How to design NPN BJT based Overvoltage protection? Overvoltage protection using NPN BJT.

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  • เผยแพร่เมื่อ 22 พ.ค. 2024
  • #foolishengineer #Transistor #Overvoltage
    0:00 Skip Intro
    00:24 What is over voltage protection
    01:42 NPN transistor for OV protection
    01:55 Circuit construction and working
    03:55 Simulation 1
    05:03 Simulation 2
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  • วิทยาศาสตร์และเทคโนโลยี

ความคิดเห็น • 32

  • @wtfucrazy
    @wtfucrazy 18 วันที่ผ่านมา

    Good work!

  • @sudhansumtripathy
    @sudhansumtripathy 2 หลายเดือนก่อน

    thank you for showing the direction of current flow, easy to understand

  • @theforcefor
    @theforcefor 2 ปีที่แล้ว +1

    Nice video, thanks for your work :)

    • @FoolishEngineer
      @FoolishEngineer  2 ปีที่แล้ว

      Thank you so much for watching, please dont forget to subscribe to my channel!!!

  • @anuragmahajan5919
    @anuragmahajan5919 2 ปีที่แล้ว +1

    Nice video! 👍

  • @johnjcb4690
    @johnjcb4690 2 ปีที่แล้ว

    I appreciate so much I try to understand but , why does t2 close, what is the current there ? How so

  • @surajupadhyay3947
    @surajupadhyay3947 ปีที่แล้ว

    Very well explain thanks sir

    • @FoolishEngineer
      @FoolishEngineer  ปีที่แล้ว

      Thank you so much! Please show support to my video with Super thanks.

  • @kabandajamir9844
    @kabandajamir9844 2 ปีที่แล้ว

    The world's best teacher

    • @FoolishEngineer
      @FoolishEngineer  2 ปีที่แล้ว

      Thank you so much for watching!! Please don't forget to subscribe to our channel

  • @nhuphan6969
    @nhuphan6969 ปีที่แล้ว

    why/how did you select 18k and 720 for R1 and R2 respectively in the zener diode case?

    • @bertblankenstein3738
      @bertblankenstein3738 11 หลายเดือนก่อน

      Note that for an npn transistor a base emitter (BE)voltage of 0.5v or less the transistor is off, not conducting from collector to emitter, and for BE 0.7v or greater it will turn on.
      So using a voltage divider, the base sees 720/(18000+720) of the supply voltage. 12v in produces less than 0.5v at the BE junction (off) while 19v would produce just over 0.7v at the VE junction (on). You'd have to choose an appropriate transistor and look at the specs too.
      It is also important to keep the resistor values in the k-ohm range and not in the m-ohm range. This is to allow a few mA to be used in to the q1 base. By having a few mA there, q1's collector can sink/drain a few hundred mA, and q1's CE voltage can be brought down preventing q2 from turning on.
      There are better over voltage protection circuits I'm sure, but if you go with this, I'd probably do some tests and measurements the realized design behaves as expected.

    • @bertblankenstein3738
      @bertblankenstein3738 11 หลายเดือนก่อน

      Ahh, I didn't see the zener diode part until after. Zener have a reverse breakdown voltage that they operate in, but that can vary so you'd need to know what the rating is on the zener for starters. And then yes, start figuring.

  • @sp.shoyon
    @sp.shoyon ปีที่แล้ว

    can you design a 27 V protection circuit ? (with resistor values)
    I mean if the voltage goes over 27 volt then the circuit will be turn off.

  • @solidname9085
    @solidname9085 ปีที่แล้ว

    What happen when we connect 12v dc adaptor, still we need over voltage protection?
    Because I think 12v adaptor provide same voltage or low voltage and not > 12v.

    • @FoolishEngineer
      @FoolishEngineer  ปีที่แล้ว +1

      sometimes due to any failure it might provide >12V

  • @razajaved6848
    @razajaved6848 ปีที่แล้ว

    Nice tutorial. But how to calculate the value of R3?
    And will the circuit work in a same way if the NPN BJTs are replaced by N-Channel MOSFETs?

    • @democracyforall
      @democracyforall 10 หลายเดือนก่อน

      The video is good but it is just as good to do calculation and show it, by simply using a package it does not really showes the proffesional side, anyone can use the package but calculation only engieers can do and he should have done that or should do that...

  • @RODOLFO.M.S
    @RODOLFO.M.S 2 ปีที่แล้ว +1

    🙏🏼🇧🇷👍 Newly Subscribed...please make a video that doesn't exist on TH-cam. A video showing the electrons in the Joules Thief circuit. Thank you very much.

    • @FoolishEngineer
      @FoolishEngineer  2 ปีที่แล้ว

      Will do. Thank you so much for watching!! Please don't forget to subscribe to our channel

    • @RODOLFO.M.S
      @RODOLFO.M.S 2 ปีที่แล้ว

      @@FoolishEngineer 🙏🏼🇧🇷👍

    • @lezbriddon
      @lezbriddon ปีที่แล้ว

      K53beWYdIpc

  • @ozanugursahin7443
    @ozanugursahin7443 2 ปีที่แล้ว +2

    But when Q1 is on very very little current can flow through to Q2,so Q2 can't be off.Because uA enough to open to Q2

    • @FoolishEngineer
      @FoolishEngineer  2 ปีที่แล้ว +1

      The current flows in nA or pA which is not sufficient to turn on the Q2

    • @ozanugursahin7443
      @ozanugursahin7443 2 ปีที่แล้ว

      @@FoolishEngineer thank you :)

    • @hariprasadgowdakerenadka8450
      @hariprasadgowdakerenadka8450 ปีที่แล้ว

      Need to select q2 such as collectors current rating is more than load current

  • @gazaziho
    @gazaziho 8 หลายเดือนก่อน

    Most words with Ri Ri (indian English accent)

  • @stevem1097
    @stevem1097 2 ปีที่แล้ว

    ...ha