EMF & flux equation (& graph) of AC generator | Electromagnetic induction | Physics | Khan Academy
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- เผยแพร่เมื่อ 22 เม.ย. 2021
- Let's explore the EMF and flux equations of an AC generator and draw graphs for them.
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Created by Mahesh Shenoy
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There is a lot of talk about free energy and how to create it, but there is very little information available on how to do it at the undergraduate level. BACK EMF is one of the ways that free energy can be created, but it is not available at the undergraduate level. This is because it is not taught in school. There are a few schools that offer courses on free energy, but they are mostly at the graduate level. There are also a few online courses, but they are mostly expensive and not worth the money. The bottom line is that if you want to learn how to create free energy, you will have to do it on your own. There are a few books that you can read that will give you some information on how to do it, but they are mostly written for people who already know a lot about electricity.
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Back EMF is a powerful force that can be harnessed to generate electricity. When a conductor is moved through a magnetic field, an electromotive force (EMF) is induced in the conductor. This EMF can be used to generate electricity.
The strength of the EMF depends on the speed at which the conductor is moved and the strength of the magnetic field. The faster the conductor is moved, or the stronger the magnetic field, the greater the EMF.
The direction of the EMF also depends on the direction of motion of the conductor and the orientation of the magnetic field. If both are moving in the same direction, then the EMF will be in opposing directions and will cancel out. However, if they are moving in opposite directions, then they will reinforce each other and produce a stronger EMF.
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Lastly Great explanation about flux vs emf i.e lens law and farade law
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can we use flux linkage as NBA sin(wt) considering theta to be the angle between flux lines and Area of the loop.....
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It makes sense
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Your explanation is really handy, but the equation that you have used takes Sin instead of Cos
Thanks sir
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This is the same way voltage is induced in dc generator ? The commutator convert it to dc voltage right ?
Sir I have a doubt. Is the concept maximum emf is induced when minimum flux is linked is true for generators since their conductors get linked by the flux from a pole at a time
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Very simple explanation. I like it. Can be harnessed this back emf, and so to be used as electric power?
Yes back emf can be harnessed from motor..
Even recent electric vehicles or trains uses the back emf to charge up its batteries.
@@safeezrahman8823 But it will be the same amount of power? or less?
Might be bit less, but good part is at least some energy is harnessed instead of total wastage.
So basically, E0 is the derivative of the flux, but with a different amplitude?
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This is equivalent to 1hour learning in class
In my textbooks it shows EMF max is at 90. Your explanation makes sense but the textbooks I'm reading doesn't. Why would they write it that 90 is at max?
Is it written sin or cos there?
bro to get emf you have to differentiate ( cos omega t ) which becomes (-sin omega t) omega and at 90 sin =1 that's why emf is max at sin. take it this way emf is change in flux at 90 flux changed from max (cos0) to min (cos90) and hence the max emf at 90
edit:- sorry! dude i tried my best but i don't think i've explained it well, but sir in the video did it very clearly, i understood it here only.
several teachers get this wrong... they state maximum emf is when the coil is vertical which is clearly not the case
@@riteshyadav1716 well explained
cuz it is of sin not of cos
cracked on the sticks ngl
Chup!
Omg!!! I can't able to clear my doublt. At first case conductor placed in perpendicular position so max number of flux lines touches to the conductor.so max magnetic field and flux linking are there. But emf value=0. How ?? Max magnetic field and flux touches to the conductor it should create max emf at begin right ???? But we consider angle of conductor sin0. So emf become zero. I can't understand . Please anyone let me explain and clear my doubt
In EMF equation theta is the angle btw velocity(v) and magnetic field (B) so by that angle at begining is zero as coil is about to rotate rightwards ,in direction of magnetic field , so zero EMF . And at begining flux is max but emf is not as emf as per faraday refers to change of flux not the value of flux
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Sir Please Solve My Doubt
In figure you have taken a rectangular coil , and when this coil rotate then rate of change of flux would be constant so induced EMF should also be in constant (in rectangular shape).
The induced emf will be variable (As you have shown in figure) only if when coil would be circular , because then rate of change of flux would not be constant.
Sir Please Explain...I'm Very Confused !
Flux happens to be BAcos(theta). Notice this result is independent of the shape of the coil. So regardless of the shape, the flux would be sinusoidal, and the rate of change of flux would be sinusoidal (a variable) too.
@@KhanAcademyIndiaEnglish ok sir thanks
@@KhanAcademyIndiaEnglish Question: Why does an EMF graph for a DC generator look different? I understand current only flows in one direction but how does that relate to the graph? Shouldn't there still be Cos(180) giving -1?
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Which white board are you using sir?
Not white board. He is using applications
@@njordapollon9631 please explain it a little I am also making educational videos I want to make like this. which applications can I use?
No ok!
What is N, B & A?
Thanks sir
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