Two more of my papers, recordings of my live sessions, worked solutions and video solutions all can be found here: www.tickettailor.com/events/mrastburymaths/1291828
shouldn't the frictional force be going down the plane in question 12b since the horizontal force is holding the particle in equilibrium so friction opposes that? great video though thank you!
Sir, you are reaching prime R9 levels in the A-Level Maths world. Keep it up and you will definitely reach 🐐 status. You even have the work rate and defensive discipline of Maldini, making predicted papers 24/7, single handedly saving A-Level Maths. Unbelievable.
for q7 do you have to use the z value, or can you just do inverse normal using the mean and varience you cancluted becuase i ended up with the same answer
hi sir in Q5b why don't you use the critical value this time to compare the difference in the probability rather than using the significance level BTW great Video!!
Friction is acting up the slope because the question wants us to find the minimum value of X, this is found when X is doing the least amount of work to hold the particle in equilibrium and friction is doing the most amount to hold it in place.
If a smaller force of X acts on the ball, the ball will "fall more" so to maintain equilibrium the friction would have to act up the slope. "Smallest possible value" hints that equilibrium would be maintained.
you arent considering the man, just the forces on the ladder. the ladder doesnt feel the reaction only the man does, but we arent considering the man, only what the ladder feels.
Commented a few days ago saying how good it is that there are no mistakes in these papers. However, I do think there might be a slight slip in question 2? Surely, the median log is the 44.5th log not the 44th, because the midpoint of 0 and 88 is 44.5 not 44. For example, the midpoint of 4 items is not the second one, because then there would be 2 greater than it and only one less, it's actually the 2.5th one. I'd appreciate confirmation on this. Thanks.
@@MrAstburyMaths Thanks. What's strange is that there do seem to be a number of questions in the official Edexcel textbook which go against that reasoning though. For example, in mixed exercise 3 year 1, question 6, they clearly find the 25.5th result out of 50 in the solution bank despite it being continuous data. Likewise, example 3 in chapter 2 year 1 also clearly uses the 35.5th result out of 70 even when the data intervals are continuous. Do you think all these questions in the textbook are mistakes? Thanks.
@@jameskonefal3453 hi, how strange, thanks for digging deeper into this. I have checked the mark scheme (Edexcel International June 2022 S1 Q4) and they accept both choosing 44th or 44.5th. Interestingly they say 44th giving 23.57 is correct and that they allow 44.5th giving 23.64. I don’t know what to believe now!! Lol
Thank you for the paper!!! It’s been great prep. For the last part of question 11, wouldn’t we have to round up our value of h to 4.09 (3sf) since we need |v| to be strictly less than 10?
for stats question 7b, i didnt use the standard normal, i used inverse normal with the approximation and distribution the same as you did, and then i got n-0.5= 44.527, hence n=45.027 and hence n = 45, is that ok or do i have to use the standard normal?
For Q8 part b, Cant we use the Area Under the Graph equation to find "t". I did this but I get t = 10s - which is different to your answer in which you use SUVAT.
What should the answer to 13d be? Should it be along the lines of how all the potential energy is being transferred to kinetic energy, and none is lost as friction to the pulley. Thanks in advance :)
hii, just asked my teacher this and he said that because a smooth pulley means no resistance to motion (friction) , then the markschemes will look for “we are assuming that the tension of A and B are the same” i hope this helps and best of luck with your exam next week!!
Yo how do i know when to do the boundary + or - 0.5 for a frequency table? I was confused because the logs have length which i thought would be continuous
31:20. Hi I’m confused how come you add the probability of 2 and 4 to get 1/3 rather than timesing their probabilities) sorry probably very silly questions but I’ve left this revision a bit last minute haha)
Because 1/3 is the probability of selecting an even number which is the same as selecting 2 OR 4 so you add. Timesing probabilities is if you had 2 AND 4
@@mdlxni7236 because in part b there is friction acting in the same direction as x. The object is still in equilibrium so forces are still balanced so x must be smaller(as the friction contributes to balancing weight)
Hey Mr Astbury, for question 5c, would you get the marks for inputting x as 0 and probability of 0.1 then doing trial and error on the n value until you get a percentage less than 0.01? thanks
the probability of failing the bounce test is 0.1 and it says none fail so we need to find the probability of not failing. so the probability of not failing is 1-0.1 which is 0.9.
I’ve made another 2. I will be using them in my live sessions this weekend. You can sign to the Sunday one. There is literally only 1 space left though!
i think it's just: if the pulley weren't smooth, there would be friction done by the string on the pulley, which we would have to consider when making calculations. we assume it's smooth so we don't have to make it all so complicated. something like that, but I'm not sure exactly ???
i know this isnt part of the question, but for q9, what does the displacement/time graph actually look like? can you tell from the vectors in the question? i just cant see what the motion of the particle will be like and its confusing me bc it seems to be in all different places relative to the origin
@@slyaiming when would it not be negligible? So then why is it that when you're working out stuff with an item on a slope, the reaction force isn't negligible? Thanks!
@@Sam-qs4vx Here, we are looking at force acting on the ladder, the reaction force you are talking about is acting on the person, so is not considered. On a slope, we are looking at the forces on (e.g.) a ball, so the forces it experiences will come from the slope itself, as well as its own weight.
@@Sam-qs4vx In this question it specifies that you're finding the "force exerted on the ladder" but if it doesn't state that, then you can add reaction forces.
is linear regression - from Q1, something that can come up in edexcel paper3? Its not difficult now i know how to do it but I have never seen it before?
At 43:38 where does the 0.9 come from? Why can't we use the tables in the formula book (which gets a value of n=50) is it because it skips the n values between 40 and 50 so isn't accurate?
@alaziziomar_ Yepp I know :) Had such a good teacher for 1st year who taught us half of pure and all of mechanics but then she retired and we've had the worst teacher ever trying to teach us the rest of pure and all of stats so yeah I don't get stats
Dunno if you’ve figured it out yet, but the 0.9 comes from the fact binomials have a fixed probability of success & two fixed outcomes (success and failure). Since the probability of failure is 0.1, the probability of success is 1 - P(Failure), hence 0.9.
Look at ‘v’. That’s in bold. ‘F’ is also in bold. So we can assume we are writing in i and j form, as v (bold) is in i and j. If it had the modulus sign/said ‘magnitude’, then we would find the magnitude
quick question, how do you know if you should leave answers in i,j form, or on top of each other in brackets sort of vector form for vector questions? or does it not matter?
Hello, I have a very important question and really need a respond🫣Are the A Level tricky questions from youtube channel suitable for A Level Edexcel board??Wising everyone sunny and well deserved summer!👍
Hi! For this question I did: 0.13+0.25+p+q+r+s = 1 so p+s+q+r = 0.75 (EQ1) // (q)/(q+r) = 0.6 so q = 1.5r (EQ2) // and 0.13+p+s = 0.7 so 0.57= p+s (EQ3) -> if you sub in EQ3 & EQ2 into EQ1 this will give you r (0.072) and then you can find q because q = 1.5r -> I hope that helps :)
At 49:55 how do you know when to use that for of standard deviation/variance ? Like how come it isn’t just 28? Oh and at 51:10 how come you square rooted the variance in the calculation? Ps, I know this is a stupid question, but I’ve literally never been told why, lol, so it always confuses me. Thank you 😃
whenever you do a hypothesis test with the normal distribution you always keep the mean the same and change the standard deviation (so do this only when youre about to attempt a hypothesis test question with *normal* D) he square rooted the variance because when you use the calculator you have to put in the mean and the standard deviation (square rooting the variance gives standard deviation) hope that helps 💝
Two more of my papers, recordings of my live sessions, worked solutions and video solutions all can be found here: www.tickettailor.com/events/mrastburymaths/1291828
shouldn't the frictional force be going down the plane in question 12b since the horizontal force is holding the particle in equilibrium so friction opposes that? great video though thank you!
cheers boss
can we all collectively pray that a question simular to q4 is not coming up tomorrow
Right cause wtf
It came up💔
watching this on 2x as i eat breakfast 2 hours before the exam is peak
same :')
bae wake up, final astbury paper just dropped
The fact that i was waiting for this video and looking for this comment
@@Thorfinn.05 🤣🤣🤣🤣
Sir, you are reaching prime R9 levels in the A-Level Maths world. Keep it up and you will definitely reach 🐐 status.
You even have the work rate and defensive discipline of Maldini, making predicted papers 24/7, single handedly saving A-Level Maths. Unbelievable.
this guy is the goat
I think of you when I goto sleep
I think we all do the same
😭😭😭😭😭😭
Real
Mr Astbury on a better run than '09 Barca
My test is in 2.5 hours, lets smash this!
Real we got this
@@connorjhuk im sure i failed lmao
@@ignedeo3811 tbh idk how I feel about it, statistics went well in the end... Unlike mechanics, which is weird cause I'm better at mechanics usually.
@@ignedeo3811 either way is what it is
Mr Astbury you're great but there is no way I'm gonna even attempt question 4
if any of u lot got qs 4 in ur first try ur not human
🤖
I'm cremated
edit 20/5 12:55: THIS PAPER IS ACTUALLY GONNA DEEP FRY ME I'M SO SCREWED WTF
Sym
1:02:33 bros avoiding the boy's name is so funny to me 🤣
💯
These papers are excellent. It's extremely rare to find online resources with no mistakes in them!
THE KING IS HERE! 👑
What i would do without Goatsbury i do not know
who else is cooked after bio today
Yes, it was good
me i’m utterly done for Mate
LETS GET TRIGGY WITH IT
type shiiiiiiiii
Seen so many people in my college library watching ur vids , ur a legend
Awesome! Tell them to subscribe! 😀
Anyone else here a few hours before the exam? 😂
Ye bro, good luck for you)
Love that u made this paper challenging! Thanks alot Mr Astbury!!!
My pleasure 😊
@@MrAstburyMaths cute
@@rory1487 he won't let you hit
I love how he says perfect after every question
Can I just say that i love youuu and sooo many of your questions came up today so thank you so much saving my grade frr
UR THE GOAT I GOT SO MANY MARKS THANKS TO YOU 🐐🐐
last hr im here
God bless this sweet man 😭💖
35:37 if you skipped q4 to watch the solution like me well done
I managed to get it with a very long winded method.
do you want a medal mate?
@ravjayakodi2746 atleast they tried it. They deserve an applause
for q7 do you have to use the z value, or can you just do inverse normal using the mean and varience you cancluted becuase i ended up with the same answer
Fr man , I also used inverse normal
for q7 part b why do u have to use the z distributuion when you already have your mean and sigma
I’m confused for Q2, why isn’t the height 20/3, because applying the same logic used to get the width wouldn’t give 5.6cm
hi sir in Q5b why don't you use the critical value this time to compare the difference in the probability rather than using the significance level BTW great Video!!
Both methods are correct and will get you full marks, and this way is easier imo but doesn’t work for all cases
in q2b the median is between the 44th and 45th value so shouldnt you have taken 44.5 instead of 44 giving 23.64 instead of 23.57 as the answer??
you only do that for discrete data sets, this is continuous so you just half the frequency instead of adding one and then halving like you did
will friction not act down the slope in 12)b)
i thought this too
Yeah i think he got it wrong idk I don’t know how it would be acting up the slope alongside the other force too
Friction is acting up the slope because the question wants us to find the minimum value of X, this is found when X is doing the least amount of work to hold the particle in equilibrium and friction is doing the most amount to hold it in place.
If a smaller force of X acts on the ball, the ball will "fall more" so to maintain equilibrium the friction would have to act up the slope. "Smallest possible value" hints that equilibrium would be maintained.
100% needed icl
The same probability question came up as the last question of stats 2024 best believe I got full marks
1:45:01 How come there is no reaction force from the ladder on the man?
yeah that's what i thought as well
you arent considering the man, just the forces on the ladder. the ladder doesnt feel the reaction only the man does, but we arent considering the man, only what the ladder feels.
You are the best. You are literally the goat. Thank you very much sir for all the amazing help and support. ❤
Question 7b) we have the mean and standard deviation, so can't we just use inverse normal with these values instead of standardising
Do you get the same answer? If so yes the method is good! If not, then it ain’t!
@@MrAstburyMaths I think you do 😅😅 in theory it should work shouldn’t it?
@@MrAstburyMaths yh thats what i did as well and i got 45
I found 44 balls in 5c using trial and error with different N values until probability fell under 0.01, would I get any marks?
No
Very good explanations!
Commented a few days ago saying how good it is that there are no mistakes in these papers. However, I do think there might be a slight slip in question 2? Surely, the median log is the 44.5th log not the 44th, because the midpoint of 0 and 88 is 44.5 not 44. For example, the midpoint of 4 items is not the second one, because then there would be 2 greater than it and only one less, it's actually the 2.5th one. I'd appreciate confirmation on this. Thanks.
Using linear interpolation with the 25.5th log would then give the slightly different answer of exactly 23.6 cm.
They are continuous data intervals so you use 88/2 = 44 for the median. The method in the video is correct 👍
@@MrAstburyMaths Thanks. What's strange is that there do seem to be a number of questions in the official Edexcel textbook which go against that reasoning though. For example, in mixed exercise 3 year 1, question 6, they clearly find the 25.5th result out of 50 in the solution bank despite it being continuous data. Likewise, example 3 in chapter 2 year 1 also clearly uses the 35.5th result out of 70 even when the data intervals are continuous. Do you think all these questions in the textbook are mistakes? Thanks.
@@jameskonefal3453 hi, how strange, thanks for digging deeper into this. I have checked the mark scheme (Edexcel International June 2022 S1 Q4) and they accept both choosing 44th or 44.5th. Interestingly they say 44th giving 23.57 is correct and that they allow 44.5th giving 23.64. I don’t know what to believe now!! Lol
for question 7 couldnt u have just used inverse normal to find P(x
For 13c why can't we do R= 2Tcos(90-a /2) - I thought thats how you calculate the reaction on the pulley?
Thats also the way the textbook says to do it, so confusing
I know i used this way and got a completely different answer to him
09:16 where does the 15 logs come from?
The frequency is equal to the number of logs with that class of length. Hope this helps
Thank you for the paper!!! It’s been great prep. For the last part of question 11, wouldn’t we have to round up our value of h to 4.09 (3sf) since we need |v| to be strictly less than 10?
for question 7 can you use inverse normal and put prob as 0.0239 it rounds up to n=45 ?
I thought this too
Yeah I think you can
it might be because it is a show that question so you can't do that
you have to remeber to add the 0.5 to your answer because you found n - 0.5 then you get exactly the same answer he got
Is it just me or is this paper extremely difficult
You did watch the intro right?!
for stats question 7b, i didnt use the standard normal, i used inverse normal with the approximation and distribution the same as you did, and then i got n-0.5= 44.527, hence n=45.027 and hence n = 45, is that ok or do i have to use the standard normal?
if your calculator can do it you won't get docked points for it, just make it clear what you're doing on the paper
@@tomlynn27 the final value i got though was like a few decimal places differnt to his but rounded it was the same?
@@emilycook1544 the mark scheme will likely say 'awrt 45.03' or similar so your answer would still be right
bought youtube premium to watch this
i dont understand how we can have an intersection between two values that do not touch/ overlap for q3
For Q8 part b, Cant we use the Area Under the Graph equation to find "t".
I did this but I get t = 10s - which is different to your answer in which you use SUVAT.
I did the same hmm
@@user-ub2ii4fb2q nah - I made a silly mistake lol - the method works.
@@Xarishher ohh then I must have also haha thank you
What should the answer to 13d be? Should it be along the lines of how all the potential energy is being transferred to kinetic energy, and none is lost as friction to the pulley. Thanks in advance :)
hii, just asked my teacher this and he said that because a smooth pulley means no resistance to motion (friction) , then the markschemes will look for “we are assuming that the tension of A and B are the same”
i hope this helps and best of luck with your exam next week!!
Yo how do i know when to do the boundary + or - 0.5 for a frequency table? I was confused because the logs have length which i thought would be continuous
I think you only adjust the boundaries when there is a gap like if it was 15
thank you🙏🏻
Hey could you please add another date to the live sessions? Or maybe increase the capacity?
you know for questions 5a the second part, I wrote P(1
For Binomial CD, the function only works when P(X≤x), so you would need to find the range of values that fit the function’s criteria, hence P(1
31:20. Hi I’m confused how come you add the probability of 2 and 4 to get 1/3 rather than timesing their probabilities) sorry probably very silly questions but I’ve left this revision a bit last minute haha)
Because 1/3 is the probability of selecting an even number which is the same as selecting 2 OR 4 so you add. Timesing probabilities is if you had 2 AND 4
hi, does anyone know why in Q12, part b X has been reduced as Mr Astbury said.
@@mdlxni7236 because in part b there is friction acting in the same direction as x. The object is still in equilibrium so forces are still balanced so x must be smaller(as the friction contributes to balancing weight)
@@janlaidler4860 thank you!
Top man thankyou!
🐐
5 days to revise stats and mechanics. Can't remember any of it. Its not looking good man 😂
its not looking good "brev"...
@@Xarishher nah brev ain't looking good indeed
@@user-pu9vu6ed8m Do you do Further Maths.
I haven't touched Normal Maths for like months - prioritizing F Maths.
So its not looking good for me 2.
@@Xarishher Nah man normal maths way more than hard enough for me haha
1 day to revise stats and mechanics
Hey Mr Astbury, for question 5c, would you get the marks for inputting x as 0 and probability of 0.1 then doing trial and error on the n value until you get a percentage less than 0.01? thanks
i reckon so if you show the trials as working and make it clear and all that, then its valid i think, that's what i did anyway
Yh that’s what I did
Hi sorry quick question, for 5C, why did you use 0.9 ?
the probability of failing the bounce test is 0.1 and it says none fail so we need to find the probability of not failing. so the probability of not failing is 1-0.1 which is 0.9.
@@jasrajkaur505 ty bro
🙏
Will you make another version of this predicted paper?
I’ve made another 2. I will be using them in my live sessions this weekend. You can sign to the Sunday one. There is literally only 1 space left though!
@@MrAstburyMaths Sold out 😩
@@MrAstburyMaths is it possible to buy the recorded session because they are all sold out? Thank you
You missed 13d
i think it's just: if the pulley weren't smooth, there would be friction done by the string on the pulley, which we would have to consider when making calculations. we assume it's smooth so we don't have to make it all so complicated.
something like that, but I'm not sure exactly ???
would it be no friction?
i know this isnt part of the question, but for q9, what does the displacement/time graph actually look like? can you tell from the vectors in the question? i just cant see what the motion of the particle will be like and its confusing me bc it seems to be in all different places relative to the origin
1:27:59 , how do you know that the perpendicular component of X is going ‘down’? Like how do you decide to split up the force in that direction?
Well if it was going up it wouldn’t make a right angled triangle
Sir, for Q5, is it alright if i just do trial and error analysing the different probabilities in comparison to the SL?
thats what i did as well and reckon its ok to do
For question 14 no reaction force for the person? Why not?
You're working out forces on the ladder, so the reaction of the person is negligible.
@@slyaiming when would it not be negligible? So then why is it that when you're working out stuff with an item on a slope, the reaction force isn't negligible? Thanks!
@@Sam-qs4vx Here, we are looking at force acting on the ladder, the reaction force you are talking about is acting on the person, so is not considered. On a slope, we are looking at the forces on (e.g.) a ball, so the forces it experiences will come from the slope itself, as well as its own weight.
@@Sam-qs4vx In this question it specifies that you're finding the "force exerted on the ladder" but if it doesn't state that, then you can add reaction forces.
At 51:40 shouldnt the upper limit be 862 as you are testing for less than 863. The Ncd bounds are included or are they not?
how come your not using the Casio fx-cg50 for this sir
question three asks for exact values. shouldnt you leave them as fractions?
Terminating decimals are exact so I was okay here 👍
wait i dont understand on Q9 whem you said t=5 now sub it into the i what am i subing it into?
For the first question why is my r value different ive done it like 3 times. Mine has x and y with frequency next to it
ohhh you have your frequency setting on for statistics just clear your calculator. press shift 9, 3, =
no way q6(a) on stats would ever be 7 marks right? I don't think it was particularly hard, max 4-5 marks right?
Stats and mechanics always give out lots of marks for actually not a lot of working unlike pure i think which makes you second guess urself so idk
darts average reveal pls
UR THE BEST
hi, does anyone know why in Q12, part b X has been reduced as Mr Astbury said.
Because friction force is acting now and if X is not reduced the particle would have a resultant force upwards
@@elias.000 thank youu!
is linear regression - from Q1, something that can come up in edexcel paper3? Its not difficult now i know how to do it but I have never seen it before?
ye comes up a lot as a few marks with a hypothesis test
At 43:38 where does the 0.9 come from? Why can't we use the tables in the formula book (which gets a value of n=50) is it because it skips the n values between 40 and 50 so isn't accurate?
ur cooked brev
@alaziziomar_ Yepp I know :)
Had such a good teacher for 1st year who taught us half of pure and all of mechanics but then she retired and we've had the worst teacher ever trying to teach us the rest of pure and all of stats so yeah I don't get stats
@@sambuckeridge7020 my teacher finished our content 2 weeks before the first paper 💀 (or around that)
Dunno if you’ve figured it out yet, but the 0.9 comes from the fact binomials have a fixed probability of success & two fixed outcomes (success and failure).
Since the probability of failure is 0.1, the probability of success is 1 - P(Failure), hence 0.9.
Ceo of saving my grades
For question 4 couldn't you also have 4 4 3
that adds to 11 which is odd g
1:15:50 is it not magnitude of the acceleration
Look at ‘v’. That’s in bold. ‘F’ is also in bold. So we can assume we are writing in i and j form, as v (bold) is in i and j. If it had the modulus sign/said ‘magnitude’, then we would find the magnitude
quick question, how do you know if you should leave answers in i,j form, or on top of each other in brackets sort of vector form for vector questions? or does it not matter?
Leave your answer in the form it's written in I the question
always answer in the form given in the question, which is almost always i,j form
Oh okkk makes sense! Thanks guys:)
Is there any way I can get those other two predicted papers??
www.tickettailor.com/events/mrastburymaths/1291828
@@MrAstburyMaths thanks!
for question 2eii why are we squaring 0.5?
What he got there is standard deviation. Variance is the square of standard deviation, which is what the question is asking for.
@@Sam-qs4vx thank you!
Hello,
I have a very important question and really need a respond🫣Are the A Level tricky questions from youtube channel suitable for A Level Edexcel board??Wising everyone sunny and well deserved summer!👍
Yes, 100%
for Q3, I got r = 0.092 and q = 0.138. i dont know what i did wrong
Hi! For this question I did: 0.13+0.25+p+q+r+s = 1 so p+s+q+r = 0.75 (EQ1) // (q)/(q+r) = 0.6 so q = 1.5r (EQ2) // and 0.13+p+s = 0.7 so 0.57= p+s (EQ3) -> if you sub in EQ3 & EQ2 into EQ1 this will give you r (0.072) and then you can find q because q = 1.5r -> I hope that helps :)
and why in q13 is it equal to 2ma?
We say the sum of forces = ma. Ma come from the equation F = Ma
So its 2ma because the mass is 2m
Babe wake up, new Astbury paper just dropped.
BEAT ME TO IT 😭😭😭😭😭
@@user-cd4wy7gm3o🤣 broooo
@@user-cd4wy7gm3o mb bro 😅
At 49:55 how do you know when to use that for of standard deviation/variance ? Like how come it isn’t just 28?
Oh and at 51:10 how come you square rooted the variance in the calculation?
Ps, I know this is a stupid question, but I’ve literally never been told why, lol, so it always confuses me.
Thank you 😃
whenever you do a hypothesis test with the normal distribution you always keep the mean the same and change the standard deviation (so do this only when youre about to attempt a hypothesis test question with *normal* D)
he square rooted the variance because when you use the calculator you have to put in the mean and the standard deviation (square rooting the variance gives standard deviation)
hope that helps 💝
Oh my goodness, I’m literally so stupid 😭. Yes that helps so much, thank you!!
@@Black_VoidXx noo u got this and np 💝💝
q9 is such a stupid question
Need AQA Paper 3 MATHS!!!!! Upload before tomorrow please ma man
Let’s goooooooo
mr astbury u are my waifu
goat