Your lesson are the best can't lie but if you take too long to explain and all that we sometimes don't finish watching the videod because they take too long but otherwise you're the best
1.If you see a variable resistor does it always mean we are investigating the internal resistor? 2.Is there an exception where the gradient of the graph is not the internal resistance?
Sir wnen the graph has the inverse of voltage and resistance what is the gradient? and how can I relate the equation the students formed for the expiriment to the graph?
Shouldnt you use values at the same point. Since voltage is 0; 7.2 shouldnt current be 0;0. Though im aware that wont work as your denominater but still right?
So like sir ,okay first ,good morning .My question is : the internal resistance becomes used up as it moves into the external circuit ? then the decreasing resistance is Vexternal ? just so i don't get stuck when i answer questions during my active recall sessions Thank you
Remember that Internal resistance is the resistance inside a battery. It remains constant for as long as there is current flowing in the external circuit. Vext depends on the value of the Vin=Ir
Sir how do we calculate r and emf if the graph given is resistance vs 1/current? I was practicing using 2018 nov question paper! Calculating the internal resistance i used the gradient but my answer was wrong. Then for the emf I took the value where 1/current was zero, but then i was wrong.
That’s a very brilliant question, trust me… Unfortunately there’s no physical “internal resistance”, it’s only a concept. As a result, there’s no way we can put a voltmeter across it… The only way we can measure it is by measuring the external resistance. You would imagine that when current increases, the voltage in the internal resistance increases, which causes a decrease in the external voltage. The graph you see is a graph of external voltage. I hope that makes sense
Prelims are starting by this week friday . Goodluck matriculants of 2024❤
Thank GOD for giving us you, you are making my life easier as an Educator.
You are most welcome sir... I'm glad I can be able to add value to you and your learners.
Thanks
Tnque sir. I was never a fan of circuits for the past two years until i came across your videos
Thankyou Sir for your help,much appreciated.keep up the great work you doing
Great content! All the best to 2021 learners, making use of this platform will help them a lot.
Many thanks
@@MKMReborn All the best.
@@MKMReborn keep going!!!
Your lesson are the best can't lie but if you take too long to explain and all that we sometimes don't finish watching the videod because they take too long but otherwise you're the best
High quality lessons. Thank you
Glad you like them!
you're the best teacher sir !!!
Great teacher
1.If you see a variable resistor does it always mean we are investigating the internal resistor?
2.Is there an exception where the gradient of the graph is not the internal resistance?
No, you may also investigate the relationship between current and potential difference
You're the best Mlunghisi....thank you please continue doing the best
It is my sincerest pleasure
Well said sir🔥🔥🔥
Why does the gradient represent the internal resistance and not the total resistance?
Thank you Mlungu you are my hero
Sir wnen the graph has the inverse of voltage and resistance what is the gradient? and how can I relate the equation the students formed for the expiriment to the graph?
Sir keep up with the good... , do not stop ...♡
You're welcome
Shouldnt you use values at the same point. Since voltage is 0; 7.2 shouldnt current be 0;0. Though im aware that wont work as your denominater but still right?
No when you work out gradient you have to have two points of the graph not 1
Is the voltage on y-axis always the external voltage or you can be given the internal voltage?
It is always external voltage. Remember there is physical way to measure internal voltage
Sir so is the gradient negative because the current strength increases resulting the voltage to decrease?
Thank you Sir, I've been waiting for a long time for this video 🎉😭😭❤🏆🔥💯
You're welcome
Sir I am a bit confused by question 8.4 I don't get how you got the gradient without using any points on the graph
The formula that was given
So like sir ,okay first ,good morning .My question is : the internal resistance becomes used up as it moves into the external circuit ? then the decreasing resistance is Vexternal ? just so i don't get stuck when i answer questions during my active recall sessions
Thank you
Remember that Internal resistance is the resistance inside a battery. It remains constant for as long as there is current flowing in the external circuit. Vext depends on the value of the Vin=Ir
YOU ARE A BLESSING
Thank you 😊
Thank God for you
Thank you 😊
Sir why is the internal resistance negative
sir can i ask if V loss is equal to V internal?
Yes... It's just a matter of preference of what you want to call it.
Sir why is the internal resistance zero
Danko Sir👏🤝
Danko!!!
Sir how do we calculate r and emf if the graph given is resistance vs 1/current? I was practicing using 2018 nov question paper! Calculating the internal resistance i used the gradient but my answer was wrong. Then for the emf I took the value where 1/current was zero, but then i was wrong.
May you please check in the videos I’ve made. I think I answered that question
Is the gradient of the graph always the internal resistance?
Sometimes it is conductance (the inverse of resistance)
sir how can you tell which axis is which
It will be given to you...
thanku u help me get bonus
Thank you very much, sir
Can you please 🙏 do a video on electrostatic
It's already there.
@@MlungisiNkosi Oh thank you sir just saw it🙏
@@its_justchristie super 😊
@@MlungisiNkosi a good night
Thank you soo much!!!
Thank you so much sir
You're welcome
Can you please teach me how to calculate ammeter 🥺?...
That’s the current across a conductor
Can you do lessons on Faraday's law please
Will do
Also please do Questions for preliminary exam sir💔you last did the multiple choice
I'm on it sir
❤
slayyyyyy!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Slay on slayer 😂
I mean negative
why does the graph have negative gradient? sorry i realise it sounds like a stupid question lol
That’s a very brilliant question, trust me… Unfortunately there’s no physical “internal resistance”, it’s only a concept. As a result, there’s no way we can put a voltmeter across it… The only way we can measure it is by measuring the external resistance. You would imagine that when current increases, the voltage in the internal resistance increases, which causes a decrease in the external voltage. The graph you see is a graph of external voltage.
I hope that makes sense
i saw many past papers that include cost ,please try to do it
I definitely will... Thanks for the suggestion.
I'm writing today paper 1 I'm nervous