv line length 220km of 600mw powerplant, 100mvar reactor sending end, if shunt reactor off what is the reciving end voltage caculation?
Sir, where did you get the 43.39MW?
Good morning sir,
How can I solve this problem? Your help will be highly appreciated.
Determine the efficiency and regulation of a 3-phase, 50 Hz, 150 kms long transmission line
having three conductors spaced 3.5 metres delta formation when the receiving end delivers 25
MVA at 120 kV and p.f. 0.9 lagging. The resistance of the conductor is 0.25 ohm per km and the
effective dia is 0.75 cm. Neglect leakance and use (i) nominal-T, and (ii) nominal-π.
Well explained sir ✨✨🙌🙌
Sir ... please can you tell me how you got angle A= 0.0813 ....
Sir aapn ne A , B ,,C , D ke value ke last me kese nilai means ko si from mee
Sir I can't understand A value in the sum
Sir abcd parameter use chesi nominal t methoda exmas lo essay ga cheyavachu ha sir
Yes you can do it if the method is not mentioned in your problem
Sir last answer A= how u got sir .... please reply me
i am wondering how you got A= 0.995
@15.25 I got A= -8.8786....
Where you got the answer 9.317
Thank you very much ❤
Nice explanation sir
Any videos on addders sir
Which adders maa?
please exption how a value comes
See the previous video
There is a mistake, correct me if I am wrong.
Pr= root under 3 x Ir x Vr x cos fi r
But in the solution it is taken as '3' not root under root under 3 why?
Three phase power formula is 3vph Iph cos fi. As we are analysing a single phase circuit we need to use this formula for finding the receiving end power. I have not used √3 there
Tell me the timing of the video where you find error
3:33
@@MrRavindraprasadIn question 3 phase 50 Hz is mentioned
Sir while solving problems on abcd parameters the phase angle must be included to find a ?
Can we consider only magnitude?
Yes you need to consider Phase angle and Magnitude both
@@MrRavindraprasad thanks sir
@@MrRavindraprasad sir phase angel of Ir(-36.86) ,why you take negative sine ?
@@SaiKumar-hy5gb Load is lagging in nature and Vr is considered as reference
👌👌👌👌
Tq u sir ☺
🫡🫡🫡🫡🫡🫡