I should point out that current transformers have a rule "Secondary winding should not be in an open-circuit state". That is, if the secondary current is zero, the primary current should be zero or else you violate the turns ratio formula and that excessive magnetic energy could damage the transformer. Using a half-rectifier circuit causes an open-circuit condition on the negative half-cycle. I believe there is a bleeding resistor across the secondary winding on the PCB that should have been used in your demonstration. Thanks.
I was advised that the current transformer should have a shorting link placed across the terminals if the monitoring circuit is removed, else a high voltage will be generated across the open circuit terminals. This occurs when the secondary is half wave rectified unless there is some internal limiter.
There should be first burden resistor across the secondary winding, then after that, diode and level shifting for interface to ADC of microcontroller which in most cases accepts only positive voltage, 0-5V or 0-3.3V or Vref negative (>0) to Vref positive(>0) voltage.
I enjoyed the video like always. I've gained indepth knowledge about current transformer. But can we connect capacitor across the rectifier to smooth out the ripple. If we connect capacitor does it render the measurement useless ?
Salam, interesting video, now we understand better those CT. I have a side question : I am building a power supply with a big toroidal transformer (220-35vAC) which gives approx 40VDC with no load. Under 5A load, i have 34VAC but the DC voltage is dropping to 31VDC, i added another 25A bridge rectifier but nothing helps, i am still loosing 9VDC while VAC stays stable. Any idea why ? Thanks.
I should point out that current transformers have a rule "Secondary winding should not be in an open-circuit state". That is, if the secondary current is zero, the primary current should be zero or else you violate the turns ratio formula and that excessive magnetic energy could damage the transformer. Using a half-rectifier circuit causes an open-circuit condition on the negative half-cycle. I believe there is a bleeding resistor across the secondary winding on the PCB that should have been used in your demonstration. Thanks.
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I was advised that the current transformer should have a shorting link placed across the terminals if the monitoring circuit is removed, else a high voltage will be generated across the open circuit terminals. This occurs when the secondary is half wave rectified unless there is some internal limiter.
جزاك الله خير
Nice experiment sir. 🎉
Clear explanation, thank you
❤bhai Haseeb the the great engineer ❤
Thank you very much sir
Salam Alaikum .Excellent work .May Allah protect you.
Vare varee nias sar thanks
best regards
Nice sir 👌👍
There should be first burden resistor across the secondary winding, then after that, diode and level shifting for interface to ADC of microcontroller which in most cases accepts only positive voltage, 0-5V or 0-3.3V or Vref negative (>0) to Vref positive(>0) voltage.
I enjoyed the video like always. I've gained indepth knowledge about current transformer.
But can we connect capacitor across the rectifier to smooth out the ripple. If we connect capacitor does it render the measurement useless ?
sir please do explain more about ct voltage measurement ?
Salam, interesting video, now we understand better those CT.
I have a side question : I am building a power supply with a big toroidal transformer (220-35vAC) which gives approx 40VDC with no load.
Under 5A load, i have 34VAC but the DC voltage is dropping to 31VDC, i added another 25A bridge rectifier but nothing helps, i am still loosing 9VDC while VAC stays stable. Any idea why ?
Thanks.
Awesome. Thank you sir.
What happend if the CT damaged in Ac circuite board. Is there any problem occure.. please tellme sir..
dear haseeb sir, its not supposed to use a diode in a ct to measure current via oscilloscope???
kullanmış zaten !
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nek je alsh saVama
Walekum mus salam sir what have you shown
Thank you very much Sir