The description for the molecular orbital theory of cycloadditions was so helpful. It made so much more sense the way you presented it. Thank you for your work.
You're on the right track! Look at the diagram at 4:14 (video timeline) and you see 4 pi electrons for the diene reacting partner. Then look at the diagram at 4:41 and you see 2 pi electrons for the alkene partner. Altogether, there are six pi electrons participating in the cyclization process, forming two new sigma bonds and a pi bond in the new ring.
@@jpmccormick3491 Thank you! I ment: Why can only 2 electrons be in the state where all orbitals are in-phase, so the lowest energy state. I would think 4 e- would be able to fit in that state.
+alekhya VV Good suggestion! I'll put it on the list. Unfortunately ... I'm in a very period right now and cannot get to this right away. Good luck with your exam!
Great question! Yes, it is. However, other examples are not common, unless light is involved. In a photochemical reaction, the HOMO/LUMO in the excited state of an alkene will have altered symmetry.
The description for the molecular orbital theory of cycloadditions was so helpful. It made so much more sense the way you presented it. Thank you for your work.
I had such a hard time understanding my professor. You made it so easy. Thank you!
Thank you so much!
You're welcome! Glad it was helpful. Best wishes for success!
Thank you sooooo much.... i understand it here.
Thanks, nice video! Makes everything clear :)
great video
Very nice video!
Can you interpret the electrocyclic reaction, cycloaddition, sigmatropic reaction and their difference?
very informative! but what exactly do the phases of orbital means?
Thank you sooooooooo much now i get it
beautifully explained (Y)
thanks :)
thanks so much!!!
+Connie Martin You're welcome! Glad it was helpful. I appreciate the comment.
Why can the four bonding orbitals only contain 2 electrons? Why not 4?
You're on the right track! Look at the diagram at 4:14 (video timeline) and you see 4 pi electrons for the diene reacting partner. Then look at the diagram at 4:41 and you see 2 pi electrons for the alkene partner. Altogether, there are six pi electrons participating in the cyclization process, forming two new sigma bonds and a pi bond in the new ring.
@@jpmccormick3491 Thank you! I ment: Why can only 2 electrons be in the state where all orbitals are in-phase, so the lowest energy state. I would think 4 e- would be able to fit in that state.
@@jpmccormick3491 I figured it out, it is *one* molecular orbital, so only two electrons
so which reactions emit a photon of light?!
can u pls upload a video of photo dissociation, photo reduction and photo oxidation with examples. I have a major exam in 2 days. Thanks again (:
+alekhya VV Good suggestion! I'll put it on the list. Unfortunately ... I'm in a very period right now and cannot get to this right away. Good luck with your exam!
is it possible to have more than a 4+2 cycloaddition formula?
Great question! Yes, it is. However, other examples are not common, unless light is involved. In a photochemical reaction, the HOMO/LUMO in the excited state of an alkene will have altered symmetry.
thanks so much for this!!!
مفيش ترجمة ياصاحبي
What does EWG mean? I don't really understand what you're saying there. Sorry, German. :D
EWG = electron-withdrawing group
Thank you, that helps me a lot!
Electron withdrawing group
عايزين العرب يشتغلو بقا وكفاية نوم .. كل مافتح فيديو علمي الاقيه اجنبي ومفيش عربي اصحوا بقا ياعرب