In the parallelogram ABCD, AD=BC AB=CD B(8,1) C(11,5) Taking coordinates of B as (x1,y1) and C as (x2,y2) Difference between the x coordinates = x2 - x1 = 11-8 =3 Difference between the y coordinates = y2 - y1 =5-1 = 4 A = (2,3) D= (2+3,3+4) D=( 5,7)
Guess we can find this with midpoint way, easier than this! As we know, diagonals of parallelogram are bisecting each other. So, Midpoint of AC = Midpoint of BD method, we can solve quickly and get the solution sir.
In the parallelogram ABCD,
AD=BC
AB=CD
B(8,1) C(11,5)
Taking coordinates of B as (x1,y1)
and C as (x2,y2)
Difference between the x coordinates = x2 - x1
= 11-8
=3
Difference between the y coordinates = y2 - y1
=5-1
= 4
A = (2,3)
D= (2+3,3+4)
D=( 5,7)
It is very short and more helpful for the exams thanks 👍
Thank you sir. I understood clearly ! Thank you 😊
Thank you sir. I loved the video 👍
Sir you can take elimination method
Guess we can find this with midpoint way, easier than this! As we know, diagonals of parallelogram are bisecting each other. So, Midpoint of AC = Midpoint of BD method, we can solve quickly and get the solution sir.
Great💥
Nice video!
"Better simplify now so initially you'll have less simplifying to do later" GIRL MATH
Can i use the same method for a square???
it will be even easy in the case of square
Why was the 1 negative ? Wasnt the 6 supposed to stay as negative ?
Kadak 😂
Why is it so complicated. Im having a mental breakdown
I need a Weapon
Great job sir but your method was way too long I got the answer in the first 2 minutes
Hi,can you tell me how did you find it ?
@@mimimano3424by mid point method, yk that diagonals of parallelogram bisect each other so the mid point of both the diagonals are same