Please don't come to PSUs . You will ruin your future. Job stress is like hell. Aggreed to all the points speaker said. Lower level at PSU is where you are paid more, upper level you get seriously lower than your private counterpart.
The following observations were recorded during a trial on a 4-stroke diesel engine : Power absorbed by non-firing engine when driven by an electric motor engine = 1750 rpm, brake torque = 327.4 Nm, fuel used 42000 kJ/kg, air supplied temperature of cooling water = temperature = 20.8°C, specific heat of water =4.19 kJ/kg K, and specific heat of exhaust gases 1.25 kJ/kg K. Determine : a) B.P, b) Mechanical efficiency, c) BSFC, and d) how to oslve?
a) Brake Power (B.P): The formula to calculate brake power is: B.P = (2πNT)/60 Where: N = Engine speed in rpm T = Torque in Nm Given values: N = 1750 rpm T = 327.4 Nm Calculating B.P: B.P = (2π × 1750 × 327.4)/60 B.P ≈ 57085.85 Watts b) Mechanical Efficiency: The formula for mechanical efficiency is: Mechanical Efficiency = (B.P / I.P) × 100 Where: B.P = Brake power I.P = Indicated power Since we don't have the indicated power (I.P) given, we can't calculate the mechanical efficiency with the provided information. c) Brake Specific Fuel Consumption (BSFC): The formula for brake specific fuel consumption is: BSFC = (Fuel used / B.P) Given values: Fuel used = 42000 kJ/kg (per unit mass of fuel) B.P = 57085.85 Watts Since the fuel used is given per unit mass of fuel (kJ/kg), we need to convert the brake power (B.P) to kJ/s before calculating BSFC. B.P_kJ_s = B.P / 1000 B.P_kJ_s = 57085.85 / 1000 B.P_kJ_s ≈ 57.09 kJ/s BSFC = Fuel used / B.P_kJ_s BSFC = 42000 / 57.09 BSFC ≈ 735.45 g/kWh (grams per kilowatt-hour) d) How to solve: To solve for the parameters mentioned above, you need the following information: Engine speed (rpm) Brake torque (Nm) Fuel used (kJ/kg) Air supplied temperature (°C) Specific heat of water (kJ/kg K) Specific heat of exhaust gases (kJ/kg K) Using the provided formulas and calculations, you can determine the brake power (B.P), brake specific fuel consumption (BSFC), and mechanical efficiency. However, the indicated power (I.P) is required to calculate the mechanical efficiency, and it is not provided in the given information.
Finally someone spoke the actually facts
Please don't come to PSUs . You will ruin your future. Job stress is like hell. Aggreed to all the points speaker said. Lower level at PSU is where you are paid more, upper level you get seriously lower than your private counterpart.
Are u in psu?
How's your opinion on Airport Authority of India?
Beta ji wo baap hai@@user-jhP-urx3-6gh
The following observations were recorded during a trial on a 4-stroke diesel engine : Power absorbed by non-firing engine when driven by an electric motor engine = 1750 rpm, brake torque = 327.4 Nm, fuel used 42000 kJ/kg, air supplied temperature of cooling water = temperature = 20.8°C, specific heat of water =4.19 kJ/kg K, and specific heat of exhaust gases 1.25 kJ/kg K. Determine : a) B.P, b) Mechanical efficiency, c) BSFC, and d) how to oslve?
a) Brake Power (B.P):
The formula to calculate brake power is:
B.P = (2πNT)/60
Where:
N = Engine speed in rpm
T = Torque in Nm
Given values:
N = 1750 rpm
T = 327.4 Nm
Calculating B.P:
B.P = (2π × 1750 × 327.4)/60
B.P ≈ 57085.85 Watts
b) Mechanical Efficiency:
The formula for mechanical efficiency is:
Mechanical Efficiency = (B.P / I.P) × 100
Where:
B.P = Brake power
I.P = Indicated power
Since we don't have the indicated power (I.P) given, we can't calculate the mechanical efficiency with the provided information.
c) Brake Specific Fuel Consumption (BSFC):
The formula for brake specific fuel consumption is:
BSFC = (Fuel used / B.P)
Given values:
Fuel used = 42000 kJ/kg (per unit mass of fuel)
B.P = 57085.85 Watts
Since the fuel used is given per unit mass of fuel (kJ/kg), we need to convert the brake power (B.P) to kJ/s before calculating BSFC.
B.P_kJ_s = B.P / 1000
B.P_kJ_s = 57085.85 / 1000
B.P_kJ_s ≈ 57.09 kJ/s
BSFC = Fuel used / B.P_kJ_s
BSFC = 42000 / 57.09
BSFC ≈ 735.45 g/kWh (grams per kilowatt-hour)
d) How to solve:
To solve for the parameters mentioned above, you need the following information:
Engine speed (rpm)
Brake torque (Nm)
Fuel used (kJ/kg)
Air supplied temperature (°C)
Specific heat of water (kJ/kg K)
Specific heat of exhaust gases (kJ/kg K)
Using the provided formulas and calculations, you can determine the brake power (B.P), brake specific fuel consumption (BSFC), and mechanical efficiency. However, the indicated power (I.P) is required to calculate the mechanical efficiency, and it is not provided in the given information.
🤣🤣🤣🤣
Wo sab theek hai, why talking in midst of jungle??
😅😅
They are crying after left MADE EASY 😂
Sir PSU E1 with 40k basic Vs. Central Government Level 6 Job?
The video title should be "don't choose PSU"
Thank You Sir
True sir ❤
how to manage relatives pressure while preparing with a drop?
Ignore.
Just ignore them. It will create pressure on you if you don't ignore them