Your teaching method is much better than all other channels ever exist in TH-cam who make Enginneering Videos.Please continue uploading relevant lecture.
thanks you actually covered an example with complex poles that nobody else seems to want to do, this is the only sort of problem that matches my homework lol
I have seen so many vedios on this topic but I feel all difficult but finally I gone through your explanation is very very easy and you made the questions as very easy thank you sir
very very useful video, helped a lot, u r so greatt, so much efforts u have taken to bring such wonderful output, may god bless you , u will reach great heights
while calculating centroid, shouldn't we only consider the real parts of poles and zeros ? in this particular problem the imaginary parts are getting cancelled out but in other cases it will be a problem...won't it ?
doubt: to check root locus point are we supposed to consider only real poles or for example there is a conjugate in 2+4j 2 is on real line so 2 also shall i consider?
I think that you are asking about finding the root locus on the real line. If so the complex roots don't matter because they always appear in conjugate pairs anyways. So if you add them in you will always get an even number (2) added to what ever poles and zeros are to the right of the point you are evaluating. Since adding 2 to an odd number leaves it odd and adding 2 to an even number leaves it even you can ignore the complex roots for this purpose.
You should consider only the on real axis.(i.e. only real numbers) not the complex poles that lies on the s- plane. 2+4j is a complete pole. You should not consider only 2.
clear all; clc; s = tf('s'); disp('The given transfer function is,'); Gs = (s+9)/(s*(s^2+4*s+11)) rlocus(Gs,'k'); axis([-6 2 -6 6]); sgrid; I think it is like this... Just try this in Matlab
You explain everything without confusing the student. It's very rare and very valuble skill.
Your teaching method is much better than all other channels ever exist in TH-cam who make Enginneering Videos.Please continue uploading relevant lecture.
th-cam.com/video/r3TlKbs7TKQ/w-d-xo.html
Yes sirrr
@@srivallipadhamavathi😂😂🎉
thanks you actually covered an example with complex poles that nobody else seems to want to do, this is the only sort of problem that matches my homework lol
I have seen so many vedios on this topic but I feel all difficult but finally I gone through your explanation is very very easy and you made the questions as very easy thank you sir
Welcome 😊
Sir you are a Smart Engineer indeed. Thank you for saving my life, all the way from South Africa ✌
U are always a magical teacher...thanks a lot
Thank you so much
Seriously he is
Ara bata thanku ki koi jarurat nahi
Even explained those terms which were not asked in this question but we may need in some other questions👏👏, Thank you!!
This was extremely well explained! Love from Canada.
th-cam.com/video/r3TlKbs7TKQ/w-d-xo.html
at 19:38 ans= -16
17 is crt
Thankyou sir, for explaining every detail, without confusing
I'm blessed.......as i found this video.
Thanku you so muchhhhhh sir.
very very useful video, helped a lot, u r so greatt, so much efforts u have taken to bring such wonderful output, may god bless you , u will reach great heights
Made my day 😇
gone through lot of videos but this one is the right one. nice explanation
Do share to your class group
@@smartEngineerShinton Ok bro!
small doubt if zero is there in b/w poles then how to calculate break away or in point?
@@abhiramambati3346 break away point exists btw two adjacent poles ,break in point exists btw two adjacent zeros ,btw pole and zero they don't exist
sir number of asymtotes is not the number of poles .It is poles-zeros(p-z)
You r write
Such a detailed explanation 👏👏👏🏻👏🏻
Прекрасный урок! Спасибо огромное!
sir why we take +-90 and +-270....It should we 90 and 270 ?
Sir please reply
Why u have take plus or minus 180 in asymptodes , as in first problem it's not there
The best video I saw on this topic 👏
Super Bhayya..Well Explained
Explanation is tooo Good👏👏👏
thanks a lot brother
helped me a lot before the exam
th-cam.com/video/r3TlKbs7TKQ/w-d-xo.html
Thanks Biradar
✌🤟❤
U make it simpler
Now I can complete my assignment. 😜
Really thanks
th-cam.com/video/r3TlKbs7TKQ/w-d-xo.html
Why +- only in this question...in asymptote
Sir, your explanation was clear and satisfyng thank you
Explained well thank you sir..
Is the angle of arrival/departure measured from the centroid?
Ur are the 🔥 fire sir no words to tell about ur teaching sir
sir if we got the zero at rightside to the pole then what is the root locus on real axis
ur... our garden angle 🔥
Do share to your class group
Osm lecture sir continue uploading...
God level explaination
th-cam.com/video/r3TlKbs7TKQ/w-d-xo.html
while calculating centroid, shouldn't we only consider the real parts of poles and zeros ? in this particular problem the imaginary parts are getting cancelled out but in other cases it will be a problem...won't it ?
how you got angle of departure 17 degree, it is 58 degree according to that formula you have calculated
Thank you so much!! I understand so much better now!
This is the best video I have ever seen on this. Also much better than anything my professor explains, she confuses me lol
Extraordinary bhaiya
Deserves more subscribers
Control System Needs So Much Attention. Active Mind Whole Book.
Sir ur channel didnt show up for some days I was worried what had happened. Thank God finally it came back.
Got hacked😭
@@smartEngineerShintonthen how did you get back bro because i too last my account how did you recover
sir why you consider 90* and 270* as same angle with same line
Yaa I'm also confuse
what if a pole present on right side of real axis can we find gain stability
How to find angle of arrival 😊
sir what about lack of zeros? how does it affect my test point?
sir if we got k value is negative then what we need to do sir?
Sir how imaginary part solve in caslo fx-991EX plz tell them...
Aiml medha job's gurinchi oka video chy Anna skills ame narchukovalo chappu anna
Sir, what if the k value is negative is that okay?
GREAT VIDEO, keep doing this
Like on of the best explainations i have watched ❤️
th-cam.com/video/r3TlKbs7TKQ/w-d-xo.html
14:00 need link
Thank you so much sir❤
The best teacher 👍❤️ i😭 iam madly searching for the best video then I found u tqq uu best video
Welcome 🤗 and do share to your class group
you are good teacher thank you......
Welcome 🤗
@@smartEngineerShinton never
Excellent lecture sir. Is this from nagoor kani text book sir
Sir angle of departure value is -16⁰
Thank you for really helpful this video
doubt: to check root locus point are we supposed to consider only real poles or for example there is a conjugate in 2+4j 2 is on real line so 2 also shall i consider?
I think that you are asking about finding the root locus on the real line. If so the complex roots don't matter because they always appear in conjugate pairs anyways. So if you add them in you will always get an even number (2) added to what ever poles and zeros are to the right of the point you are evaluating. Since adding 2 to an odd number leaves it odd and adding 2 to an even number leaves it even you can ignore the complex roots for this purpose.
You should consider only the on real axis.(i.e. only real numbers) not the complex poles that lies on the s- plane. 2+4j is a complete pole. You should not consider only 2.
@@saineethureddy6195 thanks but it's been 2 months since I've completed my xam
th-cam.com/video/r3TlKbs7TKQ/w-d-xo.html
@@mallamgurudeep1341 😂
Plz do a qustion with zero exist and non comblex
Super explanation 👌
th-cam.com/video/r3TlKbs7TKQ/w-d-xo.html
When is break away point?
Only if two poles are in adjacent
how to know poles are complex or not ?
Thank you so much sir 🙏
Awesome video
Brilliant man
It helped a lot.
Sir how can we do code of this in the matlab ???
clear all;
clc;
s = tf('s');
disp('The given transfer function is,');
Gs = (s+9)/(s*(s^2+4*s+11))
rlocus(Gs,'k');
axis([-6 2 -6 6]);
sgrid;
I think it is like this... Just try this in Matlab
Sir i have options with root locus part and time response steady state analysis which shall i choose
great explain bro
So angle of departure and break away point pass through same point as per cross imaginary axis sir?
th-cam.com/video/r3TlKbs7TKQ/w-d-xo.html
While finding q why you are doing p-z-1
th-cam.com/video/r3TlKbs7TKQ/w-d-xo.html
Thank you so much sir 💥🥰
When zero is ended with in real axis
Then there is no need to draw root locus from o to infinity?
th-cam.com/video/r3TlKbs7TKQ/w-d-xo.html
Thank you sir🙏
Thank you 🤗
Thank you 💖
th-cam.com/video/r3TlKbs7TKQ/w-d-xo.html
nicely explained ☺️
Brother this video very good, but slove difficult problem to solve
I think angle of departure is -57.79 degree
th-cam.com/video/r3TlKbs7TKQ/w-d-xo.html
Yes you are right 👍
Don't we write asymptotes as P-Z???
Thats the number of asymptots
Sir thee thanne 🎉
Athe athe... Mattanal alle mwuthe 😌
@@akaparz4109 mattannal endha machaa
Bro why you consider j value is -1
Why no break away point
Because there are no adjacent poles
th-cam.com/video/r3TlKbs7TKQ/w-d-xo.html
Ma Man thank u sm
Thanks for clean explanation.
Thank you so much 😊
In finding centroid only real part of the poles and zeroes is to be taken
Amazing video
th-cam.com/video/r3TlKbs7TKQ/w-d-xo.html
best video 😇
Sir dsp videos (teaching) continue karoo
shout out to the bug at 4:29 😅
😁
Angle of departure is 58 or 59 degree ,your calculated ans is wrong
Superrrrrrrrrrrrrrrrrrrrrr explanation
Love you sir
why +,- are used in angle of asymptotes
thankyou sir
Thank u souch sir
Thank you
270 samaj me nhi aa Raha hai ,90 me kese exist ho gya
Your lecture is exllent sir👏🙏 but the marker pen your are using is not good please do explain with good marker🙂sir
Thanks 🙏
Thanks a lot
VERRRRRY GOOOD