Higher Physics - equations of motion. I derive all 4 equations of motion then go over some important points to remember when using them. Look out for the video of examples as well!
That's the acceleration due to gravity. Using sign convention and taking upwards as positive, that means that acceleration due to gravity (always taken as downwards) must be -9.8ms-2.
@Mariyam Jahangir Hey! 9.8 ms is the value of Earth's gravity. As the objects motion was upwards, the gravity was opposing it. So was used with negative sign .
@Mariyam Jahangir when you drop an object on Earth, it accelerates towards the ground at 9.8ms⁻² (ignoring the effects of air resistance). As for the negative sign, that's called 'sign convention' - deciding which direction is positive and which is negative. I take upwards to be the positive direction. Since objects accelerate downwards (the negative direction), acceleration due to gravity is taken as -9.8ms⁻²
Why would people dislike the truth about the Equations of motion everything is perfect *its slow pace to not fall behind *simple and going through each step *perfect illustration i can't see why people disliked this?
Perfect! Exactly what i was looking for. Most other videos just show how to memorize the equations, this goes under the hood. The equations make perfect sense now.
Thank you so much! I couldn't figure out how to get the 3rd equation, but after this explanation the 3rd and 4th seem quite obvious. Of course it's harder if you don't know how you're supposed to get there.
Dear Mr Smith, I humbly request you to make a video regarding graphs of uniform acceleration etc. I have a lot of trouble reading them and obtaining data from them. This is just a suggestion.
There is a video called 'Velocity-time graphs' - is that any use to you? If you tell me what areas the video would need to cover, it's something which I'm sure I could do at some time because it wouldn't take too much work.
It's really a good lecture . I was able to understand very efficiently without subtitles . Would you please solve more examples in your video . That would be really helpful . Love form India !!
thank you sir !!!!!that was useful, now iam grateful that i found a teacher like you , i hope your students understand that they HAVE YOU !!!!!many thanks
That's because (ignoring air resistance), the path of the projectile is perfectly symmetrical. The vertical velocity at any height on the way down will be equal to that on the way up.
Wow, thanks a ton. In the exercise only u was given and the rest you had to find out by reading the text carefully and making one assumption (taking upwards as positive). Hadn't known how to do this before watching the vid. Super content!!!
Thank-you very much. My brain was very confused because of this kinematic equations of Sir Isaac Newton and was about to destroyed because no one was able to explain this concepts in simple way. You explained them very well and help me overcome my physics problems. Thank-you very much buddy!!👍
if v=0 and we are looking at the horizontal how do we decide whether we use s=1/2*(u+v)t or s=ut+1/2at^2 as the first equation would need us to half but the second equation doesn't.
But you are more awesome than me.I am just a student whereas you are a teacher.Not just a normal teacher but an super awesome teacher.Btw you are welcome.
Thanks this halped me alot i have ny paper tomorrow and i was having a lot of trouble understanding this but after watching this video but now its all cleared thankyou mr smith
I'm working on 21 new videos right now - hopefully there will be something of use among them. I will also try to get another equations of motion examples video made as it's a much searched video.
It's a font in Apple Keynote called 'chalkduster'. I like the look but it doesn't always work when writing equations so I'll probably not use it again.
Excellent video! Could you please tell me how did you make such video containing moving symbols? I really love this approach to show equation derivations.
For Higher Physics in Scotland, pupils need to choose the correct equation from a 'relationships sheet'. The equations are written as I show them in the video so I don't want to cause confusion by adding symbols that pupils won't be familiar with.
I have a question, i was doing homework and came across a question that said a ball being thrown vertically upwards at 4ms-1, whats the height of the ball after 2 seconds and i was writing down what i had and used a=-9.8ms-2 which gave a negative displacement, should i have taken acceleration as negative or have i done something wrong?
The full question is “a ball is thrown vertically upwards from the edge of a cliff as shown on the diagram” on the diagram shows the cliff being 33 m tall and the ball being thrown at 4 ms-1 “the effects of friction can be ignored” a) “what is the height of the ball above sea level 2 seconds after being thrown?” Thanks for the help
![Linear Motion Equations - How to apply [PHYSICS ROX ~ MS HOO EXPLAINS]](/img/n.gif)
how did you get -9.8 for the acceleration?
please help, thanks
That's the acceleration due to gravity. Using sign convention and taking upwards as positive, that means that acceleration due to gravity (always taken as downwards) must be -9.8ms-2.
good question
@Mariyam Jahangir Hey! 9.8 ms is the value of Earth's gravity. As the objects motion was upwards, the gravity was opposing it. So was used with negative sign .
@Mariyam Jahangir when you drop an object on Earth, it accelerates towards the ground at 9.8ms⁻² (ignoring the effects of air resistance). As for the negative sign, that's called 'sign convention' - deciding which direction is positive and which is negative. I take upwards to be the positive direction. Since objects accelerate downwards (the negative direction), acceleration due to gravity is taken as -9.8ms⁻²
@@MrSmithsPhysicsonline you use calculator for these. We don't use calculator in india for such small problems.
Am i only the one watching in 2024 😢😅😅
Thanks for watching - this is my most popular video, so you're not the only one!
@@MrSmithsPhysicsonline thanks 😊
No you aren't my friend
We are here
Nooo
Why would people dislike the truth about the Equations of motion everything is perfect
*its slow pace to not fall behind
*simple and going through each step
*perfect illustration
i can't see why people disliked this?
I personally love all my videos, but I guess we're all entitled to an opinion! Thanks for your positive comment.
@@MrSmithsPhysicsonline thx this helped a lot
Perfect! Exactly what i was looking for. Most other videos just show how to memorize the equations, this goes under the hood. The equations make perfect sense now.
Thanks for the comment!
Excellent.
.
. teaching with nice illustration
Thank you! The illustrations can take a long time so it's nice to know that they're appreciated.
Thank you so much! I couldn't figure out how to get the 3rd equation, but after this explanation the 3rd and 4th seem quite obvious. Of course it's harder if you don't know how you're supposed to get there.
Glad the video helped. What other topics would you like to see covered?
So glad I found your channel struggling so much with physics and need it for uni
How did you get on in the end?
You just completed my 1 week project within 9.11/1.25min
Thank you brother
Excellent - all in a day's work!
You're an absolute legend. School is closed due to Covid-19 and this is teaching me so much of the higher course for next year. Thank you!
Thank you - I'm working on new videos too. Glad they're helping.
Hi
Me too
Dear Mr Smith, I humbly request you to make a video regarding graphs of uniform acceleration etc. I have a lot of trouble reading them and obtaining data from them. This is just a suggestion.
There is a video called 'Velocity-time graphs' - is that any use to you? If you tell me what areas the video would need to cover, it's something which I'm sure I could do at some time because it wouldn't take too much work.
It's really a good lecture . I was able to understand very efficiently without subtitles . Would you please solve more examples in your video . That would be really helpful .
Love form India !!
I'll certainly try to make more videos with worked examples. Thanks for the comment.
Got a new student, very well explained. This video is really helpful.Thank you sir
Thanks for the comment!
@@MrSmithsPhysicsonline welcome, sir.
tq uuuuuuuuuuuuuuuuuuuuuu sooooooooooooooooo muchhhhhhhhhhhhhhh sir .the best thing about u is that u r responding all the comments
I'm trying - I really appreciate the feedback. Glad you liked it!
hi sir how are u sir
Your video is unexplicably amazing!!!!!!
Thank you so much!!!!!!
You've obviously got good taste!
thanks! This is what I need for knowing the concept of the formula
Glad you found it useful - thank you!
Clear and brief! Also helpful example question at the end! Thank you very much!
You're very welcome! Glad you found it helpful.
Thank you! This explanation was all i needed. Keep making more videos!❤
Thank you - glad you found it useful!
Saw many videos on this but perfectly understood this one.
Thank you Sir for such a great explanation.
I would love to be your student
Thank you
Thanks and welcome - glad that it helped.
My teacher never explained how to extract these, thanks so much now I can easily remember equations of motion
You don't need to know the derivations any more but I feel that it's still useful to know where they come from.
Good videos
I like it
Good I will like your suggestion
thank you sir !!!!!that was useful, now iam grateful that i found a teacher like you , i hope your students understand that they HAVE YOU !!!!!many thanks
Thank you! Glad that you're finding the videos helpful. All the best!
Such an amazing lecture I've heard ever, i was facing problem in understanding the equations of motion but after this i got all of that.
Thank you very much - glad you found it useful.
Thank you Mr. Smith, it was very helpful!
Glad it helped!
I found this video very helpful, thank you!
Thanks. BTW I love a good meme too.
Seriously, this is the best explanation ever.
That's the best comment ever! Thanks.
I have a higher physics autumn assessment tomorrow on odu, thanks for these videos they are really helpful for revising
Good luck - you can do it!
Thank you Sir! Your video really helped me in solving numericals!
Excellent - glad it helped!
Thank you so much for this video, it was very useful!! I'm trying to learn these equations for the first time for my BMAT exam, you definitely helped!
Glad to have helped - good luck!
What is bmat exam ?
Hallooo army 😊
how do u consider initial and final velocity of the ball be the same? ( although der is difference in sign due difference in direction)
That's because (ignoring air resistance), the path of the projectile is perfectly symmetrical. The vertical velocity at any height on the way down will be equal to that on the way up.
Glad! I found this video,my teacher is not so good . So I wasn't able to understand it, but you cleared all doubts
Glad it was helpful!
It's good to see you replying for every comment .
I try to reply to them all so that I can help anyone with a problem. Glad you noticed!
Super, reminds me of o level physics which I am beginning to need again.....thank you, very clear and helpful
O level - those were the days!
This teacher just solved my problems.
Glad to help - who's going to sort my problems?
Thank You very much sir. I've found good use of TH-cam.
Glad to hear that - all the best!
Thank you so much!
Glad you liked it!
Bhai thanx kyuki aap sabko comment bhi karte ho aur bdhiya explain bhi krte hoo
Hmesha isi 5rh krna all the best
Bhai you teach good
Thank you! I always try to reply to all comments although some of them seem to get lost at times. Glad you are finding the videos useful.
Wow, thanks a ton. In the exercise only u was given and the rest you had to find out by reading the text carefully and making one assumption (taking upwards as positive). Hadn't known how to do this before watching the vid. Super content!!!
Glad it helped! Thank you for the kind comment.
Thank-you very much. My brain was very confused because of this kinematic equations of Sir Isaac Newton and was about to destroyed because no one was able to explain this concepts in simple way. You explained them very well and help me overcome my physics problems. Thank-you very much buddy!!👍
Thanks for the lovely comment - all the best!
Thanks sir for the proof of kinematic equation it's really helpful
Glad you found it helpful
This video was really helpful for me. Thanks a lot for making this video
Glad it was helpful!
The explanation was great ,helped me a lot in my assignment again ,thx for helping 🔥🔥
Glad it helped!
Congrats for the great explanation! I’m 100% sure I’ll get good marks in tomorrow’s physics exam because of you sir! Love from india ❣
Hope everything went well with the exam!
Great! I got the results and got 20/25 🤩🤩🤩
how do you study??😭 i need help omg
the girl who threw the ball should be a pro athlete
Maybe she is - I'll ask.
You are a legend my friend
Thanks - takes one to know one!
if v=0 and we are looking at the horizontal how do we decide whether we use s=1/2*(u+v)t or s=ut+1/2at^2 as the first equation would need us to half but the second equation doesn't.
If you're looking at the horizontal component, acceleration is zero so both equations simplify to s=vt.
@@MrSmithsPhysicsonline thanks I didn't consider that
You are awesome.I understood it in one watch.
Thank you - you are awesome too!
But you are more awesome than me.I am just a student whereas you are a teacher.Not just a normal teacher but an super awesome teacher.Btw you are welcome.
Sooo nice its clear my all doubts its help me a lot.... Thanku
Glad you found it useful - thank you!
thank you for the example.helped a lot:D
Glad it helped!
Thanks this halped me alot i have ny paper tomorrow and i was having a lot of trouble understanding this but after watching this video but now its all cleared thankyou mr smith
Good luck tomorrow - fingers crossed!
very interested...
......
.......
.....
nice way of teaching
.......
excellent teacher
Glad you liked it!
perfect ....well done
Thank you - glas you found the video helpful.
Thanks for helping me a day before my class test...🙏
Glad you found the channel in time for the test - hope it helped.
Thanks ,I caught up all my work 👍 now I'm on track 😊
Magic - glad that it helped.
Tomorrow is my exam thanks for helping
Good luck!
So helpful
Cheers - it's taken me a while to respond, but I got there!
All the best!
Excellent explanation 👍👍👍 hope you make more such amazing videos and help us understanding the concepts of physics. Best of luck helped me alot
Thank you for the nice comment - what topics would you find most helpful?
SIR YOURE THE GOAT TYSM!!
You're too kind!
Very helpful 😀Thankx!
Thanks, Astrophile!
nice video and your vice is nice
Thank you - I'm glad that it's been helpful.
What is meant by displacement? The distance covered from original position? Hope you can help!
Have a look at this video of definitions, where displacement is covered...
th-cam.com/video/5YF8dZfrtvo/w-d-xo.html
this helps alot thanks!
Glad to hear it!
Great Mr. SMITH
You explained it very well.
Thanks very much!😇
Glad to help!
Thanks 🐯
Glad you liked it!
Thanks so much for you help!
What are the 3 dots that you put next to t in the example?
The 3 dots means 'therefore'.
@@MrSmithsPhysicsonline Ah I see, thanks :)
I have a test tomorrow. Thanks for the help
Good luck - hope it goes well!
OMG MY SAVIOUR...I SAW THIS AND WAS CRYING CUZ I DIDNT UNDERSTAND..MY UNDERSTANDING IN PHYSICS SUCKS....TYTY SO MUCH!!!
Physics has that effect on people sometimes - glad to help!
Really vry helpful thanks
Thank you!
Thanks alot and I will share the video to all my friends....
Great - thank you!
Wow your teaching is amazing I loved it we’ll make more videos like this ❤
Moree videos in the pipeline!
thanks .it was helpful .
Great - glad that you found it helpful.
@@MrSmithsPhysicsonline i commented 3yrs back xd i m in 12th now and now i got the reply haha
Thanks a lot sir ,well explained☺☺☺
Thanks!
Thanks a lot sir,i needed some revision.please upload more about function,linear, force
I'm working on 21 new videos right now - hopefully there will be something of use among them. I will also try to get another equations of motion examples video made as it's a much searched video.
thanks for this epic vid understood how to derive thanks to you
No problem! It's a tricky job deriving the equations but I think the animations help.
sir how we will get to know that v- u in height of triangle?
It might be easier to imagine some values - say u=6m/s and v=10m/s. The height of the triangle must be 4 ie 10-6. Hope this helps!
thanks sir you are the best teacher in the world
I agree!
Mr Smith.. u r awesome...😊😊..
thanks :)
You're Albert Einstein why are you here. You should be teaching HIM not the other way around.
ha ha ^^
Thanks for all your work, Albert - it's been an inspiration!
Sir really a great vid
Helped me a lot
Glad to hear that - any other topics you'd like to see covered?
thanks a ton ,this is something you dont usually get on yt.thank you for sharing this video .love from india:D
My pleasure! I'm keen to make more videos with example questions - are there other topics you'd like to see covered?
verreeey helpfull and easy
Easy - you've obviously understood it well!
Relative motions plz
I'll hopefully have one soon on relative motion - a past paper solution video.
Thank you!! You made it so easy to understand. And I understood 🤯🤯🤯🤯
Glad it helped!
❤thanks, it help alot much appreciated 🙏
Thanks for the comment - glad it helped.
Thank you very much mr. Smith
Glad it helped - thank you!
good sir
Good comment - thanks!
Thank you sir, it helped a lot
That's great - glad you liked it.
excellent explanation!
Thank you - glad you liked it.
Am I only one watching in 2024
You're doing well - I'm still living in the 1980s.
@@MrSmithsPhysicsonline😂 nicee
Please save me from higher physics hell
Save yourself - if you've started revising now then you've got time to get some serious revision in and turn it around. Good luck!
Can do more example of solving problems for these equations..... It really helps us
Will do!
May i know what is the font you are using for the presentation. It looks good .
It's a font in Apple Keynote called 'chalkduster'. I like the look but it doesn't always work when writing equations so I'll probably not use it again.
from nepal😍
Welcome from sunny Scotland!
hey he's foreign that's lit
From Scotland - ya dancer!
Excellent video! Could you please tell me how did you make such video containing moving symbols? I really love this approach to show equation derivations.
I use Keynote on an iMac for the animations. It takes a long time for each video but i'm happy with the results.
@@MrSmithsPhysicsonline thx，helps a lot
Helped me a lot
Thank you!
Wonderful video ,very well explained ,if same give a like
Thank you!
8:03 how many of you guys laughed hardly🤣🤣🤣🤣
Was it when I said "now that's a big number". Sounded quite funny listening back to it after all this time.
@@MrSmithsPhysicsonline no sir I just posted for fun sorry 🥰
It's all good - maybe it had some people going to that point which looks good to TH-cam.
@@MrSmithsPhysicsonline NICE TO🥰 MEET YOU , ARE YOU FROM WHERE??
From sunny Scotland.
Genius!, you have a gift!
True that!
Thanks for your help
Happy to help!
Can you please become my physics teacher.
I can be your TH-cam Physics teacher - that's probably better than having me as a teacher in real life!
What do we get out of these equations? 1d vectors? Why don't we write the arrow symbol for vectors on these equations?
For Higher Physics in Scotland, pupils need to choose the correct equation from a 'relationships sheet'. The equations are written as I show them in the video so I don't want to cause confusion by adding symbols that pupils won't be familiar with.
I have a question, i was doing homework and came across a question that said a ball being thrown vertically upwards at 4ms-1, whats the height of the ball after 2 seconds and i was writing down what i had and used a=-9.8ms-2 which gave a negative displacement, should i have taken acceleration as negative or have i done something wrong?
I get an answer of -11.6m which means that the object would be 11.6m below its starting position (if possible). What's the full question?
The full question is “a ball is thrown vertically upwards from the edge of a cliff as shown on the diagram” on the diagram shows the cliff being 33 m tall and the ball being thrown at 4 ms-1 “the effects of friction can be ignored” a) “what is the height of the ball above sea level 2 seconds after being thrown?” Thanks for the help
Joe?
Thanks mr. Smith 😃
You're very welcome!