India | Trending Math Olympiad Question.
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- เผยแพร่เมื่อ 13 ก.ย. 2024
- India Math Olympiad question.
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Nice and wonderful work sir.
Yah very interesting
Thanks!
Impressive
First comment sir OP
FROM INDIA
I am Indian
Brilliant explain❤❤
Do you know JEE mains and JEE advanced
And IIT
30 and 10^(-4)
At least you tried here..😂😅😂😅
What do you mean bro?
e^(log 3 + 1) or e^(-4)
Good work, Sir. ❤
(x/3)^(3+Log[10,x]=3*10^4 x=30 x=0.0001=1/10000 final answer
(logx + 3)log(x/3) = 4 + log3
(logx + 3)(logx - log3) = 4 + log3
logx = u => x = 10ᵘ
(u + 3)(u - log3) - (4 + log3) = 0
u² + (3 - log3)u - 4(1 + log3) = 0
u = { log3 - 3 ± √[(3 - log3)² + 16(1 + log3)] }/2
u = { log3 - 3 ± √[(log3)² + 10log3 + 25] }/2
u = [log3 - 3 ± (log3 + 5)]/2
u = log3 + 1 = log30 ∨ u = -4
x = 10ᵘ
*x = 30 ∨ x = 10⁻⁴*