Clock Wise Rotation About Any Arbitrary Point Concept with Coordinate Points GCSE
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- เผยแพร่เมื่อ 18 ต.ค. 2024
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This is the most straight forward method and is easiest to understand. Thank You, Anil Kumar!
Thanks for appreciation.
true, really true !!!!
I'm a teacher and my kids will be happy in sure of it . thanks for the tips buddy
Most useful and clear explanation of this concept. Thank you!
Tks. This is the best way to understand any student abt rotation exept origin rotation
I appreciate. Finally, this thing has sank into my mind.
Thank you so much! This really helped me understand this concept in a simple way which seemed complicated at first, but now totally makes sense.
Thanks. Here are related examples: th-cam.com/video/GITnruIimnw/w-d-xo.html
Awesome I was teaching my daughter this and you have it so easy!!
Thanks
This video is so helpful, thank you so much anil sir
Thanks a lot for appreciation
Greetings from Sri Lanka! Wonderful explanation. Good luck!
THANK YOU SO MUCH YOU SAVED MY GCSEEEEEEEEEEEEEEEEEEEEE
perfect sir... you deserve 100000000000000000000000000000000000000000000000 likes
Thank you, great to show my year 7 kids.
Thank you sooooo much this was soooo simple and i understood
Thank you sir that's helps alot .
Any angle can use this method? For example 30 degree of rotation also same rule will work?
Thanks very much, for your classes, nice explanations
sir should we apply the same concept for qns like rotating about 270degrees
Thank you so much
Very useful video sir. Thank you so much
Thanks. Here are few related videos: th-cam.com/video/GITnruIimnw/w-d-xo.html
Very useful
Can u do the same thing except counterclockwise
appreciate
thanku
Sir 🙏✨✨
How do u suddenly go to the right at b'?
Bestttt
Thanks for Appreciation!
All the Best to You!
Thank you bro
Thanks. Here is related video: th-cam.com/video/GITnruIimnw/w-d-xo.html
Thank you sir
Thanks for appreciation
Rotation of a point or a graph -90/+90 degree or 180 degree at any center point without needing to draw any graph.
Formula 1: Rotation of a graph 90 degree anti-clockwise (or counter-clockwise) about origin (0,0)
(X, Y) ==> (-Y, X)
Formua 2: Rotation of a graph 90 degree clockwise (or 270 degree clockwise) about origin (0,0)
(X, Y) ==> (Y, -X)
Formula 3: Rotation of a graph 180 degree anti-clockwise (or counter-clockwise) about origin (0,0)
(X, Y) ==> (-X, -Y)
To do mathematical calculation you need to do 3 following steps.
(Note: (Xp , Yp) is the name of center-point of rotaion of the graph, (not X*p, Y*p))
Step 1: Move/Shift the graph to origin (0,0)
(X - Xp, Y - Yp) Formula 4
(Xp and Yp are just names (not X*p, Y*p))
Step 2: Use according Formula 1, 2 or 3 for rotational graph -90 degree, 90 degree or 180 dregree to rotationally solve the this step
Step 3: Move/Shift the graph back to the rotaional center-point with formula below
(X + Xp, Y + Yp) Formula 5
(Xp and Yp are just names (not X*p, Y*p))
=============
I am using example in this video clip to mathematically solve the method above
Example: Rotate the triangle graph of points A(1, 1), B(2, 3) and C(3 ,0) 90 degree clockwise about the center-point P(Xp, Yp) = (-1, 2)
Solve:
Step 1: Move/Shift the graph to origin (0,0)
(X - Xp, Y - Yp)
A(1, 1) ==> Ao(1 + 1, 1 + 2) (Ao is just a name (not A*o))
= Ao(2, -1)
B(2, 3) ==> Bo(2 + 1, 3 - 2) (Bo is just a name (not B*o))
= Bo(3, 1)
C(3 ,0) ==> Co(3 + 1, 0 - 2) (Co is just a name (not C*o))
= Co(4, -2)
Step 2: Use according Formulae 1, 2 or 3 for rotational graph -90 degree, 90 degree or 180 dregree to rotationally solve the this step.
In this step, the question says rotate 90 degree clockwise. Hence, we use "Formula 2"
That is (X, Y) ==> (Y, -X)
Ao(2, -1) ==> A'(-1, -2)
Bo(3, 1) ==> B'(1, -3)
Co(4, -2) ==> C'(-2 , -4)
Step 3: Move/Shift the graph back to the rotaional center-point with formula below
(X + Xp, Y + Yp)
A'(-1, -2) ==> A''(-1 - 1, -2 + 2)
= A''(-2, 0)
B'(1, -3) ==> B''(1 - 1, -3 + 2)
= B''(0, -1)
C'(-2 , -4) ==> C''(-2 - 1, -5 + 2)
= C''(-3, -2)
Anil Kumar blundered. His answers A'B'C' he plotted on the graph are completely different from what he wrote as ordered pairs. All wrong.
Nope! As he stated we are going to be using the point (-1, 2) as the new origin. so hes graphing it as if (-1, 2) was the original graph. Where his points match. 😊
thankyou so much