Wow thank you so much! This helped me understand this so much better. A lot of ochem material I've seen speeds past this but you take it nice and slow. I super appreciate it and I feel much better about this!
yes due to resonance (conjugation) and also due to a hydrogen bond between the keto and enol group. The keto-enol tautomer has 76% appearance. I think he made a little mistake there.
@Nissipriya Anandhakrishnan he means bond dissociation enthalpy ( which is basically the energy required to break a bond) more energy is required to break a strong bond like c=o as compared to the c=c bond hence in most cases (not every case)the keto form is more stable than the enol form
@@chitranshjawere4953 yeah but he is referring to bond dissociation energy which is negative so what more in magnitude is lesser You get the point right but your statement is correct stability and energy arr inversely related
@@metroidfan77yes65 but why that c double bond carbon is more stable than c double bond oxygen? I cannot relate this point as my teacher also has told the same
how does the H3O+ not get consumed here i don't understand.. it is first transformed to H2O then again to H3O+, why is this not a consumption? (sorry just started my studies)
After the reaction you find the H3O+ in the same form as it was before the rxn, so even though it is used in the reaction, it isn't consumed permanently and you get is back in it's original form so basically it is used to speed up the process, and that is the definition of catalysts: they are the substance that increases the rate of a reaction without itself being consumed. we get them back in the final product. i might be wrong since i'm also a student.
@@ihaveagoal4665 U are correct ! The amount of h30+ used for reaction is gotten back after the reaction so it can be cancelled out as being on reactant side of first reaction and on product side of second while practically performing experiments it always seems that the h30+(or anything else in similar situation) isn't even used and just acted as a catalyst
it doesn't matter the time all the matter is that you are understanding the mechanism ,well I do not feel that the professor is in hurry all he is care about that we are receiving the information correctly
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isko dekhne ke baad tu air 1 aur main air 2 😁
air 1,2 k liye practice bahut chaihe bhai but concept wise ye channel really acha smjha rha h @@yaminyaminyaminn
Kya hua Bhai kitne number aaye,plz reply
Main bhi prepare ho rha hu jee ke liye is channel se this guy is far more better than others,he is providing free content 😅
you deserve a Nobel Prize
😂😂😂😂
Finally someone could explain this thing properly...thanks!
I'll give you a shout out after I pass this exam, thanks brah.
which exam.. !! NEET?
@@ipshita792 not likely he is not an Indian
Bro failed
@@cashboys-j9m 😂 lol
did you pass the exam?
this is so helpful!!! i was so confused, and couldn't find any information i needed to understand in other places
Thanks! Im studying using your amazing videos before the exam. If I pass, ill give you another $10 😂🎉
whether u passed bro
you passed bro?
Guys, I passed. GOOD LUCK EVERYONE
I wouldn't understand stuff if it weren't for your videos. Thank you!!
Thank you. Im in med school in Germany. Helped me a ton
May I know that why acetone is much more stable than it's enol form??
Wow thank you so much! This helped me understand this so much better. A lot of ochem material I've seen speeds past this but you take it nice and slow. I super appreciate it and I feel much better about this!
Great videos thanks from Egypt
isn’t my man the GOAT?
YES SIR HE IS THE GOAT
Good explanation
The enolic content in acetyl acetone is 75%-76%
Coreect
This is helpful, thank you.
Bro's savior
This guy is awesome 😎
Best teacher
It helped me a lot .
😘😘😘
where do u study?
India
thank you mark whalberg
amazing ........
Is phenol shows ketoenoltautomer
I passed my exam, y'all! Good luck!
OMG YES!!
Yeah!!!
at 2:50, isn't the major product 2,4 pentadione (acetylacetone) due to conjugation.
yes due to resonance (conjugation) and also due to a hydrogen bond between the keto and enol group. The keto-enol tautomer has 76% appearance. I think he made a little mistake there.
GREAT VIDEO
Can both the ketone undergo enolization?
Thank uu sooooo much sir ji
Good one
Great video
Thank you
thank u so much ..
This is brief👍😊
Does anyone know WHY enols are unstable?
Bond energy(C=O) >Bond energy(C-O)
This makes keto form more stable as compared to enolic form.
@Nissipriya Anandhakrishnan Energy is inversely related to stability . More energy in a substance,the less stable it is.😄
Might be,Enols form enolate ion where the -ve charge on oxygen atom made it reactive towards a reaction,destabilising the enol structure..
@Nissipriya Anandhakrishnan he means bond dissociation enthalpy ( which is basically the energy required to break a bond) more energy is required to break a strong bond like c=o as compared to the c=c bond hence in most cases (not every case)the keto form is more stable than the enol form
@@chitranshjawere4953 yeah but he is referring to bond dissociation energy which is negative so what more in magnitude is lesser
You get the point right but your statement is correct stability and energy arr inversely related
thanks a lot
Pharmacy student is here✊
Why acetone is more stable than it's enol form? Plz explain I am in big trouble 🙏
Because a carbon-oxygen double bond (ketone) is more stable than a carbon-carbon double bond (enol).
@@metroidfan77yes65 but why that c double bond carbon is more stable than c double bond oxygen? I cannot relate this point as my teacher also has told the same
I guess it's because of the electronegativity difference. There is a partial negative charge on O and a partial positive charge on C.
@@metroidfan77yes65 ohk thanks
Nice....
Thank u very much sir
Thanks man
What does stability mean?
I laughed for a second and then thought ......he is joking right?
Are you?
Good question
Stability means the tendency to resist any change in structure due to external force
Thank u 😊
Why actylacetone is 70% enolic)
❤️
👑👑👑
how does the H3O+ not get consumed here i don't understand.. it is first transformed to H2O then again to H3O+, why is this not a consumption? (sorry just started my studies)
After the reaction you find the H3O+ in the same form as it was before the rxn, so even though it is used in the reaction, it isn't consumed permanently and you get is back in it's original form so basically it is used to speed up the process, and that is the definition of catalysts: they are the substance that increases the rate of a reaction without itself being consumed. we get them back in the final product.
i might be wrong since i'm also a student.
@@ihaveagoal4665 U are correct !
The amount of h30+ used for reaction is gotten back after the reaction so it can be cancelled out as being on reactant side of first reaction and on product side of second
while practically performing experiments it always seems that the h30+(or anything else in similar situation) isn't even used and just acted as a catalyst
Thank you sooooooooooooooooooooooooo much sir
:)
need a new mic
😖😖
If u speak a bit faster u can cover more and will cost less time
I always play his videos at 1.25 or 1.5 speed. I hope this helps
This is exactly why people can't have nice things.
it doesn't matter the time all the matter is that you are understanding the mechanism ,well I do not feel that the professor is in hurry all he is care about that we are receiving the information correctly
thank you