No, derivatives are technically calculus. Although I think I remember doing problems like this in algebra. Instead of differentiating the objective function to find the critical point, we would just find the peak of the parabola. This explains why we only maximized area, but not volume. With area, the objective function is a quadratic (parabola), so we just found the vertex (x = -b/2a, f(x) = ax^2 + bx + c).
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The legend we don't deserve
Thats just advanced algebra thats not even calculus
No, derivatives are technically calculus.
Although I think I remember doing problems like this in algebra. Instead of differentiating the objective function to find the critical point, we would just find the peak of the parabola. This explains why we only maximized area, but not volume. With area, the objective function is a quadratic (parabola), so we just found the vertex (x = -b/2a, f(x) = ax^2 + bx + c).