21.1 Acidity of the Alpha Hydrogen | Organic Chemistry

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  • เผยแพร่เมื่อ 28 พ.ย. 2024

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    • @ChadsPrep
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      Glad to hear it, Bellerie Art - you're welcome!

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    • @ChadsPrep
      @ChadsPrep  ปีที่แล้ว

      Glad they helped you!

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    • @ChadsPrep
      @ChadsPrep  ปีที่แล้ว

      Awesome to hear this :) happy studying!

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    @gitudegefa5007 3 ปีที่แล้ว +4

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    • @ChadsPrep
      @ChadsPrep  3 ปีที่แล้ว

      Right back at you Gitu! :)

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    @MOHAMMADMURSALEEN-eq6ir ปีที่แล้ว +1

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    • @ChadsPrep
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  • @oliviaevans2961
    @oliviaevans2961 11 หลายเดือนก่อน

    Hi Chad! First of all, thank you so much for all of your videos. They are incredibly helpful! I have a question regarding reactions involving carboxylic acid derivatives and BH3 and THF. In one of your videos, you mentioned that there is something to be aware of, but it wasn't too important. However, we are now being asked about it in class, as apparently, it turns a carboxylic acid and ester into a cyclic structure. Could you please clarify what this is and why it is important to know? Thank you so much in advance!

  • @peybak
    @peybak 3 ปีที่แล้ว +4

    Thanks for the video. I want to ask why is it that during acid catalyzed tautomerization, your base doesn't simply deprotonate your protonated oxygen instead of the alpha carbon? I can't find a good answer actually.

    • @ChadsPrep
      @ChadsPrep  3 ปีที่แล้ว +3

      Great question Peyman! It is actually more likely to be deprotonated at the oxygen than the alpha carbon which would just simply convert it back to its keto form rather than to the enol form. If you look back at the mechanism equilibrium arrows are used throughout and I give a reminder that most of the time the keto form is more stable than the enol form and is favored in the equilibrium. So the enol will be the nucleophile in a couple of acid-catalyzed reactions in this chapter, but it is typically only formed in small concentrations while in equilibrium with the keto form. Hope this helps!

    • @peybak
      @peybak 3 ปีที่แล้ว +2

      @@ChadsPrep I appreciate the response Chad! I think I came up with the same conclusion you mentioned. If a base deprotonates the oxygen, then there is no enol! Thank you for the concise videos.

  • @AdityaSingh-ox7ni
    @AdityaSingh-ox7ni ปีที่แล้ว

    hey don't you think that in the first step the carbanion is more stable at 1 degree rather than the 2 degree one?, considering that doesn't 2nd product should be more stable? 5:17

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    @abhinavnallapati5038 7 หลายเดือนก่อน

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    • @ChadsPrep
      @ChadsPrep  7 หลายเดือนก่อน

      Glad to hear it!

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    • @ChadsPrep
      @ChadsPrep  ปีที่แล้ว

      Glad the channel/videos are helping!