This is the guy that when send to count the number of horses in a herd counts the legs and divides by 4 instead of just counting the horses individually.
В Харьковском институте радиоэлектроники такие задачи решали устно. 1) Рисуется система координат, по горизонтали - реальные числа, по вертикали - i (мнимые). 2) Рисуем окружность с центром в начале координат и радиусом 2, поскольку а) 2 и -2 - очевидные ответы, б) поскольку уравнение шестой степени, то и корней будет шесть. И располагаться они будут на этой окружности симметрично (подобно вершинам шестиугольника, вписанного в окружность с радиусом 2. Гарвард отдыхает!
Why not use the radical sign.. (k^6)^(1/6)= (2^6)^(1/6) ; k=2 (removes both exponents 6 on both sides); or simply substitute by inspection algebraically.
A quadratic equation give two solution and the cubic equation give 3 solution totally we have 6 solition in cubic equation simply you use cubic squares of unity
Solve the equation : k⁵=2⁶. Rearrange the equation to give : (k/2)⁶ - 1 = 0 Let z =k/2, so we have: z⁶ - 1 = 0 This is a polynomial equation of degree 6 and so It has six roots. zᵣ. (r = 0,1,2,3,4,5). The 6 roots are: zᵣ= cos(2rπ/6) + isin(2rπ/6) r = 0,1,2,3,4 So the 6 roots are ±1, 1/2 ± i√(3/2), - 1/2 ± i√(3/2) . Recall, z=k/2 thus k=±2, 1± i√3, - 1±i√3. ,
@@Alamaths: I'm not a math teacher. I'm an Electrical Engineer, and did a lot of complex math for filter design. And, for fun, did exponentiation and logarithms with complex numbers.
So , a TUTOR says people don't need a tutor to tell how to solve it ? He is either trying to instil shame and guilt in you or he is trying to encourage a higher level of thinking in that year's intake of students
Divide both sides by 2^6 Sub x = k/2 Then it becomes a 6th roots of unity problem and the rest follows I don't think Harvard would assume the candidate not knowing Euler's formula...
π = 2 in the Riemann Paradox and Sphere Geometry System Incorporated... In English and Deutsch ... University 🎓🏫 Universal ♾️💍🔐 As same as Universe... That's means π= 2 in the Universe... So K can be Solved for 2 , -2 , π and -π (Real Number) + 4 Complex Number Solution
Hours is the best way of doing it. You could also see the solutions of +/-2, and divide k power 6 - 2 power 6 by k-2, then by k+2 and solve the remaing quyartic
@habeebalbarghothy6320 k belongs to all the possible solutions (complex and real solutions) because it is not stated in the problem whether to find real or complex solutions. ❤❤ Thanks for the comments
And 4 complex solutions ... the solutions are 2 times the six sixth roots of unity. so 2,-2,1+iV3,1-iV3,-1+iV3,-1-iV3 ... takes less than 1 second ... no need to write anything
Just to let you know that having the same power sensibility doesn't guarantee you/us the same base of reasonability. And more importantly, just to sharp your/our minds and that's the beauty of Mathematics. Thanks for the comments 👍
The answer is obvious. Not even a second is needed there. The solution resembles the government's efforts to deal with everything as long and complicated as possible.😂
@@Alamaths The secondary school where I studied 45 years ago was a physics-mathematics specialization. We were trained for simple solutions like in the army. By the way - if a task is given, then the = sign must be put all the time, even when continuing the solution in the next line!!!!
Yes. But they didn't specify whether k is real or complex. Just solve for both complex and real solutions. Thanks for the comments 👍 Are you a maths teacher 💖?
First of all, the question is very poorly asked and too vague. In what domain are we looking for the solution: Real Set (R), Relative Set (Z), Rational (Q), Complex (C), Natural Number (N), etc.? Also, this is a case of an equation with just one(1) unknown variable, k. It is a waste time going into these details.
Каждое алгебраическое уравнение степени n имеет ровно n корней- это теорема. Поэтому и корней должно быть ШЕСТЬ, а не только 2 и - 2. да устно мы знаем что 2 и - 2 это два корня, но нужно ещё 4 найти. +еще необходимо показать "решение" а не просто устно написать ответ, этого недостаточно например в экзаменах, важна решение, даже если неправильно решил, многие учителя в первую очередь смотрят на решение, метод - как ты решил, чтобы понять насколько ты знаешь про это.
@@Alamaths I'm not a teacher, and certainly not a maths teacher. Some people do crosswords to pass the time, others do soduku, but for me it's equations or inequalities.
Unless otherwise stated, you’re expected to get all the possible solutions for problems like this, which you just did. Most times, you may be asked to find only the real values. It is a crime to equate powers just like dat without considering the value. You can only do that after you must have worked out a problem and then you only need to apply the laws of indices to getting the final solution. Anyways kudos to you Man👏
I too had immediately the solution being 2 & -2 ! It is nothing boss ! Complex Number Solution is again a extension of the original solution only !! It is Just Nothing for someone Who attempts n clears JEE Advanced !! And Am Not One of Them !! Hahahahahaha
@@Alamaths Entiendo tu punto de vista. Toda ecuación puede resolverse de forma extendida o directa. Solo digo que para demostrar la necesidad de aplicar el esquema de solución que planteas hubiese sido interesante proponer dos variables, una de cada lado de la ecuación, o dos exponentes diferentes a los fes de obligarte a buscar una solución mediante el método matemático que planteas.
Yet another very bad YT maths video. Slow methods fail exams and competitions. As many other commentershave pounted out, this problem can be understood and then solved in about 20 seconds if you draw a circle in the complex plane.
Sluggish and basic steps stretched out time wise..constantly reminding us of very basic algebra ( second year high school algebra). These people are just plain gougers...wasting time for cash??
Love your “board” cleanliness and tidiness. I taught Math for 30 years, you surprised me.😢
Thanks for the comments 👍
Are you a professor of maths 💖?
Thanks for teaching me, great teacher, good math lesson
Thanks for the comments 👍
I'm glad you found it helpful. Are you a maths teacher? 💖
This is the guy that when send to count the number of horses in a herd counts the legs and divides by 4 instead of just counting the horses individually.
Great 👍. Thanks for the comments 👍
Where are you watching from 💖?
Excellent. In advance level, you are required to show exhaustive solutions for K.
Unlike ordinary level in which only real solutions are asked for.
Yeah. Thanks for the comments 👍
Are you a professor of maths 💖?
Six equally spaced points on the circumference of the circle of radius 2 in the complex plane. 2e^(i*n*(pi)/3 ) n=0 to 6
Great 👍. Thanks for the comments
Where are you watching from 💖?
n = 0 to 5
n=0,1,2,3,4,5 (6 solutions)
K=2*cis(n*pi/3)
if n=0 then K=2
if n=3 then K=-2
These are the 2 real solutions, the other 4 are complex.
n=1 to 6 as there are 6 solutions. n=0 gives the same solution as n=6
correction n=0 to 5, for a total of 6
Nice 👍
Thank you! Cheers!
В Харьковском институте радиоэлектроники такие задачи решали устно.
1) Рисуется система координат, по горизонтали - реальные числа, по вертикали - i (мнимые).
2) Рисуем окружность с центром в начале координат и радиусом 2,
поскольку
а) 2 и -2 - очевидные ответы,
б) поскольку уравнение шестой степени, то и корней будет шесть. И располагаться они будут на этой окружности симметрично (подобно вершинам шестиугольника, вписанного в окружность с радиусом 2.
Гарвард отдыхает!
Yes. But it has other complex solutions
Thanks for the comments 👍
Where are you watching from 💖?
K = 2cis(2nπ/6). Where n = 0,1,2,3,4,5
Great 👍. Thanks for the comments
Where are you watching from 💖?
Why not use the radical sign.. (k^6)^(1/6)= (2^6)^(1/6) ; k=2 (removes both exponents 6 on both sides); or simply substitute by inspection algebraically.
Okay. Thanks for the comments 👍
Are you a professor of maths 💖?
Great example, how to make science from the fact 2=2.
Wow, thanks for the comments 👍
Are you a maths teacher 💖?
Why are you not applying the exponential rule instead of bitting behind the bush. Answer is -2 or 2 a exp n = b exp n, therefore a=b
Yes. But it has other complex solutions.
Thanks for the comments. Are you a maths teacher 💖?
A quadratic equation give two solution and the cubic equation give 3 solution totally we have 6 solition in cubic equation simply you use cubic squares of unity
Great 👍. Thanks for the comments
Brilliant 🎉
Thanks 👍
Facilitaria respeitando a igualdade.
Yes. Thanks for the comments 👍
Are you a maths teacher 💖?
(K^6=2^6)^1/6=2; There for k=2
Great 👍. Thanks for the comments
Are you a maths teacher 💖?
Solve the equation :
k⁵=2⁶.
Rearrange the equation to give :
(k/2)⁶ - 1 = 0
Let z =k/2, so we have:
z⁶ - 1 = 0
This is a polynomial equation of degree 6 and so
It has six roots. zᵣ. (r = 0,1,2,3,4,5).
The 6 roots are:
zᵣ= cos(2rπ/6) + isin(2rπ/6)
r = 0,1,2,3,4
So the 6 roots are
±1, 1/2 ± i√(3/2), - 1/2 ± i√(3/2) .
Recall, z=k/2
thus k=±2, 1± i√3, - 1±i√3.
,
Great 👍. Thanks for the comments.
Are you a professor of maths 💖?
Wonderful 😊
For our next video.... if 2+2r4, what does 2+2 equal
Great 👍. Thanks for the comment
Where are you watching from 😘?
k⁶ = 2⁶
k = 2*cis (2*π*n/6) , n integer
= 2*cis(n*π/3) , n = 0, ±1, ±2, 3
= ±2, 1±i*√3, -1±i*√3
Yes. Thanks for the comments 👍
Are you a maths teacher 💖?
@@Alamaths: I'm not a math teacher. I'm an Electrical Engineer, and did a lot of complex math for filter design. And, for fun, did exponentiation and logarithms with complex numbers.
Dévide by 2⁶ and then put Z=e^2πi Θ= x/2 so that e^2πiΘ = 1= e^2πik.
Then u substitute k for 0,1,...5 and the rest is calculous.
Yes. Thanks for the comments 👍
Are you a professor of maths 💖?
Yep. At the University of Damascus. In the speciality of Symplectic Geometry and it's applications in the celestial mechanics.
Using de Moivre's formula, the answer is trivially 2cis(k\pi/3), 0
Great 👍. Thanks for the comments.
Are you a maths teacher 💖?
@@jiangchuYT A wrong and funny answer! Have a lot at it again. (Give you a hint: there are multiple mistakes)
What about check of complex roots? It’s the most interesting
Great 👍. Thanks for the comments. Are you a professor of maths 💖?
Solution by insight
2^6=(-2)^6
k=2. or k=-2
You got it. But k also has complex solutions. Thanks for the comments 👍
Where are you watching from 💖?
As my favorite teacher used to say, “isn’t it intuitively obvious?”
Thanks . Professor?
K=2
So , a TUTOR says people don't need a tutor to tell how to solve it ? He is either trying to instil shame and guilt in you or he is trying to encourage a higher level of thinking in that year's intake of students
❤
Thanks for the comments 👍.
Where are you watching from 💖 ?
@@Alamaths I am from Bangladesh
@@mustakahmed6225 Wow, thanks 😊
Divide both sides by 2^6
Sub x = k/2
Then it becomes a 6th roots of unity problem
and the rest follows
I don't think Harvard would assume the candidate not knowing Euler's formula...
Noted. Thanks for the comments 👍. Where are you watching from 💖?
@@Alamaths I'm from Hong Kong. Nice to see someone pay effort to explain maths to the public, keep it up🤜
What a hand job!!!
Thanks for the comments.
Where are you watching from 💖?
π = 2 in the Riemann Paradox and Sphere Geometry System Incorporated...
In English and Deutsch ...
University 🎓🏫 Universal ♾️💍🔐 As same as Universe...
That's means π= 2 in the Universe...
So K can be Solved for 2 , -2 , π and -π (Real Number)
+ 4 Complex Number Solution
Thanks for the comments 👍. Where are you watching from 💖?
Esqueceu totalmente as regras básicas da matemática da escola primária.
Regra da exponeciacao já dá a resposta de imediato.
Great 👍. Thanks for the comments
-2and2
Great 👍. Thanks for the comments
Where are you watching from 💖?
Ever heard of Ocham's razor?? PERFECT example
Yes. Thanks for the comments 👍
Are you a maths teacher 💖?
Las 6 soluciones (2 reales, 4 complejas) forman los vértices de un hexágono regular.
Yes. Thanks for the comments 👍
Are you a maths teacher 💖?
4 Complex Number in That Solution...
And K = 2 and (-2)... (Real Number)
Mucho más sencillo: son las seis raíces sextas de 64, todas de módulo 2 y argumentos, 0, 60, 120, 180, 240 y 300, como bien dice g414nk0.
Wow, thanks for the comments 👍.
Are you a professor of maths 💖?
Hours is the best way of doing it. You could also see the solutions of +/-2, and divide k power 6 - 2 power 6 by k-2, then by k+2 and solve the remaing quyartic
Yes. Thanks for the comments 👍.
Where are you watching from 💖?
As both sides have same exponent
k=2 , -2
Yes. It has other complex solutions and a real solution again (k=-2). Thanks for the comments 👍 🎉
Where are you watching from 💖?
@@Alamaths so you have to say that k belongs to complex numbers,
Or find all solutions
@habeebalbarghothy6320 k belongs to all the possible solutions (complex and real solutions) because it is not stated in the problem whether to find real or complex solutions. ❤❤
Thanks for the comments
And 4 complex solutions ... the solutions are 2 times the six sixth roots of unity. so 2,-2,1+iV3,1-iV3,-1+iV3,-1-iV3 ... takes less than 1 second ... no need to write anything
Yeah! Even powers yield positive numbers So -2 works by inspection too.
Ok. So what? Where can we apply that in daily life?
Just to let you know that having the same power sensibility doesn't guarantee you/us the same base of reasonability. And more importantly, just to sharp your/our minds and that's the beauty of Mathematics. Thanks for the comments 👍
2, obvious
Yes. K= -2 and other complex solutions. Thanks for the comments 👍
Are you a maths teacher 💖?
When power same ,then
Base equal k=2
Yes. But it has other complex and real solutions. Thanks for the comments 👍
Are you a maths teacher 💖?
This shows the standard of Harvard University.. such a simple problem.. I am sure the same person takes 1 hour to solve a=b/2, while b=10, what is a=?
Yeah, from your own perspective. Thanks for the comments 👍
Are you a maths teacher 💖?
NB: But it has other complex solutions
@@Alamaths No sir, I am a Radio Frequency Integrated Circuits designer
@@PSRao_1712 Wow, thanks 😊
Mnoho výpočtu pro nic. Z logiky věci K =2.
Good. Thanks for the comments 👍
Aplica logaritmo logo e tá raivoso em 1 linha
Are you a maths teacher 💖?
How come? I can't believe the ans!
Yes. Thanks for the comments 👍
Are you a professor of maths 💖?
As it is an equation of degree 6, it has 6 solutions..needs to find all six roots...2 are real and 4 imaginary/complex roots.
Great 👍.
Thanks for the comments.
Where are you watching from 💖?
Do it in your head in 15 seconds in complex polar coordinates
Thanks 👍. Are you a maths teacher 💖?
ln (k^6)= ln(2^6); ; i,e 6 ln k= 6 ln2 ; ln k= ln 2 ; i,e k=2. 2nd Method k^6=64 ; i,e (k^3+8)(k^3-8)=0 ; i,e (k+2)(k^2-2k+4)(k-2)(k^2+2k+4)=0 ; k= -2 or k=2 or k= 1+√3i or k= 1-√3i or k= -1+√3i or k= -1-√3i where i=√(-1)
Great 👍. Thanks for the comments
Are you a professor of maths 💖?
@@Alamaths No
@@subratabiswas2502 okay. Thanks
Grat.😁
K^6=2^6
K=2
Great 👍. Thanks for the comments
Where are you watching from 💖?
Long process
Since the powers are the same k = 2
Great. But it has other complex and real solutions.
Where are you watching from 💖?
2 e^(i*pi/3)?
Yeah. Thanks for the comments 👍
Where are you watching from 💖 👀?
This simple k= 2
The answer is obvious. Not even a second is needed there. The solution resembles the government's efforts to deal with everything as long and complicated as possible.😂
Wow, thanks for the comments 👍
Are you a professor of maths 💖?
@@Alamaths
The secondary school where I studied 45 years ago was a physics-mathematics specialization. We were trained for simple solutions like in the army. By the way - if a task is given, then the = sign must be put all the time, even when continuing the solution in the next line!!!!
Wow 👌. Thanks 👍
Imagine some solutions are complex…
Somebody should say somewhere whether K is real or complex.
Yes. But they didn't specify whether k is real or complex. Just solve for both complex and real solutions. Thanks for the comments 👍
Are you a maths teacher 💖?
Am I gifted child if I calculate this whole thing in my mind withing 8 minute. (Bcz video took 10 min.clearly I was faster ) 🤭
Great 👍. Thanks for the comments.
Where are you watching from 💖?
Зачем это вообще считать, если очевидно, что к=2 и к=-2,так как степень чётная?
Great 👍. Thanks for the comments
Where are you watching from 💖?
Just look at the original K^6 = 2^6, immediately know that K=2. Why make things so complicated???
Prof. It has other complex and real solutions.
Thanks for the comments 👍.
Where are you watching from 💖?
I’ve found solution in a nanosecond
Okay. Thanks for the comments.
Where are you watching from 💖?
NB: it has other complex and real solutions.
@@Alamaths Sicily
Whatttt... I knew that the answer was 2 and -2 in three second... It is just to see the ecuation
Great 👍. Thanks for the comments
how is breaking that down relevant to real world situations?
Great 👍. Thanks for the comments
Thanks for the comments 👍
Where are you watching from 💖?
0=1222 ext.
Great 👍. Thanks for the comments.
Are you a maths teacher 💖?
lnk = ln2; k =2
Great 👍.
Thanks for the comments
Where are you watching from 💖?
@@Alamaths Serbia
Chào giáo sư tương lai thời 10.1
Oh, thanks for the comments 👍
Are you a teacher of maths?
К равен 2
K=2 ose -2
Yes. Thanks for the comments
Where are you watching from 💖?
A first grader would have solved the problem in an eye beat.
😂
Great 👍. Thanks for the comments
Where are you watching from 💖
isn't obvious that K=+/-2?
Yes. But it has other complex solutions. Thanks for the comments 👍
Where are you watching from 💖?
K= 2/-2
Great 👍 . Thanks for the comments.
Where are you watching from 💖?
se ho lo stesso esponente in una uguaglianza avrò lo stesso argomento : K = 2
Great 👍. Thanks for the comments
Are you a maths teacher 💖?
k=+ 2
-
Good. Thanks for the comments 👍
Are you a maths teacher 💖?
K=2
Yes. But it has other complex and real solutions. Thanks for the comments 👍
Where are you watching from 💖?
@@Alamaths india 🇮🇳 ♥️
Sixth order equation has six roots.
Это 1 из 6 корней, нужно еще 5 найти ))).
А их можно найти только решив уравнение полностью
First of all, the question is very poorly asked and too vague. In what domain are we looking for the solution: Real Set (R), Relative Set (Z), Rational (Q), Complex (C), Natural Number (N), etc.? Also, this is a case of an equation with just one(1) unknown variable, k. It is a waste time going into these details.
Okay 👍. Thanks for the comments.
Are you a maths teacher 💖?
by exponantional equation
k=2
log k^6. =log. 2^6
6 log k= 6 log 2
log k= log 2
k= 2😂😂😂
Yes. But it has other complex solutions.
Thanks for the comments 👍
Where are you watching from 💖?
My God, and this is the simple Harvard University Admission ? It´s obvious that K = 2 not necessary to do any operation.
Yes. But it has other complex solutions
Thanks for the comments 👍
Where are you watching from 💖?
Balderdash
Great. Thanks for the comments
K= /2/
Great 👍. Thanks for the comments
Where are you watching from 💖?
A=2 then 2= ... Howmuch. Only Harvard university people can answer. Non other.
Yes. But it has other complex solutions. Thanks for the comments 👍
Where are you watching from 💖?
2
Yes. But it has other complex and real solutions. Thanks for the comments 👍
Where are you watching from 💖?
Решение этого уравнения похоже на объяснение "чёрного квадрата" Малевича, т.е. возведение бессмыслицы в абсолют.
Yes. Thanks for the comments 👍.
Where are you watching from 💖?
Каждое алгебраическое уравнение степени n имеет ровно n корней- это теорема.
Поэтому и корней должно быть ШЕСТЬ, а не только 2 и - 2.
да устно мы знаем что 2 и - 2 это два корня, но нужно ещё 4 найти.
+еще необходимо показать "решение" а не просто устно написать ответ, этого недостаточно например в экзаменах, важна решение, даже если неправильно решил, многие учителя в первую очередь смотрят на решение, метод - как ты решил, чтобы понять насколько ты знаешь про это.
This is painful. You can see that k= 2 or -2
Thanks 👍. Where are you watching from 💖?
😂😂😂😂 k=2 that's it sir
देखने से पता चलता है k=2 या-2
Yes. Thanks for the comments 👍
Where are you watching from 💖?
Uh, a mountain out of a mole hill?
Thanks for the comments 👍.
Where are you watching from 💖?
k⁶ = 2⁶
k⁶ - 2⁶ = 0
(k³)² - (2³)² = 0 → recall: a² - b² = (a + b).(a - b)
(k³ + 2³).(k³ - 2³) = 0 → recall: a³ + b³ = (a + b).(a² - ab + b²)
(k + 2).(k² - 2k + 2²).(k³ - 2³) = 0 → recall: a³ - b³ = (a - b).(a² + ab + b²)
(k + 2).(k² - 2k + 2²).(k - 2).(k² + 2k + 2²) = 0
(k + 2).(k - 2).(k² - 2k + 4).(k² + 2k + 4) = 0
(k + 2).(k - 2).(k² - 2k + 2²).(k² + 2k + 4) = 0
First case: (k + 2) = 0
k + 2 = 0
→ k = - 2
Second case: (k - 2) = 0
k - 2 = 0
→ k = 2
Third case: (k² - 2k + 4) = 0
k² - 2k + 4 = 0
Δ = (- 2)² - (4 * 4) = 4 - 16 = - 12 = 12i²
k = (2 ± i√12)/2
k = (2 ± 2i√3)/2
→ k = 1 ± i√3
Fourth case: (k² + 2k + 4) = 0
k² + 2k + 4 = 0
Δ = (2)² - (4 * 4) = 4 - 16 = - 12 = 12i²
k = (- 2 ± i√12)/2
k = (- 2 ± 2i√3)/2
→ k = - 1 ± i√3
Wow. I don't, but I respect 💯 . Thanks for the comments 👍.
Are you a professor of maths 💖?
May I have your contact information?
@@Alamaths I'm not a teacher, and certainly not a maths teacher. Some people do crosswords to pass the time, others do soduku, but for me it's equations or inequalities.
@@key_board_x thanks. May I have your contact number?
Yes but just use (r(cost + isint))^n = r^n. (cosnt + isinnt)
Do not use decimal points for multiplication. Parentheses up against each other is sufficient for multiplication.
Unless otherwise stated, you’re expected to get all the possible solutions for problems like this, which you just did. Most times, you may be asked to find only the real values. It is a crime to equate powers just like dat without considering the value. You can only do that after you must have worked out a problem and then you only need to apply the laws of indices to getting the final solution. Anyways kudos to you Man👏
Yes. Thanks for the comments 👍 🙂
Where are you watching from 💖?
@@Alamaths you’re welcome sir! I’m watching from Auchi, Edo State.
"Dat" is not correct. Write in correct English.
@@robertveith6383 are you referring to me or someone else?
Long process wrong
Thanks. But it has other complex solutions.
Are you a maths teacher 💖?
2，2，2i,-2i
Yes. Thanks for the comments 👍. Are you a professor of maths 💖?
2i and -2i is Wrong ...
Для интересующихся математикой совсем нет необходимости расписывать разность квадратов. Скучно.
Noted. Thanks for the comments 👍
Are you a maths teacher 💖?
Caша, пиши отв.
it is showing that k=2, why r u calculating. r u mad
OK 👍. Thanks for the comments
Are you a maths teacher 💖?
I too had immediately the solution being 2 & -2 !
It is nothing boss !
Complex Number Solution is again a extension of the original solution only !!
It is Just Nothing for someone Who attempts n clears JEE Advanced !!
And Am Not One of Them !!
Hahahahahaha
Okay. Thanks for the comments 👍
Where are you watching from 💖?
@@Alamaths JEE Advanced Google it 😅
@@Alamaths N where you are from ??
You're kidding ? Solving this equation and writing the 6 complex solutuons takes less than 1 second by mind
Great 👍. Thanks for the comments. Are you a maths graduate 💖?
Indeed. Presumably the idea of using rotation and scaling in the complex plane is beyond the standard he is aiming at.
@rogerphelps9939 yes. Thanks for the comments 👍 ❤🎉
Less than 1sec? What second left? .99999😅
Exactly:same exponent same base
it´s 2, the answer is 2 ffs
Yes. But it has other complex solutions. Thanks for the comments 👍
Are you a professor of maths 💖?
😅к не равно 2❓❗
Yes. But it has other complex and real solutions. Thanks for the comments 👍.
Are you a professor of maths 💖?
K es 2 desde el principio. El desarrollo de toda esa lógica es una estupidez.
OK 👍. Thanks for the comments.
But it has other complex solutions
Are you a maths teacher 💖?
@@Alamaths Entiendo tu punto de vista. Toda ecuación puede resolverse de forma extendida o directa. Solo digo que para demostrar la necesidad de aplicar el esquema de solución que planteas hubiese sido interesante proponer dos variables, una de cada lado de la ecuación, o dos exponentes diferentes a los fes de obligarte a buscar una solución mediante el método matemático que planteas.
Yet another very bad YT maths video. Slow methods fail exams and competitions. As many other commentershave pounted out, this problem can be understood and then solved in about 20 seconds if you draw a circle in the complex plane.
Wow, thanks for the comments 👍
Where are you watching from 💖?
The answers other than 2 and -2 are imaginary and are an example of why mathematicians are nuts.
Great 👍. Thanks for the comments
Where are you watching from 💖?
Лошо записване. Слагайте дробната черта срещу равенството, а не надолу.
Видими неща обяснени сложно.
Good. Thanks for the comments 👍
Sluggish and basic steps stretched out time wise..constantly reminding us of very basic algebra ( second year high school algebra). These people are just plain gougers...wasting time for cash??
Great 👍. Thanks for the comments.
Are you a maths teacher 💖?
К=2
Yes. But it has other complex and real solutions. Thanks for the comments 👍.
Where are you watching from 💖?
Please your method is too long
OK. Thanks for the comments 👍
Where are you watching from 💖?
高校1年生レベルの問題
Thanks for the comments 👍
Are you a professor of maths 💖?
Borra este video. Es muy simple la respspuesta. 2=2
Why? But it has other complex solutions
Thanks for the comments 👍
Are you a maths teacher 💖?
i lost interest
Oh o, thanks for the comment 👍
And where are you watching from 😘?