❤ adding all equations and dividing by 2 bc+ca+ab = 600 using this equation with given equations bc = 300 ca = 200 ab = 100 multiplying these equations and taking square root abc = 1000√6 a = 10√6/3 b = 10√6/2 c = 10√6 a^4+b^4+c^4 = 360000(1/81+1/16+1) = 40000/9+22500+360000 = 40000/9+382500 = 4444++4/9+382500 = 386944+4/9
Eq2 - Eq1 gives c.(b-a) = 100 (Eq4), then Eq4 + Eq3 gives b.c = 300 and Eq3 - Eq4 gives a.c = 200, and then with Eq1 we get a.b = 100.
(a^2).b.c = 20000 and a^2 = 20000/300 = 200/3; (b^2).a.c = 30000 and b^2 = 30000/200 = 150;
(c^2).a.b = 60000 and c^2 = 60000/100 = 600
So we have a^2 = 200/3; b^2 = 150; c^2 = 600. Finally (a^4) + (b^4) + (c^4) = (200/3)^2 + (150)^2 + (600)^2 = 3482500/9.
Great piece of work!
Thanks a million sir/ma.
A great question and class, congratulations!❤
Perfect! You the best tutor...❤❤❤
❤
adding all equations and dividing by 2
bc+ca+ab = 600
using this equation with given equations
bc = 300
ca = 200
ab = 100
multiplying these equations and taking square root
abc = 1000√6
a = 10√6/3
b = 10√6/2
c = 10√6
a^4+b^4+c^4 = 360000(1/81+1/16+1)
= 40000/9+22500+360000
= 40000/9+382500
= 4444++4/9+382500
= 386944+4/9
Nice approach sir/ma.
You the best.
Wow!!! You captured my full attention completely with your explanations, sir. Great work. Thanks for this video, man....❤❤❤
Wow!!! Thanks a million for watching and encouraging us.
We love you dearly sir/ma...❤❤❤❤❤❤💕💕💖💖
Apreciat
Great move sir
E=a⁴+b⁴+c⁴=
(a²+b²+c²)² -2(a²b²+b²c²+c²a²);=>
ab+bc+ca=600; ab=100
bc=300; ca=200,; a²=200/3; b²=150; c²=600; E=(2450/3)²-2(140000)=3482500/9
Great one. You the best sir.
@onlineMathsTV Sir, Pleased that you take interest in solution in comment section.
Great move sir