Root locus for complex poles

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You explain everything without confusing the student. It's very rare and very valuble skill.

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Your teaching method is much better than all other channels ever exist in TH-cam who make Enginneering Videos.Please continue uploading relevant lecture.

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[@srivallipadhamavathi]

Yes sirrr

[@gbengadayo6296]

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[@Skystrike70]

thanks you actually covered an example with complex poles that nobody else seems to want to do, this is the only sort of problem that matches my homework lol

[@nehasrinivas7501]

I have seen so many vedios on this topic but I feel all difficult but finally I gone through your explanation is very very easy and you made the questions as very easy thank you sir

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Welcome 😊

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U are always a magical teacher...thanks a lot

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Seriously he is

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​

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Sir you are a Smart Engineer indeed. Thank you for saving my life, all the way from South Africa ✌

[@arslan_1.0]

Even explained those terms which were not asked in this question but we may need in some other questions👏👏, Thank you!!

[@arulnalmanan7622]

at 19:38 ans= -16

[@Fahimsy3d]

This was extremely well explained! Love from Canada.

[@edutechguruengineeringlear4280]

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[@alexandragarcia785]

Thank you so much!! I understand so much better now!

[@anmolmaurya2413]

Thankyou sir, for explaining every detail, without confusing

[@vijaysimha6642]

The best video I saw on this topic 👏

[@SMV1972]

Прекрасный урок! Спасибо огромное!

[@alliswell2246]

I'm blessed.......as i found this video.
Thanku you so muchhhhhh sir.

[@abhiramambati3346]

gone through lot of videos but this one is the right one. nice explanation

[@smartEngineerShinton]

Do share to your class group

[@abhiramambati3346]

@@smartEngineerShinton Ok bro!
small doubt if zero is there in b/w poles then how to calculate break away or in point?

[@prathyusha8090]

@@abhiramambati3346 break away point exists btw two adjacent poles ,break in point exists btw two adjacent zeros ,btw pole and zero they don't exist

[@mayankgurung3468]

Brilliant man
It helped a lot.

[@saikiranmarrapu1233]

Explanation is tooo Good👏👏👏

[@maxthegladiator7587]

Sir, your explanation was clear and satisfyng thank you

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[@smartEngineerShinton]

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[@bharathnani2803]

Super Bhayya..Well Explained

[@user-tf6pf6sy4u]

GREAT VIDEO, keep doing this

[@lf8175]

This is the best video I have ever seen on this. Also much better than anything my professor explains, she confuses me lol

[@sachincr3708]

Sir i have options with root locus part and time response steady state analysis which shall i choose

[@NaveenReddy-zk7of]

Extraordinary bhaiya

[@SunilKumar-ee5ud]

Ur are the 🔥 fire sir no words to tell about ur teaching sir

[@907shindeyash6]

Deserves more subscribers

[@maheshsonawane8737]

Thanks Biradar
✌🤟❤
U make it simpler
Now I can complete my assignment. 😜
Really thanks

[@edutechguruengineeringlear4280]

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[@prasadbadhe5596]

Osm lecture sir continue uploading...

[@ajayanand3986]

Thank you for really helpful this video

[@iremcantas6602]

sir what about lack of zeros? how does it affect my test point?

[@mohammeddawood1941]

Thank you so much sir❤

[@chinmayamj5615]

Thank you so much sir 🙏

[@TejashwiVulupala]

what if a pole present on right side of real axis can we find gain stability

[@MUKESHTHIPIRI]

ur... our garden angle 🔥

[@smartEngineerShinton]

Do share to your class group

[@naseeratayee3751]

how you got angle of departure 17 degree, it is 58 degree according to that formula you have calculated

[@Coder_Minds]

Why u have take plus or minus 180 in asymptodes , as in first problem it's not there

[@suniansunifacts8712]

sir why we take +-90 and +-270....It should we 90 and 270 ?
Sir please reply

[@loveyoubts2002]

while calculating centroid, shouldn't we only consider the real parts of poles and zeros ? in this particular problem the imaginary parts are getting cancelled out but in other cases it will be a problem...won't it ?

[@mteja9569]

Awesome video

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Thank you so much sir 💥🥰

[@poudankumar5371]

Like on of the best explainations i have watched ❤️

[@edutechguruengineeringlear4280]

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[@everyoneslifestyle6795]

nicely explained ☺️

[@pratyushpro9060]

thanks a lot brother
helped me a lot before the exam

[@edutechguruengineeringlear4280]

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[@ibrahimmuntatharadnan9634]

great explain bro

[@whatwhyhowmedia]

Control System Needs So Much Attention. Active Mind Whole Book.

[@mubzplay]

Plz do a qustion with zero exist and non comblex

[@otobong1476]

Sir, what if the k value is negative is that okay?

[@blessingshenjere484]

Ma Man thank u sm

[@04aachalbaydukar5]

Sir how imaginary part solve in caslo fx-991EX plz tell them...

[@liyakathshaik4934]

Thank you so much 😊

[@poongodisrinivas4580]

Thank you so much sir

[@jsdhemanth8263]

So angle of departure and break away point pass through same point as per cross imaginary axis sir?

[@edutechguruengineeringlear4280]

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[@mth_3277]

sir number of asymtotes is not the number of poles .It is poles-zeros(p-z)

[@faisalhazry]

VERRRRRY GOOOD

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God level explaination

[@edutechguruengineeringlear4280]

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[@llllllll859]

how to know poles are complex or not ?

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Thank u souch sir

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Thank you sir🙏

[@smartEngineerShinton]

Thank you 🤗

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Thank you 💖

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[@03adityadwivedie.e79]

best video 😇

[@NikangVideos6377]

In finding centroid only real part of the poles and zeroes is to be taken

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you are good teacher thank you......

[@smartEngineerShinton]

Welcome 🤗

[@alex13ethiotube91]

@@smartEngineerShinton never

[@dhanushdharanikumar880]

Thanks sir 🙏

[@ujjeltiwary7898]

Love you sir

[@mallamgurudeep1341]

doubt: to check root locus point are we supposed to consider only real poles or for example there is a conjugate in 2+4j 2 is on real line so 2 also shall i consider?

[@Jnglfvr]

I think that you are asking about finding the root locus on the real line. If so the complex roots don't matter because they always appear in conjugate pairs anyways. So if you add them in you will always get an even number (2) added to what ever poles and zeros are to the right of the point you are evaluating. Since adding 2 to an odd number leaves it odd and adding 2 to an even number leaves it even you can ignore the complex roots for this purpose.

[@saineethureddy6195]

You should consider only the on real axis.(i.e. only real numbers) not the complex poles that lies on the s- plane. 2+4j is a complete pole. You should not consider only 2.

[@mallamgurudeep1341]

@@saineethureddy6195 thanks but it's been 2 months since I've completed my xam

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@@mallamgurudeep1341 😂

[@jsdhemanth8263]

When zero is ended with in real axis
Then there is no need to draw root locus from o to infinity?

[@edutechguruengineeringlear4280]

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Thanks a lot

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Thank you

[@shaikrizwan8873]

Superrrrrrrrrrrrrrrrrrrrrr explanation

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Excellent lecture sir. Is this from nagoor kani text book sir

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thank you sir

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thankyou sir

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Super explanation 👌

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Thanks 🙏

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Amazing video

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Sir thee thanne 🎉

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Brother this video very good, but slove difficult problem to solve

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[@smartEngineerShinton]

Welcome 🤗 and do share to your class group

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Aiml medha job's gurinchi oka video chy Anna skills ame narchukovalo chappu anna

[@manojneeli7151]

14:00 need link

[@shreerambharadwaj2623]

thank u so much sir

[@gokulsnair9930]

Poliyane😍

[@XYZ-0101]

Why +- only in this question...in asymptote

[@govindvarmaagroya105]

Sir how can we do code of this in the matlab ???

[@smartEngineerShinton]

clear all;
clc;
s = tf('s');
disp('The given transfer function is,');
Gs = (s+9)/(s*(s^2+4*s+11))
rlocus(Gs,'k');
axis([-6 2 -6 6]);
sgrid;
I think it is like this... Just try this in Matlab

[@manishkumartg1406]

Thankyou

[@sagarsinha668]

sir why you consider 90* and 270* as same angle with same line

[@abinashpaikaray3561]

Yaa I'm also confuse

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[@elpaso4765]

Thanks for clean explanation.

[@-sai-oj7ou]

Tqqq

[@smartEngineerShinton]

Welcome 🤗 and do share to your class group

[@aiswarya518]

When is break away point?

[@venumadamanchi5023]

Only if two poles are in adjacent

[@triveninagabirava9001]

While finding q why you are doing p-z-1

[@edutechguruengineeringlear4280]

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🙏

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🙏🙏🙏

[@shreyasraju7216]

Can teach today I have an exam tomorrow

[@BTS-07]

Don't we write asymptotes as P-Z???

[@mayankgurung3468]

Thats the number of asymptots

[@SUZAKU__007]

Thank you sir but u sound like a student :)

[@jamydordo3428]

Angle of departure is 58 or 59 degree ,your calculated ans is wrong